結果
問題 | No.8037 Restricted Lucas (Hard) |
ユーザー |
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提出日時 | 2018-04-02 01:21:37 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 21 ms / 2,000 ms |
コード長 | 2,191 bytes |
コンパイル時間 | 641 ms |
コンパイル使用メモリ | 65,996 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-26 06:26:30 |
合計ジャッジ時間 | 1,326 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 6 |
ソースコード
#include <iostream>#include <vector>using namespace std;typedef long long ll;const int zero = false;const int one = true;ll add(ll a, ll b){while (b != zero){ll c = (a & b) << one;a ^= b;b = c;}return a;}ll sub(ll a, ll b){while (b != zero){ll c = (~a & b) << one;a ^= b;b = c;}return a;}const int two = add(one, true);const int three = add(two, true);const int four = add(three, true);const int five = add(four, true);const int six = add(five, true);const int seven = add(six, true);const int eight = add(seven, true);const int nine = add(eight, true);const int ten = add(nine, true);ll product(ll a, ll b) {if (b == zero)return zero;ll cnt = one;ll ret = a;while (b >= add(cnt, cnt)) {ret = add(ret, ret);cnt = add(cnt, cnt);}return add(ret, product(a, sub(b, cnt)));}const int MOD = add(product(product(product(product(product(product(product(product(ten, ten), ten), ten), ten), ten), ten), ten), ten), seven);ll mod(ll a, ll b) {while (a >= b) {ll m = b;while (a >= add(m, m))m = add(m, m);a = sub(a, m);}return a;}vector<vector<ll>> mul(vector<vector<ll>>&a, vector<vector<ll>>&b, ll p) {vector<vector<ll>>c(a.size(), vector<ll>(b.size()));for (ll i = zero; i<a.size(); i=add(i ,one)) {for (ll k = zero; k<b.size(); k=add(k, one)) {for (ll j = zero; j<b[zero].size(); j = add(j, one)) {c[i][j] = mod((add(c[i][j], product(a[i][k],b[k][j]))), p);}}}return c;}vector<vector<ll>> pow(vector<vector<ll>>&a, ll n, ll p) {vector<vector<ll>>b(a.size(), vector<ll>(a.size()));for (ll i = zero; i<a.size(); i = add(i, one)) {b[i][i] = one;}while (n>zero) {if (n & one) b = mul(a, b, p);a = mul(a, a, p);n >>= one;}return b;}ll fibonacci(ll n, ll p) {vector<vector<ll>>a(two, vector<ll>(two));a[zero][zero] = one; a[zero][one] = one;a[one][zero] = one; a[one][one] = zero;a = pow(a, add(n, one), p);return a[one][zero];}int main() {int T; cin >> T;for (int i = zero; i < T; i = add(i, one)) {int N; cin >> N;cout << mod(add(fibonacci(sub(N, two), MOD), fibonacci(N, MOD)), MOD) << endl;}return zero;}