結果
問題 | No.573 a^2[i] = a[i] |
ユーザー |
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提出日時 | 2018-03-31 19:18:34 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 66 ms / 2,000 ms |
コード長 | 2,246 bytes |
コンパイル時間 | 845 ms |
コンパイル使用メモリ | 103,860 KB |
実行使用メモリ | 12,876 KB |
最終ジャッジ日時 | 2024-06-26 03:38:49 |
合計ジャッジ時間 | 3,668 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 47 |
ソースコード
# include <iostream># include <algorithm># include <vector># include <string># include <set># include <map># include <cmath># include <iomanip># include <functional># include <utility># include <stack># include <queue># include <list># include <tuple># include <unordered_map># include <numeric># include <complex># include <bitset># include <random># include <chrono>using namespace std;using LL = long long;using ULL = unsigned long long;constexpr int INF = 2147483647;constexpr int HINF = INF / 2;constexpr double DINF = 100000000000000000.0;constexpr double HDINF = 50000000000000000.0;constexpr long long LINF = 9223372036854775807;constexpr long long HLINF = 4500000000000000000;const double PI = acos(-1);int dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };template <typename T_char>T_char TL(T_char cX) { return tolower(cX); };template <typename T_char>T_char TU(T_char cX) { return toupper(cX); };# define ALL(x) (x).begin(),(x).end()# define UNIQ(c) (c).erase(unique(ALL((c))),(c).end())# define LOWER(s) transform(ALL((s)),(s).begin(),TL<char>)# define UPPER(s) transform(ALL((s)),(s).begin(),TU<char>)# define mp make_pair# define eb emplace_back# define FOR(i,a,b) for(LL i=(a);i<(b);i++)# define RFOR(i,a,b) for(LL i=(a);i>=(b);i--)# define REP(i,n) FOR(i,0,n)# define INIT std::ios::sync_with_stdio(false);std::cin.tie(0)LL MOD = 1000000007;LL combi(LL N_, LL C_) {const int NUM_ = 400001;static LL fact[NUM_ + 1], factr[NUM_ + 1], inv[NUM_ + 1];if (fact[0] == 0) {inv[1] = fact[0] = factr[0] = 1;for (int i = 2; i <= NUM_; ++i) inv[i] = inv[MOD % i] * (MOD - MOD / i) % MOD;for (int i = 1; i <= NUM_; ++i) fact[i] = fact[i - 1] * i%MOD, factr[i] = factr[i - 1] * inv[i] % MOD;}if (C_<0 || C_>N_) return 0;return factr[C_] * fact[N_] % MOD*factr[N_ - C_] % MOD;}LL hcomb(int P_, int Q_) { return (P_ == 0 && Q_ == 0) ? 1 : combi(P_ + Q_ - 1, Q_); }LL modpow(LL a, LL n = MOD - 2) {LL r = 1;while (n) r = r*((n % 2) ? a : 1) % MOD, a = a*a%MOD, n >>= 1;return r;}int main() {int n;cin >> n;LL ans = 0;for (int i = 1; i <= n; i++) {ans += combi(n, i)*modpow(i, n - i)%MOD;}cout << ans%MOD << endl;}