結果

問題 No.650 行列木クエリ
ユーザー ふっぴーふっぴー
提出日時 2018-02-20 01:38:30
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
RE  
実行時間 -
コード長 6,720 bytes
コンパイル時間 3,187 ms
コンパイル使用メモリ 220,100 KB
実行使用メモリ 33,172 KB
最終ジャッジ日時 2023-09-23 03:53:27
合計ジャッジ時間 5,777 ms
ジャッジサーバーID
(参考情報)
judge13 / judge11
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,376 KB
testcase_01 RE -
testcase_02 RE -
testcase_03 AC 2 ms
4,380 KB
testcase_04 RE -
testcase_05 RE -
testcase_06 AC 2 ms
4,380 KB
testcase_07 AC 2 ms
4,380 KB
testcase_08 RE -
testcase_09 RE -
testcase_10 AC 2 ms
4,380 KB
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ソースコード

diff #

#include "bits/stdc++.h"
using namespace std;

#define DEBUG(x) cout<<#x<<": "<<x<<endl;
#define DEBUG_VEC(v) cout<<#v<<":";for(int i=0;i<v.size();i++) cout<<" "<<v[i]; cout<<endl

typedef long long ll;
#define vi vector<int>
#define vl vector<ll>
#define vii vector< vector<int> >
#define vll vector< vector<ll> >
#define vs vector<string>
#define pii pair<int,int>
#define pis pair<int,string>
#define psi pair<string,int>
#define pll pair<ll,ll>
#define fi first
#define se second
#define rep(i,n) for(int i=0;i<(int)(n);i++)
#define rep1(i,n) for(int i=1;i<=(int)(n);i++)
#define all(c) c.begin(),c.end()
const int inf = 1000000001;
const ll INF = 2e18 * 2;
#define MOD 1000000007
#define mod 1000000009
#define pi 3.14159265358979323846
#define Sp(p) cout<<setprecision(15)<< fixed<<p<<endl;
int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 };
int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 };



struct Modint {
	ll n;
	static const ll Mod = 1000000007;
	Modint(int n = 0) : n(n) {}
};

Modint operator+(Modint a, Modint b) { return Modint((a.n += b.n) >= mod ? a.n - a.Mod : a.n); }
Modint operator-(Modint a, Modint b) { return Modint((a.n -= b.n) < 0 ? a.n + a.Mod : a.n); }
Modint operator*(Modint a, Modint b) { return Modint(1LL * a.n * b.n % a.Mod); }
Modint &operator+=(Modint &a, Modint b) { return a = a + b; }
Modint &operator-=(Modint &a, Modint b) { return a = a - b; }
Modint &operator*=(Modint &a, Modint b) { return a = a * b; }

typedef vector<Modint> vec;
typedef vector<vec> mat;

mat mul(mat A, mat B) {
	mat C(A.size(), vec(B[0].size()));
	for (int i = 0; i < A.size(); i++) {
		for (int k = 0; k < B.size(); k++) {
			for (int j = 0; j < B[0].size(); j++) {
				C[i][j] = C[i][j] + A[i][k] * B[k][j];
			}
		}
	}
	return C;
}

mat pow(mat A, ll n) {
	mat B(A.size(), vec(A.size()));
	for (int i = 0; i < A.size(); i++) {
		B[i][i] = 1;
	}
	while (n > 0) {
		if (n & 1)B = mul(B, A);
		A = mul(A, A);
		n >>= 1;
	}
	return B;
}

struct HLDecomposition {
	int n, pos;
	vector<vector<int> > G;
	vector<int> vid, head, sub, hvy, par, dep, inv, type;

	HLDecomposition() {}
	HLDecomposition(int sz) :
		n(sz), pos(0), G(n),
		vid(n, -1), head(n), sub(n, 1), hvy(n, -1),
		par(n), dep(n), inv(n), type(n) {}

	void add_edge(int u, int v) {
		G[u].push_back(v);
		G[v].push_back(u);
	}

	void build(vector<int> rs = { 0 }) {
		int c = 0;
		for (int r : rs) {
			dfs(r);
			bfs(r, c++);
		}
	}

	void dfs(int rt) {
		using T = pair<int, int>;
		stack<T> st;
		par[rt] = -1;
		dep[rt] = 0;
		st.emplace(rt, 0);
		while (!st.empty()) {
			int v = st.top().first;
			int &i = st.top().second;
			if (i<(int)G[v].size()) {
				int u = G[v][i++];
				if (u == par[v]) continue;
				par[u] = v;
				dep[u] = dep[v] + 1;
				st.emplace(u, 0);
			}
			else {
				st.pop();
				int res = 0;
				for (int u : G[v]) {
					if (u == par[v]) continue;
					sub[v] += sub[u];
					if (res<sub[u]) res = sub[u], hvy[v] = u;
				}
			}
		}
	}

	void bfs(int r, int c) {
		int &k = pos;
		queue<int> q({ r });
		while (!q.empty()) {
			int h = q.front(); q.pop();
			for (int i = h; i != -1; i = hvy[i]) {
				type[i] = c;
				vid[i] = k++;
				inv[vid[i]] = i;
				head[i] = h;
				for (int j : G[i])
					if (j != par[i] && j != hvy[i]) q.push(j);
			}
		}
	}

	// for_each(vertex)
	// [l,r] <- attention!!
	void for_each(int u, int v, const function<void(int, int)>& f) {
		while (1) {
			if (vid[u]>vid[v]) swap(u, v);
			f(max(vid[head[v]], vid[u]), vid[v]);
			if (head[u] != head[v]) v = par[head[v]];
			else break;
		}
	}

	// for_each(edge)
	// [l,r] <- attention!!
	void for_each_edge(int u, int v, const function<void(int, int)>& f) {
		while (1) {
			if (vid[u]>vid[v]) swap(u, v);
			if (head[u] != head[v]) {
				f(vid[head[v]], vid[v]);
				v = par[head[v]];
			}
			else {
				if (u != v) f(vid[u] + 1, vid[v]);
				break;
			}
		}
	}

	int lca(int u, int v) {
		while (1) {
			if (vid[u]>vid[v]) swap(u, v);
			if (head[u] == head[v]) return u;
			v = par[head[v]];
		}
	}

	int distance(int u, int v) {
		return dep[u] + dep[v] - 2 * dep[lca(u, v)];
	}
};


class SegmentTree {
public:
	const ll MAX_N = 1 << 10;
	const mat E{ {1,0},{0,1} };
	int n;
	vector<mat> dat;

	SegmentTree(int _n) :n(_n) { dat.resize(2 * MAX_N - 1, E); }


	//k番目の値をaに変更
	void update(int k, mat a, int v, int l, int r) {
		if (r - l == 1) {
			dat[v] = a;
		}
		else {
			if (k < (l + r) / 2)
				update(k, a, 2 * v + 1, l, (l + r) / 2);
			else {
				update(k, a, 2 * v + 2, (l + r) / 2, r);
			}
			dat[v] = mul(dat[v * 2 + 1], dat[v * 2 + 2]);
		}
	}

	//[a,b)の最小値を求める
	//後ろのほうの引数は計算の簡単のための引数
	//kは接点の番号,l,rはその接点が[l,r)に対応していることを表す
	//従って、外からはquery(a,b,0,0,n)としてよぶ
	mat query(int a, int b, int k, int l, int r) {
		if (r <= a || b <= l) {
			return E;
		}
		if (a <= l && r <= b) {
			return dat[k];
		}
		else {
			mat ul = query(a, b, k * 2 + 1, l, (l + r) / 2);
			mat ur = query(a, b, k * 2 + 2, (l + r) / 2, r);
			return mul(ul, ur);
		}
	}

};


vector<set<int> > child;
vii G;
void make_child(int parent, int now) {
	rep(i, G[now].size()) {
		if (G[now][i] == parent) {
			continue;
		}
		child[now].insert(G[now][i]);
		make_child(now, G[now][i]);
	}
	return;
}


int main() {
	int n;
	cin >> n;
	child.resize(n); G.resize(n);
	HLDecomposition hld(n);
	vi a(n - 1), b(n - 1);
	rep(i, n - 1) {
		cin >> a[i] >> b[i];
		hld.add_edge(a[i], b[i]);
		G[a[i]].push_back(b[i]);
		G[b[i]].push_back(a[i]);
	}
	make_child(-1, 0);
	hld.build();
	//DEBUG_VEC(hld.vid);
	SegmentTree st(n);
	int q;
	cin >> q;
	while (q--) {
		char c;
		cin >> c;
		if (c == 'x') {
			int i;
			cin >> i;
			int u = a[i], v = b[i];
			mat x(2, vec(2));
			rep(j, 2) {
				rep(k, 2) {
					cin >> x[j][k].n;
				}
			}
			if (hld.vid[u] > hld.vid[v]) {
				swap(u, v);
			}
			//DEBUG(u); DEBUG(v);
			st.update(hld.vid[v], x, 0, 0, st.n);
		}
		else {
			int u, v;
			cin >> u >> v;
			mat ans = { {1, 0}, {0, 1} };
			while (1) {
				if (hld.vid[u]>hld.vid[v]) swap(u, v);
				if (hld.head[u] != hld.head[v]) {
					ans = mul(st.query(hld.vid[hld.head[v]], hld.vid[v] + 1, 0, 0, st.n), ans);
					v = hld.par[hld.head[v]];
				}
				else {
					if (u != v)ans = mul(st.query(hld.vid[u] + 1, hld.vid[v] + 1, 0, 0, st.n), ans);
					break;
				}
			}
			
			rep(i, 2) {
				rep(j, 2) {
					cout << ans[i][j].n << " ";
				}
			}
			cout << endl;
		}
		/*
		rep(i, n) {
			auto temp = st.query(hld.vid[i], hld.vid[i] + 1, 0, 0, st.n);
			cout << "(";
			rep(j, 2) {
				rep(k, 2) {
					cout << temp[j][k].n << " ";
				}
			}
			cout << ")  ";
			
		}
		cout << endl;
		//*/
	}
}
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