結果

問題 No.667 Mice's Luck(ネズミ達の運)
ユーザー akusyounin2412akusyounin2412
提出日時 2018-03-23 22:33:44
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 113 ms / 2,000 ms
コード長 1,780 bytes
コンパイル時間 1,018 ms
コンパイル使用メモリ 118,096 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-06-24 21:49:33
合計ジャッジ時間 3,201 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 10
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
constexpr long long MOD = 1000000000 + 7;
constexpr long long INF = std::numeric_limits<long long>::max();
const double PI = acos(-1);
#define fir first
#define sec second
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, s, t, q, ans, last, cnt, a[10000], d[100000];
struct Edge { LL to, cost; };
string str;
char c[1000][1000];
bool flag = 0, f[100000];
void YN(bool f) {
if (f)
cout << "YES" << endl;
else
cout << "NO" << endl;
}
void yn(bool f) {
if (f)
cout << "Yes" << endl;
else
cout << "No" << endl;
}
vector<Edge>vec[10000];
int main(){
cin >> str;
double sum = 0;
rep(i, str.size()) {
if (str[i] == 'o')
sum += 1;
}
printf("%.15f\n", (double)(sum*100/str.size()));
rep(i, str.size()-1) {
if (str[i] == 'o')
sum -= 1;
printf("%.15f\n", (double)(sum*100 / (str.size() - i - 1)));
}
return 0;
}
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