結果

問題 No.660 家を通り過ぎないランダムウォーク問題
ユーザー tancahn2380tancahn2380
提出日時 2018-04-07 15:26:09
言語 C++11
(gcc 11.4.0)
結果
WA  
実行時間 -
コード長 2,285 bytes
コンパイル時間 1,016 ms
コンパイル使用メモリ 103,100 KB
実行使用メモリ 27,280 KB
最終ジャッジ日時 2024-06-26 11:03:43
合計ジャッジ時間 5,015 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 WA -
testcase_02 WA -
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
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testcase_11 WA -
testcase_12 WA -
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testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
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testcase_22 WA -
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testcase_27 WA -
testcase_28 WA -
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testcase_30 WA -
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testcase_32 WA -
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testcase_37 WA -
testcase_38 WA -
testcase_39 WA -
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testcase_44 WA -
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ソースコード

diff #

# include <iostream>
# include <algorithm>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <tuple>
# include <unordered_map>
# include <numeric>
# include <complex>
# include <bitset>
# include <random>
# include <chrono>
# include <cstdlib>
# include <tuple>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
constexpr int INF = 2147483647;
constexpr int HINF = INF / 2;
constexpr double DINF = 100000000000000000.0;
constexpr double HDINF = 50000000000000000.0;
constexpr long long LINF = 9223372036854775807;
constexpr long long HLINF = 4500000000000000000;
const double PI = acos(-1);
int dx[4] = { 0,1,0,-1 }, dy[4] = { 1,0,-1,0 };
template <typename T_char>T_char TL(T_char cX) { return tolower(cX); };
template <typename T_char>T_char TU(T_char cX) { return toupper(cX); };
# define ALL(x)      (x).begin(),(x).end()
# define UNIQ(c)     (c).erase(unique(ALL((c))),(c).end())
# define LOWER(s)    transform(ALL((s)),(s).begin(),TL<char>)
# define UPPER(s)    transform(ALL((s)),(s).begin(),TU<char>)
# define FOR(i,a,b)  for(LL i=(a);i<(b);i++)
# define RFOR(i,a,b) for(LL i=(a);i>=(b);i--)
# define REP(i,n)    FOR(i,0,n)
# define INIT        std::ios::sync_with_stdio(false);std::cin.tie(0)




LL MOD = 1000000007;
LL combi(LL N_, LL C_) {
	const int NUM_ = 1010101;
	static LL fact[NUM_ + 1], factr[NUM_ + 1], inv[NUM_ + 1];
	if (fact[0] == 0) {
		inv[1] = fact[0] = factr[0] = 1;
		for (int i = 2; i <= NUM_; ++i) inv[i] = inv[MOD % i] * (MOD - MOD / i) % MOD;
		for (int i = 1; i <= NUM_; ++i) fact[i] = fact[i - 1] * i%MOD, factr[i] = factr[i - 1] * inv[i] % MOD;
	}
	if (C_<0 || C_>N_) return 0;
	return factr[C_] * fact[N_] % MOD*factr[N_ - C_] % MOD;
}
LL hcomb(int P_, int Q_) { return (P_ == 0 && Q_ == 0) ? 1 : combi(P_ + Q_ - 1, Q_); }

LL modpow(LL a, LL n = MOD - 2) {
	LL r = 1;
	while (n) r = r*((n % 2) ? a : 1) % MOD, a = a*a%MOD, n >>= 1;
	return r;
}


int n;

int main() {
	cin >> n;
	LL ans = 0;
	for (int i = n; i <= 2 * n; i++) {
		int y = (i - n) / 2;
		int x = n - y - 1;
		LL d = combi(x + y, x);
		d -= (x + y, y - 1);
		ans += d;
	}
	cout << ans << endl;
}
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