結果
| 問題 | No.663 セルオートマトンの逆操作 | 
| コンテスト | |
| ユーザー |  | 
| 提出日時 | 2018-03-10 16:33:30 | 
| 言語 | Haskell (9.10.1) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 19 ms / 2,000 ms | 
| コード長 | 1,055 bytes | 
| コンパイル時間 | 2,811 ms | 
| コンパイル使用メモリ | 174,656 KB | 
| 実行使用メモリ | 10,880 KB | 
| 最終ジャッジ日時 | 2024-10-14 13:44:49 | 
| 合計ジャッジ時間 | 4,058 ms | 
| ジャッジサーバーID (参考情報) | judge2 / judge3 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 29 | 
コンパイルメッセージ
Loaded package environment from /home/judge/.ghc/x86_64-linux-9.8.2/environments/default
[1 of 2] Compiling Main             ( Main.hs, Main.o )
Main.hs:28:26: warning: [GHC-63394] [-Wx-partial]
    In the use of ‘head’
    (imported from Data.List, but defined in GHC.List):
    "This is a partial function, it throws an error on empty lists. Use pattern matching or Data.List.uncons instead. Consider refactoring to use Data.List.NonEmpty."
   |
28 |     f x = let key = fst (head x); val = modsum . map snd $ x
   |                          ^^^^
[2 of 2] Linking a.out
            
            ソースコード
import Data.List
import Control.Monad
main = do 
  n <- readLn :: IO Int
  a <- replicateM n readLn :: IO [Int]
  print $ solve a
md :: Int
md = 10^9 + 7
type Stat = (Int, Int, Int, Int)
solve :: [Int] -> Int
solve a = let b = foldl' g [((i, j, i, j), 1) | i <- [0,1], j <- [0,1]] a
          in modsum . map snd . filter (\((h1, h2, x, y), _) -> h1 == x && h2 == y) $ b
  where
    g :: [(Stat, Int)] -> Int -> [(Stat, Int)]
    g acc a = compress (acc >>= f a)
    f :: Int -> (Stat, Int) -> [(Stat, Int)]
    f a ((h1, h2, x, y), cnt) = [((h1, h2, y, z), cnt) | z <- [0, 1], rule x y z == a]
compress :: [(Stat, Int)] -> [(Stat, Int)]
compress a = map f . groupBy (\x y -> fst x == fst y) $ a
  where
    f :: [(Stat, Int)] -> (Stat, Int)
    f x = let key = fst (head x); val = modsum . map snd $ x
          in (key, val)
modsum :: [Int] -> Int
modsum = foldl' (\x y -> (x + y) `mod` md) 0
rule :: Int -> Int -> Int -> Int
rule 0 0 0 = 0
rule 0 0 1 = 1
rule 0 1 0 = 1
rule 0 1 1 = 1
rule 1 0 0 = 0
rule 1 0 1 = 1
rule 1 1 0 = 1
rule 1 1 1 = 0
            
            
            
        