結果

問題 No.653 E869120 and Lucky Numbers
ユーザー fiord
提出日時 2018-03-04 19:04:39
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,202 bytes
コンパイル時間 1,089 ms
コンパイル使用メモリ 119,172 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-09-13 18:18:48
合計ジャッジ時間 2,065 ms
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#define _USE_MATH_DEFINES
#include <iostream>
#include <fstream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <cstring>
#include <cassert>
#include <string>
#include <vector>
#include <utility>
#include <complex>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <deque>
#include <tuple>
#include <bitset>
#include <limits>
#include <algorithm>
#include <random>
#include <complex>
#include <regex>
using namespace std;
typedef long double ld;
typedef long long ll;
typedef vector<int> vint;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef complex<ld> compd;
#define reach(i,a) for(auto i:a)
#define rep(i,n) for(int i=0;i<(int)n;i++)
#define REP(i,n) for(int i=0;i<=(int)n;i++)
#define srep(i,a,n) for(int i=a;i<(int)n;i++)
#define SREP(i,a,n) for(int i=a;i<=(int)n;i++)
#define rrep(i,n) for(int i=n-1;i>=0;i--)
#define RREP(i,n) for(int i=n;i>=0;i--)
#define all(a) (a).begin(),(a).end()
#define mp(a,b) make_pair(a,b)
#define mt make_tuple
#define pb push_back
#define fst first
#define scn second
int bitcnt(ll x) {
x = ((x & 0xAAAAAAAAAAAAAAAA) >> 1) + (x & 0x5555555555555555);
x = ((x & 0xCCCCCCCCCCCCCCCC) >> 2) + (x & 0x3333333333333333);
x = ((x & 0xF0F0F0F0F0F0F0F0) >> 4) + (x & 0x0F0F0F0F0F0F0F0F);
x = ((x & 0xFF00FF00FF00FF00) >> 8) + (x & 0x00FF00FF00FF00FF);
x = ((x & 0xFFFF0000FFFF0000) >> 16) + (x & 0x0000FFFF0000FFFF);
x = ((x & 0xFFFFFFFF00000000) >> 32) + (x & 0x00000000FFFFFFFF);
return x;
}
int bitcnt(int x) {
x = ((x & 0xAAAAAAAA) >> 1) + (x & 0x55555555);
x = ((x & 0xCCCCCCCC) >> 2) + (x & 0x33333333);
x = ((x & 0xF0F0F0F0) >> 4) + (x & 0x0F0F0F0F);
x = ((x & 0xFF00FF00) >> 8) + (x & 0x00FF00FF);
x = ((x & 0xFFFF0000) >> 16) + (x & 0x0000FFFF);
return x;
}
ll gcd(ll a, ll b) {
return a%b == 0 ? b : gcd(b, a%b);
}
#define debug(x) cout<<"case #" << x << ": " << endl
#define DEBUG 0
const ll inf = 1e9;
const ll mod = 1e9 + 7;
const ld eps = 1e-15;
const int dx[] = { 1,0,-1,0,0 };
const int dy[] = { 0,1,0,-1,0 };
int main() {
string p; cin >> p;
// 12,3,40
int under = p[p.size() - 1] - '0';
if (under != 2 && under != 3 && under != 4) {
cout << "No" << endl;
return 0;
}
bool usezero[] = { false,false };
int up = 0;
rrep(i, p.size()) {
int num = p[i] - '0' - up;
if (usezero[0] & usezero[1]) {
// 0OK
if (num != 0) {
cout << "No" << endl;
return 0;
}
up = 0;
}
else if (usezero[0]) {
// 0,6,7OKup0
up = 0;
if (num == 6 || num == 7) continue;
else if (num == 0) {
usezero[1] = true;
}
else {
cout << "No" << endl;
return 0;
}
}
else {
// 0,2,4,6,7OK
// 0
if (num == 0) {
up = 0;
usezero[0] = usezero[1] = true;
}
// 2(6+6),3(6+7),4(7+7)->up=1
else if (num == 2 || num == 3 || num == 4) {
up = 1;
}
// 6,7(up=0,usezero[0]=true)
else if (num == 6 || num == 7) {
up = 0;
usezero[0] = true;
}
else {
cout << "No" << endl;
return 0;
}
}
}
cout << (up == 0 ? "Yes" : "No") << endl;
return 0;
}
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