結果
問題 |
No.277 根掘り葉掘り
|
ユーザー |
![]() |
提出日時 | 2018-04-02 22:38:55 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,038 bytes |
コンパイル時間 | 1,173 ms |
コンパイル使用メモリ | 119,088 KB |
実行使用メモリ | 17,408 KB |
最終ジャッジ日時 | 2024-06-26 06:50:04 |
合計ジャッジ時間 | 4,896 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 10 WA * 8 |
ソースコード
# include <iostream> # include <algorithm> #include <array> # include <cassert> #include <cctype> #include <climits> #include <numeric> # include <vector> # include <string> # include <set> # include <map> # include <cmath> # include <iomanip> # include <functional> # include <tuple> # include <utility> # include <stack> # include <queue> # include <list> # include <bitset> # include <complex> # include <chrono> # include <random> # include <limits.h> # include <unordered_map> # include <unordered_set> # include <deque> # include <cstdio> # include <cstring> #include <stdio.h> #include <stdlib.h> #include <cstdint> using namespace std; using LL = long long; using ULL = unsigned long long; constexpr long long MOD = 1000000000 + 7; constexpr long long INF = std::numeric_limits<long long>::max(); const double PI = acos(-1); #define fir first #define sec second #define debug(x) cerr<<#x<<": "<<x<<'\n' typedef pair<LL, LL> Pll; typedef pair<LL, pair<LL, LL>> Ppll; typedef pair<LL, pair<LL, bitset<100001>>> Pbll; typedef pair<LL, pair<LL, vector<LL>>> Pvll; typedef pair<LL, LL> Vec2; struct Tll { LL first, second, third; }; typedef pair<LL, Tll> Ptll; #define rep(i,rept) for(LL i=0;i<rept;i++) #define Mfor(i,mf) for(LL i=mf-1;i>=0;i--) LL h, w, n, m, k, s, t, q, sum, last, cnt, ans,a[1000],d[100010]; string str; struct Edge { LL to, cost; }; vector<Edge>vec[100010]; bool f; char c; void YN(bool f) { if (f) cout << "YES" << endl; else cout << "NO" << endl; } void yn(bool f) { if (f) cout << "Yes" << endl; else cout << "No" << endl; } void dfs(LL u,LL par) { bool F = 0; d[u] = min(d[u], d[par] + 1); rep(i, vec[u].size()) { if (vec[u][i].to != par) { F = 1; dfs(vec[u][i].to, u); d[u] = min(d[u], d[vec[u][i].to] + 1); } } if (!F)d[u] = 0; } int main() { cin >> n; rep(i, n)d[i] = INF / 4; rep(i, n - 1) { LL x, y; cin >> x >> y; x--, y--; vec[x].push_back(Edge{ y,1 }); vec[y].push_back(Edge{ x,1 }); } d[0] = 0; dfs(0, 0); rep(i, n) cout << d[i] << endl; return 0; }