結果
問題 | No.664 超能力者Aと株価予測 |
ユーザー |
|
提出日時 | 2018-03-09 23:52:23 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 19 ms / 4,000 ms |
コード長 | 4,640 bytes |
コンパイル時間 | 3,241 ms |
コンパイル使用メモリ | 215,820 KB |
最終ジャッジ日時 | 2025-01-05 09:12:11 |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
other | AC * 15 |
ソースコード
#pragma GCC optimize ("O3")#pragma GCC target ("avx")#include "bits/stdc++.h" // define macro "/D__MAI"using namespace std;typedef long long int ll;#define debug(v) {printf("L%d %s > ",__LINE__,#v);cout<<(v)<<endl;}#define debugv(v) {printf("L%d %s > ",__LINE__,#v);for(auto e:(v)){cout<<e<<" ";}cout<<endl;}#define debuga(m,w) {printf("L%d %s > ",__LINE__,#m);for(int x=0;x<(w);x++){cout<<(m)[x]<<" ";}cout<<endl;}#define debugaa(m,h,w) {printf("L%d %s >\n",__LINE__,#m);for(int y=0;y<(h);y++){for(int x=0;x<(w);x++){cout<<(m)[y][x]<<" ";}cout<<endl;}}#define ALL(v) (v).begin(),(v).end()#define repeat(cnt,l) for(auto cnt=0ll;(cnt)<(l);++(cnt))#define rrepeat(cnt,l) for(auto cnt=(l)-1;0<=(cnt);--(cnt))#define iterate(cnt,b,e) for(auto cnt=(b);(cnt)!=(e);++(cnt))#define diterate(cnt,b,e) for(auto cnt=(b);(cnt)!=(e);--(cnt))#define MD 1000000007ll#define PI 3.1415926535897932384626433832795template<typename T1, typename T2> ostream& operator <<(ostream &o, const pair<T1, T2> p) { o << "(" << p.first << ":" << p.second << ")"; return o;}template<typename T> T& maxset(T& to, const T& val) { return to = max(to, val); }template<typename T> T& minset(T& to, const T& val) { return to = min(to, val); }void bye(string s, int code = 0) { cout << s << endl; exit(code); }mt19937_64 randdev(8901016);inline ll rand_range(ll l, ll h) {return uniform_int_distribution<ll>(l, h)(randdev);}#if defined(_WIN32) || defined(_WIN64)#define getchar_unlocked _getchar_nolock#define putchar_unlocked _putchar_nolock#elif defined(__GNUC__)#else#define getchar_unlocked getchar#define putchar_unlocked putchar#endifnamespace {#define isvisiblechar(c) (0x21<=(c)&&(c)<=0x7E)class MaiScanner {public:template<typename T> void input_integer(T& var) {var = 0; T sign = 1;int cc = getchar_unlocked();for (; cc<'0' || '9'<cc; cc = getchar_unlocked())if (cc == '-') sign = -1;for (; '0' <= cc && cc <= '9'; cc = getchar_unlocked())var = (var << 3) + (var << 1) + cc - '0';var = var * sign;}inline int c() { return getchar_unlocked(); }inline MaiScanner& operator>>(int& var) { input_integer<int>(var); return *this; }inline MaiScanner& operator>>(long long& var) { input_integer<long long>(var); return *this; }inline MaiScanner& operator>>(string& var) {int cc = getchar_unlocked();for (; !isvisiblechar(cc); cc = getchar_unlocked());for (; isvisiblechar(cc); cc = getchar_unlocked())var.push_back(cc);return *this;}template<typename IT> void in(IT begin, IT end) { for (auto it = begin; it != end; ++it) *this >> *it; }};class MaiPrinter {public:template<typename T>void output_integer(T var) {if (var == 0) { putchar_unlocked('0'); return; }if (var < 0)putchar_unlocked('-'),var = -var;char stack[32]; int stack_p = 0;while (var)stack[stack_p++] = '0' + (var % 10),var /= 10;while (stack_p)putchar_unlocked(stack[--stack_p]);}inline MaiPrinter& operator<<(char c) { putchar_unlocked(c); return *this; }inline MaiPrinter& operator<<(int var) { output_integer<int>(var); return *this; }inline MaiPrinter& operator<<(long long var) { output_integer<long long>(var); return *this; }inline MaiPrinter& operator<<(char* str_p) { while (*str_p) putchar_unlocked(*(str_p++)); return *this; }inline MaiPrinter& operator<<(const string& str) {const char* p = str.c_str();const char* l = p + str.size();while (p < l) putchar_unlocked(*p++);return *this;}template<typename IT> void join(IT begin, IT end, char sep = '\n') { for (auto it = begin; it != end; ++it) *this << *it << sep; }};}MaiScanner scanner;MaiPrinter printer;ll m, n, kei;ll dp[400][22];ll aa[400];int main() {scanner >> n >> m >> kei;++n;scanner.in(aa, aa + n);ll best = kei;dp[0][0] = kei;iterate(i, 1, n) {repeat(j, i) {rrepeat(k, m) {maxset(dp[i][k], dp[j][k]);maxset(best,maxset(dp[i][k + 1], dp[j][k] / aa[j] * aa[i] + (dp[j][k] % aa[j])));}}}//debugaa(dp, 10,10);cout << best << endl;return 0;}