結果
| 問題 | No.211 素数サイコロと合成数サイコロ (1) |
| ユーザー |
 smiken_61
|
| 提出日時 | 2018-03-07 17:21:09 |
| 言語 | C++11 (gcc 11.4.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 9,314 bytes |
| コンパイル時間 | 1,349 ms |
| コンパイル使用メモリ | 162,120 KB |
| 実行使用メモリ | 6,824 KB |
| 最終ジャッジ日時 | 2024-10-02 12:29:32 |
| 合計ジャッジ時間 | 2,347 ms |
|
ジャッジサーバーID （参考情報） |
judge1 / judge2 |
（要ログイン）
テストケース
テストケース表示| 入力 | 結果 | 実行時間 実行使用メモリ |
|---|---|---|
| testcase_00 | AC | 2 ms
6,820 KB |
| testcase_01 | AC | 2 ms
6,816 KB |
| testcase_02 | WA | - |
| testcase_03 | WA | - |
| testcase_04 | WA | - |
| testcase_05 | WA | - |
| testcase_06 | AC | 1 ms
6,820 KB |
| testcase_07 | AC | 1 ms
6,816 KB |
| testcase_08 | WA | - |
| testcase_09 | AC | 2 ms
6,816 KB |
| testcase_10 | AC | 1 ms
6,820 KB |
| testcase_11 | WA | - |
| testcase_12 | AC | 1 ms
6,820 KB |
| testcase_13 | AC | 1 ms
6,816 KB |
| testcase_14 | AC | 2 ms
6,820 KB |
| testcase_15 | AC | 2 ms
6,816 KB |
| testcase_16 | AC | 2 ms
6,816 KB |
| testcase_17 | WA | - |
| testcase_18 | WA | - |
| testcase_19 | AC | 1 ms
6,816 KB |
| testcase_20 | AC | 1 ms
6,816 KB |
| testcase_21 | AC | 2 ms
6,820 KB |
| testcase_22 | AC | 1 ms
6,816 KB |
| testcase_23 | AC | 2 ms
6,820 KB |
| testcase_24 | AC | 2 ms
6,816 KB |
| testcase_25 | AC | 1 ms
6,816 KB |
| testcase_26 | AC | 2 ms
6,820 KB |
| testcase_27 | AC | 1 ms
6,820 KB |
| testcase_28 | AC | 1 ms
6,820 KB |
| testcase_29 | AC | 1 ms
6,816 KB |
| testcase_30 | AC | 2 ms
6,816 KB |
| testcase_31 | AC | 2 ms
6,820 KB |
| testcase_32 | AC | 2 ms
6,820 KB |
ソースコード
#include <bits/stdc++.h>
#include<iostream>
#include<cstdio>
#include<vector>
#include<queue>
#include<map>
#include<cstring>
#include<string>
#include <math.h>
#include<algorithm>
// #include <boost/multiprecision/cpp_int.hpp>
#include<functional>
#define int long long
#define inf 1000000007
#define pa pair<int,int>
#define ll long long
#define pal pair<double,pa>
#define ppa pair<string,int>
#define ppap pair<int,pa>
#define ssa pair<string,int>
#define mp make_pair
#define pb push_back
#define EPS (1e-12)
#define equals(a,b) (fabs((a)-(b))<EPS)
#define VI vector<int>
using namespace std;
class pas{
public:
int x,y;
pas(int x=0,int y=0):x(x),y(y) {}
pas operator + (pas p) {return pas(x+p.x,y+p.y);}
pas operator - (pas p) {return pas(x-p.x,y-p.y);}
pas operator * (int a) {return pas(x*a,y*a);}
pas operator / (int a) {return pas(x/a,y/a);}
// double absv() {return sqrt(norm());}
int norm() {return x*x+y*y;}
bool operator < (const pas &p) const{
return x != p.x ? x<p.x: y<p.y;
}
// bool operator < (const pas &p) const{
// return y != p.y ? y<p.y: x<p.x;
// }
bool operator == (const pas &p) const{
return x==p.x && y==p.y;
}
};
class Point{
public:
double x,y;
Point(double x=0,double y=0):x(x),y(y) {}
Point operator + (Point p) {return Point(x+p.x,y+p.y);}
Point operator - (Point p) {return Point(x-p.x,y-p.y);}
Point operator * (double a) {return Point(x*a,y*a);}
Point operator / (double a) {return Point(x/a,y/a);}
double absv() {return sqrt(norm());}
double norm() {return x*x+y*y;}
bool operator < (const Point &p) const{
return x != p.x ? x<p.x: y<p.y;
}
bool operator == (const Point &p) const{
return fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;
}
};
typedef Point Vector;
#define pl pair<int,pas>
struct Segment{
Point p1,p2;
};
struct star{
Segment se[5];
};
double dot(Vector a,Vector b){
return a.x*b.x+a.y*b.y;
}
double cross(Vector a,Vector b){
return a.x*b.y-a.y*b.x;
}
bool parareru(Point a,Point b,Point c,Point d){
// if(abs(cross(a-b,d-c))<EPS)cout<<"dd "<<cross(a-b,d-c)<<endl;
return abs(cross(a-b,d-c))<EPS;
}
double distance_ls_p(Point a, Point b, Point c) {
if ( dot(b-a, c-a) < EPS ) return (c-a).absv();
if ( dot(a-b, c-b) < EPS ) return (c-b).absv();
return abs(cross(b-a, c-a)) / (b-a).absv();
}
bool is_intersected_ls(Segment a,Segment b) {
if(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;
if(parareru((a.p2),(a.p1),(b.p1),(b.p2))&¶reru((a.p2),(a.p1),(b.p1),(b.p1))){
// cout<<"sss"<<endl;
if(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;
if(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;
if(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;
if(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;
return false;
}
else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );
}
double segment_len(Segment a){
return (a.p1-a.p2).absv();
}
double segment_dis(Segment a,Segment b){
if(is_intersected_ls(a,b))return 0;
double r=distance_ls_p(a.p1, a.p2, b.p1);
r=min(r,distance_ls_p(a.p1, a.p2, b.p2));
r=min(r,distance_ls_p(b.p1, b.p2, a.p2));
r=min(r,distance_ls_p(b.p1, b.p2, a.p1));
return r;
}
Point intersection_ls(Segment a, Segment b) {
Point ba = b.p2-b.p1;
double d1 = abs(cross(ba, a.p1-b.p1));
double d2 = abs(cross(ba, a.p2-b.p1));
double t = d1 / (d1 + d2);
return a.p1 + (a.p2-a.p1) * t;
}
pair<Point,Point> circle_intersection(Point c1,double r1,Point c2,double r2){
double d=(c1-c2).absv();
double h=(r1*r1-r2*r2+d*d)/2.0/d;
double l=sqrt(r1*r1-h*h);
// cout<<d<<" "<<h<<" "<<l<<endl;
Point asi=c1+(c2-c1)*h/((c2-c1).absv());
Vector r1r2=(c2-c1)/((c2-c1).absv());
Vector sui={r1r2.y,-r1r2.x};
// cout<<sui.x<<" "<<sui.y<<endl;
pair<Point,Point> z=mp(asi+sui*l,asi-sui*l);
if(z.first.x>z.second.x) swap(z.first,z.second);
return z;
}
int gcd(int x,int y){
if(x<y) return gcd(y,x);
if(x==y) return x;
if(x%y==0) return y;
return gcd(y,x%y);
}
int lcm(int x,int y){
int g=gcd(x,y);
x=x/g;
return x*y;
}
class pa2{
public:
int x,y;
pa2(int x=0,int y=0):x(x),y(y) {}
pa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}
pa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}
bool operator < (const pa2 &p) const{
return x != p.x ? x<p.x: y<p.y;
}
bool operator > (const pa2 &p) const{
return x != p.x ? x>p.x: y>p.y;
}
bool operator == (const pa2 &p) const{
return abs(x-p.x)==0 && abs(y-p.y)==0;
}
bool operator != (const pa2 &p) const{
return !(abs(x-p.x)==0 && abs(y-p.y)==0);
}
};
int beki(int ba,int rr,int mo){
if(rr==0) return 1%mo;
if(rr==1) return ba%mo;
if(rr%2) return (beki(ba,rr-1,mo)*ba)%mo;
int g=beki(ba,rr/2,mo);
return (g*g)%mo;
}
int a[6]={2,3,5,7,11,13};
int b[6]={4,6,8,9,10,12};
signed main(){
double ans=0;
int k;
cin>>k;
for(int i=0;i<6;i++)for(int j=0;j<6;j++)if(a[i]*b[j]==k)ans+=(1.0/36.0);
printf("%.10lf\n",ans);
return 0;
}