結果

問題 No.592 括弧の対応 (2)
ユーザー Tsukasa_Type
提出日時 2018-03-11 23:28:44
言語 Java
(openjdk 23)
結果
AC  
実行時間 780 ms / 5,000 ms
コード長 2,288 bytes
コンパイル時間 3,555 ms
コンパイル使用メモリ 78,664 KB
実行使用メモリ 51,152 KB
最終ジャッジ日時 2024-10-15 01:04:32
合計ジャッジ時間 5,050 ms
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 3
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.io.*;
import java.util.*;
import static java.lang.System.*;
public class Main {
static FastScanner sc = new FastScanner(System.in);
public static void main(String[] args) {
int n = sc.nextInt();
ArrayDeque<Integer> stack = new ArrayDeque<>();
int[] ar = new int[n];
String s = sc.next();
for (int i=0; i<s.length(); i++) {
if (s.charAt(i)=='(') {stack.addFirst(i);}
else {
ar[stack.getFirst()] = i;
ar[i] = stack.removeFirst();
}
}
for (int i=0; i<n; i++) {
out.println(ar[i]+1);
}
}
}
class FastScanner implements Closeable {
private final InputStream in;
private final byte[] buffer = new byte[1024];
private int ptr = 0;
private int buflen = 0;
public FastScanner(InputStream in) {this.in = in;}
private boolean hasNextByte() {
if (ptr < buflen) {return true;}
else{
ptr = 0;
try {buflen = in.read(buffer);}
catch (IOException e) {e.printStackTrace();}
if (buflen <= 0) {return false;}
}
return true;
}
private int readByte() { if (hasNextByte()) return buffer[ptr++]; else return -1;}
private static boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}
public boolean hasNext() { while(hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++; return hasNextByte();}
public String next() {
if (!hasNext()) throw new NoSuchElementException();
StringBuilder sb = new StringBuilder();
int b = readByte();
while(isPrintableChar(b)) {
sb.appendCodePoint(b);
b = readByte();
}
return sb.toString();
}
public long nextLong() {
if (!hasNext()) throw new NoSuchElementException();
long n = 0;
boolean minus = false;
int b = readByte();
if (b == '-') {
minus = true;
b = readByte();
}
if (b < '0' || '9' < b) {throw new NumberFormatException();}
while(true){
if ('0' <= b && b <= '9') {
n *= 10;
n += b - '0';
}else if(b == -1 || !isPrintableChar(b)){return minus ? -n : n;}
else{throw new NumberFormatException();}
b = readByte();
}
}
public int nextInt() {
long nl = nextLong();
if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
return (int) nl;
}
public double nextDouble() { return Double.parseDouble(next());}
public void close() {
try {in.close();}
catch (IOException e) {}
}
}
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