結果
問題 | No.896 友達以上恋人未満 |
ユーザー |
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提出日時 | 2018-02-24 12:07:12 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
MLE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 1,577 bytes |
コンパイル時間 | 601 ms |
コンパイル使用メモリ | 67,704 KB |
最終ジャッジ日時 | 2025-01-05 08:49:36 |
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | MLE * 4 |
other | MLE * 7 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:32:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 32 | for(int i = 0; i < m; i++) scanf("%d", x+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:33:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 33 | for(int i = 0; i < m; i++) scanf("%d", y+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:56:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 56 | for(int i = 0; i < m; i++) scanf("%d", a+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:57:44: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=] 57 | for(int i = 0; i < m; i++) scanf("%d", b+i); | ~^ ~~~ | | | | int* ll* {aka long long int*} | %lld main.cpp:31:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with at
ソースコード
// naive2 #include <cstdio> #include <cassert> #include <iostream> #include <cstring> using namespace std; typedef long long ll; #define N (1<<25) #define M 100010 int m, n, mx, ax, my, ay, mod, mod2, mod3 = 1<<30; ll x[M], y[M], z[N], a[M], b[M], dp[N]; bool prime[N]; /* ll solve(ll a, ll b){ b *= a; return (a<mod?z[a]:0)-(b<mod?z[b]:0); } */ ll solve2(ll a){ if(a>mod) return 0; if(dp[a]>=0) return dp[a]; ll res = 0; for(ll i = a; i < mod; i+=a){ res += z[i]; } return dp[a] = res; } int main(){ scanf("%d%d%d%d%d%d%d%d",&m,&n,&mx,&ax,&my,&ay,&mod,&mod2); for(int i = 0; i < m; i++) scanf("%d", x+i); for(int i = 0; i < m; i++) scanf("%d", y+i); for(int i = 0; i < m; i++) z[x[i]] += y[i]; ll xx = x[m-1], yy = y[m-1]; for(int i = m; i < n; i++){ xx = (xx*mx+(ll)ax)&(mod-1); yy = (yy*my+(ll)ay)&(mod-1); z[xx] += yy; } for(int i = 2; i*i<mod; i++){ if(prime[i]) continue; for(int j = i*i; j<mod; j+=i){ prime[j] = true; } } /* for(int i = 2; i < mod; i++){ if(prime[i]) continue; for(int j = (mod-1)/i*i; j > 0; j-=i){ z[j/i] += z[j]; } } */ for(int i = 0; i < m; i++) scanf("%d", a+i); for(int i = 0; i < m; i++) scanf("%d", b+i); memset(dp, -1, sizeof(dp)); ll res = 0; for(int i = 0; i < m; i++){ ll r = solve2(a[i])-solve2(a[i]*b[i]); printf("%lld\n", r); (res+=r)&=mod3-1; } ll aa = a[m-1], bb = b[m-1]; for(int i = m; i < n; i++){ aa = ((aa*mx+(ll)ax+mod2-1)&(mod2-1))+1; bb = ((bb*my+(ll)ay+mod2-1)&(mod2-1))+1; (res+=solve2(aa)-solve2(aa*bb))&=mod3-1; } printf("%lld\n", res); return 0; }