結果
問題 | No.421 しろくろチョコレート |
ユーザー |
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提出日時 | 2018-03-23 16:24:08 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 17 ms / 2,000 ms |
コード長 | 2,732 bytes |
コンパイル時間 | 1,029 ms |
コンパイル使用メモリ | 107,432 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-09-23 07:16:19 |
合計ジャッジ時間 | 2,815 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 65 |
ソースコード
# include <iostream># include <algorithm># include <vector># include <string># include <set># include <map># include <cmath># include <iomanip># include <functional># include <utility># include <stack># include <queue># include <list># include <tuple># include <unordered_map># include <numeric># include <complex># include <bitset># include <random># include <chrono>using namespace std;using LL = long long;using ULL = unsigned long long;typedef pair<LL, LL> P;constexpr int INF = 2000000000;constexpr int HINF = INF / 2;constexpr double DINF = 100000000000000000.0;constexpr long long LINF = 9223372036854775807;constexpr long long HLINF = 4500000000000000000;const double PI = acos(-1);int dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };# define ALL(x) (x).begin(),(x).end()# define UNIQ(c) (c).erase(unique(ALL((c))),(c).end())# define mp make_pair# define eb emplace_back# define FOR(i,a,b) for(int i=(a);i<(b);i++)# define RFOR(i,a,b) for(int i=(a);i>=(b);i--)# define REP(i,n) FOR(i,0,n)# define INIT std::ios::sync_with_stdio(false);std::cin.tie(0)struct edge { int to, cap, rev; };const int MAX_SIZE = 12345;vector<edge>G[MAX_SIZE];void add_edge(int from, int to, int cap) {G[from].push_back(edge{ to, cap, (int)G[to].size() });G[to].push_back(edge{ from, 0, (int)G[from].size() - 1 });}bool used[MAX_SIZE];int dfs(int p, int t, int f) {if (p == t)return f;used[p] = true;for (int i = 0; i < G[p].size(); i++) {edge &e = G[p][i];if (used[e.to] || e.cap == 0)continue;int _f = dfs(e.to, t, min(f, e.cap));if (_f) {e.cap -= _f;G[e.to][e.rev].cap += _f;return _f;}}return 0;}int max_flow(int s, int t) {int flow = 0;while (true) {fill_n(used, MAX_SIZE, false);int f = dfs(s, t, INF);if (f)flow += f;else return flow;}}int n, m;string st[51];int main() {cin >> n >> m;int s = 2 * n*m + 1, t = s + 1;int wcnt = 0, bcnt = 0;REP(i, n)cin >> st[i];REP(i, n)REP(j, m) {if (st[i][j] == 'w')wcnt++;if (st[i][j] == 'b')bcnt++;add_edge(s, i*m + j, 1);add_edge(n*m + i*m + j, t, 1);if (j) {if (st[i][j] == 'w'&&st[i][j - 1] == 'b') {add_edge(i*m + j, n*m + i*m + j - 1, 1);}if (st[i][j] == 'b'&&st[i][j - 1] == 'w') {add_edge(i*m + j - 1, n*m + i*m + j, 1);}}if (i) {if (st[i][j] == 'w'&&st[i - 1][j] == 'b') {add_edge(i*m + j, n*m + (i - 1)*m + j, 1);}if (st[i][j] == 'b'&&st[i - 1][j] == 'w') {add_edge((i - 1)*m + j, n*m + i*m + j, 1);}}}int num = max_flow(s, t);cout << num * 100 + min(wcnt - num, bcnt - num) * 10 + max(wcnt - num, bcnt - num) - min(wcnt - num, bcnt - num) << endl;}