結果
問題 | No.685 Logical Operations |
ユーザー | はまやんはまやん |
提出日時 | 2018-05-12 00:05:16 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 4,884 bytes |
コンパイル時間 | 1,724 ms |
コンパイル使用メモリ | 170,072 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-06-28 09:08:33 |
合計ジャッジ時間 | 2,519 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 2 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 2 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 2 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 1 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 2 ms
5,376 KB |
testcase_16 | AC | 2 ms
5,376 KB |
testcase_17 | AC | 2 ms
5,376 KB |
testcase_18 | AC | 2 ms
5,376 KB |
testcase_19 | AC | 2 ms
5,376 KB |
testcase_20 | AC | 2 ms
5,376 KB |
testcase_21 | AC | 2 ms
5,376 KB |
testcase_22 | AC | 2 ms
5,376 KB |
testcase_23 | AC | 2 ms
5,376 KB |
testcase_24 | AC | 2 ms
5,376 KB |
testcase_25 | AC | 2 ms
5,376 KB |
testcase_26 | AC | 2 ms
5,376 KB |
ソースコード
#include<bits/stdc++.h> #define rep(i,a,b) for(int i=a;i<b;i++) #define rrep(i,a,b) for(int i=a;i>=b;i--) #define fore(i,a) for(auto &i:a) #define all(x) (x).begin(),(x).end() #pragma GCC optimize ("-O3") using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); } typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60; template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; } //--------------------------------------------------------------------------------------------------- template<int MOD> struct ModInt { static const int Mod = MOD; unsigned x; ModInt() : x(0) { } ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; } int get() const { return (int)x; } ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; } ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; } ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); } return ModInt(u); } bool operator==(ModInt that) const { return x == that.x; } bool operator!=(ModInt that) const { return x != that.x; } ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; } }; template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; }; template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) { ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; } typedef ModInt<1000000007> mint; /*--------------------------------------------------------------------------------------------------- ∧_∧ ∧_∧ (´<_` ) Welcome to My Coding Space! ( ´_ゝ`) / ⌒i / \ | | / / ̄ ̄ ̄ ̄/ | __(__ニつ/ _/ .| .|____ \/____/ (u ⊃ ---------------------------------------------------------------------------------------------------*/ ll N; //--------------------------------------------------------------------------------------------------- // state1 // 0:x=y=N // 1:x<y=N // 2:x=y<N // 3:x<y<N // state2 // 0:and=xor // 1:and<xor // state3 // 0:xor=or // 1:xor<or mint memo[70][4][2][2]; int vis[70][4][2][2]; mint f(int dig, int state1, int state2, int state3) { if (dig < 0) { if (state2 == 1 and state3 == 1) return 1; else return 0; } if (vis[dig][state1][state2][state3]) return memo[dig][state1][state2][state3]; ll b = 1LL << dig; int d = ((N & b) != 0); mint res = 0; if (state1 == 0) { if (d == 0) res = f(dig - 1, 0, state2, state3); // 0 0 else { if(state2 == 1) res += f(dig - 1, 0, 1, 1); // 1 1 res += f(dig - 1, 1, 1, state3); // 0 1 res += f(dig - 1, 2, state2, state3); // 0 0 } } else if (state1 == 1) { // 1:x<y=N if (d == 0) { res += f(dig - 1, 1, 1, state3); // 1 0 res += f(dig - 1, 1, state2, state3); // 0 0 } else { if (state2 == 1) res += f(dig - 1, 1, 1, 1); // 1 1 res += f(dig - 1, 1, 1, state3); // 0 1 res += f(dig - 1, 3, 1, state3); // 1 0 res += f(dig - 1, 3, state2, state3); // 0 0 } } else if (state1 == 2){ // 2:x=y<N if (state2 == 1) res += f(dig - 1, 2, 1, 1); // 1 1 res += f(dig - 1, 3, 1, state3); // 0 1 res += f(dig - 1, 2, state2, state3); // 0 0 } else { if (state2 == 1) res += f(dig - 1, 3, 1, 1); // 1 1 res += f(dig - 1, 3, 1, state3); // 0 1 res += f(dig - 1, 3, 1, state3); // 1 0 res += f(dig - 1, 3, state2, state3); // 0 0 } vis[dig][state1][state2][state3] = 1; return memo[dig][state1][state2][state3] = res; } //--------------------------------------------------------------------------------------------------- void _main() { cin >> N; cout << f(60, 0, 0, 0) << endl; }