結果
| 問題 |
No.5 数字のブロック
|
| ユーザー |
akusyounin2412
|
| 提出日時 | 2018-03-24 18:40:15 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 548 ms / 5,000 ms |
| コード長 | 1,744 bytes |
| コンパイル時間 | 1,353 ms |
| コンパイル使用メモリ | 119,072 KB |
| 実行使用メモリ | 396,944 KB |
| 最終ジャッジ日時 | 2024-11-18 12:15:06 |
| 合計ジャッジ時間 | 5,559 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 34 |
ソースコード
# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
constexpr long long MOD = 1000000000 + 7;
constexpr long long INF = std::numeric_limits<long long>::max();
const double PI = acos(-1);
#define fir first
#define sec second
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, s, t, q, sum, last, ans, cnt, a[100000];
int dp[10010][10010];
struct Edge { LL to, cost,mon; };
string str;
bool f = 0;
void YN(bool f) {
if (f)
cout << "YES" << endl;
else
cout << "NO" << endl;
}
void yn(bool f) {
if (f)
cout << "Yes" << endl;
else
cout << "No" << endl;
}
vector<Edge>vec[100000];
int main() {
cin >> m >> n;
rep(i, n) {
cin >> a[i];
}
rep(i, n) {
rep(j, m+1) {
if (j - a[i] >= 0)
dp[i + 1][j] = max(dp[i + 1][j], dp[i][j - a[i]] + 1);
dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]);
}
}
cout << dp[n][m] << endl;
return 0;
}
akusyounin2412