結果

問題 No.344 ある無理数の累乗
ユーザー ミドリムシ
提出日時 2018-04-29 12:46:19
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 2,549 bytes
コンパイル時間 1,066 ms
コンパイル使用メモリ 88,184 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-06-27 23:30:47
合計ジャッジ時間 2,025 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <vector>
#include <map>
using namespace std;
#define YES(condition) if(condition) cout << "YES" << endl; else cout << "NO" << endl
#define Yes(condition) if(condition) cout << "Yes" << endl; else cout << "No" << endl
#define POSS(condition) if(condition) cout << "POSSIBLE" << endl; else cout << "IMPOSSIBLE" << endl
#define Poss(condition) if(condition)cout << "Possible" << endl; else cout << "Impossible" << endl
#define First(condition) if(condition)cout << "First" << endl; else cout << "Second" << endl
#define negative(condition, num) if(condition)cout << -1 << endl; else cout << num << endl
long power(long base, long exponent, long module){ if(exponent % 2){ return power(base, exponent - 1, module) * base % module; }else if(exponent){
    long root_ans = power(base, exponent / 2, module); return root_ans * root_ans % module; }else{ return 1; }}
struct position{ int y, x; }; position move_pattern[4] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}};
template<class itr> void array_output(itr start, itr goal){ string ans; for(auto i = start; i != goal; i++){ ans += to_string(*i) + " "; } ans
    .pop_back(); cout << ans << endl; }
long gcd(long a, long b){ if(a && b){ return gcd(min(a, b), max(a, b) % min(a, b)); }else{ return a; }}
#define mod long(1e9 + 7)
#define bitcount(n) __builtin_popcount(n)
struct matrix{
vector<vector<int>> space;
matrix(vector<vector<int>> element){
space = element;
}
matrix(int size){
space.resize(size, vector<int>(size));
}
matrix operator *(matrix another){
matrix ans(int(space.size()));
for(int i = 0; i < space.size(); i++){
for(int j = 0; j < space.size(); j++){
ans.space[i][j] = 0;
for(int k = 0; k < space.size(); k++){
ans.space[i][j] += space[i][k] * another.space[k][j];
}
ans.space[i][j] %= 1000;
}
}
return ans;
}
inline vector<int> operator [](int index){
return space[index];
}
};
matrix A({{2, 2}, {1, 0}}), E({{1, 0}, {0, 1}});
matrix matrix_power(int exponent){
if(exponent % 2){
return A * matrix_power(exponent - 1);
}else if(exponent){
matrix root_ans = matrix_power(exponent / 2);
return root_ans * root_ans;
}else{
return E;
}
}
int main(){
int n;
cin >> n;
cout << ((matrix_power(n) * matrix({{2, 2}, {2, 999}}))[1][0] + 1000 - (n + 1) % 2) % 1000 << endl;
}
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