結果
問題 | No.67 よくある棒を切る問題 (1) |
ユーザー |
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提出日時 | 2018-04-03 00:34:29 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 224 ms / 5,000 ms |
コード長 | 1,829 bytes |
コンパイル時間 | 1,026 ms |
コンパイル使用メモリ | 112,008 KB |
実行使用メモリ | 8,608 KB |
最終ジャッジ日時 | 2025-03-03 11:10:45 |
合計ジャッジ時間 | 7,117 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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ファイルパターン | 結果 |
---|---|
other | AC * 30 |
ソースコード
# include <iostream> # include <algorithm> #include <array> # include <cassert> #include <cctype> #include <climits> #include <numeric> # include <vector> # include <string> # include <set> # include <map> # include <cmath> # include <iomanip> # include <functional> # include <tuple> # include <utility> # include <stack> # include <queue> # include <list> # include <bitset> # include <complex> # include <chrono> # include <random> # include <limits.h> # include <unordered_map> # include <unordered_set> # include <deque> # include <cstdio> # include <cstring> #include <stdio.h> #include <stdlib.h> #include <cstdint> using namespace std; using LL = long long; using ULL = unsigned long long; constexpr long long MOD = 1000000000 + 7; constexpr long long INF = std::numeric_limits<long long>::max(); const double PI = acos(-1); #define fir first #define sec second #define debug(x) cerr<<#x<<": "<<x<<'\n' typedef pair<LL, LL> Pll; typedef pair<LL, pair<LL, LL>> Ppll; typedef pair<LL, pair<LL, bitset<100001>>> Pbll; typedef pair<LL, pair<LL, vector<LL>>> Pvll; typedef pair<LL, LL> Vec2; struct Tll { LL first, second, third; }; typedef pair<LL, Tll> Ptll; #define rep(i,rept) for(LL i=0;i<rept;i++) #define Mfor(i,mf) for(LL i=mf-1;i>=0;i--) LL h, w, n, m, k, s, t, q, sum, last, cnt, ans,a[200010]; string str; struct Edge { LL to, cost; }; vector<Edge>vec; bool f; char c; void YN(bool f) { if (f) cout << "YES" << endl; else cout << "NO" << endl; } void yn(bool f) { if (f) cout << "Yes" << endl; else cout << "No" << endl; } int main() { cin >> n; rep(i, n)cin >> a[i]; cin >> k; double l = 0, r = 1000000100; int i = 100; while (i > 0) { double mid = (l + r) / 2; LL ss = 0; rep(i, n)ss += a[i] / mid; if (ss < k)r = mid; else l = mid; i--; } printf("%.15f\n", (l+r)/2); return 0; }