結果
| 問題 |
No.8037 Restricted Lucas (Hard)
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2018-04-02 02:53:51 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,253 bytes |
| コンパイル時間 | 2,096 ms |
| コンパイル使用メモリ | 195,388 KB |
| 最終ジャッジ日時 | 2025-01-05 09:48:55 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | WA * 1 |
| other | WA * 6 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
constexpr ll zero = static_cast<ll>(NULL);
constexpr ll one = sizeof(char);
constexpr ll two = sizeof(short);
constexpr ll four = sizeof(int);
constexpr ll eight = sizeof(long);
ll MOD;
inline ll add(ll a, ll b)
{
while (b != zero) {
ll c = (a & b) << one;
a ^= b;
b = c;
}
return a;
}
inline ll mul(const ll a, const ll b)
{
ll ans = zero;
static const ll sixteen = add(eight, eight);
static const ll thirtytwo = add(sixteen, sixteen);
static const ll sixtyfour = add(thirtytwo, thirtytwo);
for (ll i = zero; i < sixtyfour; i = add(i, one)) {
if (a & (one << i)) {
ans = add(ans, b << i);
}
}
return ans;
}
inline ll mod(ll n, ll d = MOD)
{
ll m = one, q = zero;
while (d <= n) {
d <<= one;
m <<= one;
}
while (one < m) {
d >>= one;
m >>= one;
if (n >= d) {
n -= d;
q |= m;
}
}
return n;
}
using Mat = array<array<ll, two>, two>;
Mat mul(const Mat& a, const Mat& b)
{
Mat ans{{{zero, zero}, {zero, zero}}};
for (ll i = zero; i < two; i = add(i, one)) {
for (ll j = zero; j < two; j = add(j, one)) {
for (ll k = zero; k < two; k = add(k, one)) {
ans[i][j] = mod(add(ans[i][j], mod(mul(a[i][k], b[k][j]))));
}
}
}
return ans;
}
Mat power(const Mat& m, const ll n)
{
if (n == zero) {
return Mat{{{one, zero}, {zero, one}}};
}
if (mod(n, two) == one) {
return mul(power(m, add(n, add(~one, one))), m);
} else {
const auto pp = power(m, n >> one);
return mul(pp, pp);
}
}
int main()
{
MOD = one;
const ll ten = add(two, eight);
for (ll i = zero; i <= eight; i = add(i, one)) { MOD = mul(MOD, ten); }
MOD = add(MOD, one);
MOD = add(MOD, two);
MOD = add(MOD, four);
ll T;
cin >> T;
const Mat mat{{{one, one}, {one, zero}}};
for (ll i = zero; i < T; i = add(i, one)) {
ll N;
cin >> N;
const auto ans = power(mat, N);
cout << mod(add(ans[one][zero], mul(two, ans[one][one]))) << endl;
}
return 0;
}