結果
| 問題 | No.67 よくある棒を切る問題 (1) | 
| コンテスト | |
| ユーザー |  akusyounin2412 | 
| 提出日時 | 2018-04-03 00:34:29 | 
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 224 ms / 5,000 ms | 
| コード長 | 1,829 bytes | 
| コンパイル時間 | 1,026 ms | 
| コンパイル使用メモリ | 112,008 KB | 
| 実行使用メモリ | 8,608 KB | 
| 最終ジャッジ日時 | 2025-03-03 11:10:45 | 
| 合計ジャッジ時間 | 7,117 ms | 
| ジャッジサーバーID (参考情報) | judge2 / judge4 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 30 | 
ソースコード
# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
#include <stdio.h>
#include <stdlib.h>
#include <cstdint>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
constexpr long long MOD = 1000000000 + 7;
constexpr long long INF = std::numeric_limits<long long>::max();
const double PI = acos(-1);
#define fir first
#define sec second
#define debug(x) cerr<<#x<<": "<<x<<'\n'
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, s, t, q, sum, last, cnt, ans,a[200010];
string str;
struct Edge { LL to, cost; };
vector<Edge>vec;
bool f;
char c;
void YN(bool f) {
	if (f)
		cout << "YES" << endl;
	else
		cout << "NO" << endl;
}
void yn(bool f) {
	if (f)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
}
int main() {
	cin >> n;
	rep(i, n)cin >> a[i];
	cin >> k;
	double l = 0, r = 1000000100;
	int i = 100;
	while (i > 0) {
		double mid = (l + r) / 2;
		LL ss = 0;
		rep(i, n)ss += a[i] / mid;
		if (ss < k)r = mid;
		else l = mid;
		i--;
	}
	printf("%.15f\n",  (l+r)/2);
	return 0;
}
            
            
            
        