結果
問題 | No.206 数の積集合を求めるクエリ |
ユーザー |
![]() |
提出日時 | 2015-05-09 11:10:22 |
言語 | PyPy2 (7.3.15) |
結果 |
AC
|
実行時間 | 327 ms / 7,000 ms |
コード長 | 1,712 bytes |
コンパイル時間 | 1,280 ms |
コンパイル使用メモリ | 76,328 KB |
実行使用メモリ | 139,960 KB |
最終ジャッジ日時 | 2024-07-05 21:09:55 |
合計ジャッジ時間 | 8,053 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 28 |
ソースコード
import sys def ilog2(n): if n <= 0: return 0 else: return n.bit_length() - 1 def _pack(pack, shamt): size = len(pack) while size > 1: npack = [] for i in range(0, size - 1, 2): npack.append(pack[i] | (pack[i+1] << shamt)) if size & 1: npack.append(pack[-1]) pack = npack size = (size + 1) >> 1 shamt <<= 1 return pack[0] def _pack2(seq1, seq2, shamt): M1 = _pack(seq1, shamt) M2 = _pack(seq2, shamt) size = len(seq1) + len(seq2) - 1 block_size = 1 << ilog2(size - 1) return M1, M2, shamt * block_size def pack_sequence2_mod(seq1, seq2, mod): size = min(len(seq1), len(seq2)) max_value = (mod - 1) ** 2 * size shamt = max_value.bit_length() return _pack2(seq1, seq2, shamt) def unpack_sequence(M, size, shamt): needed_sizes = [] s = size while s > 1: needed_sizes.append(s) s = (s + 1) >> 1 ret = [M] for needed_size in needed_sizes[::-1]: mask = (1 << shamt) - 1 nret = [] for c in ret: nret.append(c & mask) nret.append(c >> shamt) ret = nret[:needed_size] shamt >>= 1 return ret def poly_mul_mod_builtin(poly1, poly2, mod): M1, M2, shamt = pack_sequence2_mod(poly1, poly2, mod) size = len(poly1) + len(poly2) - 1 seq = unpack_sequence(M1 * M2, size, shamt) return seq # x % mod def solve(): stdin = sys.stdin write = sys.stdout.write _, _, N = map(int, stdin.readline().split()) A = [0] * (N + 1) B = [0] * (N + 1) for n in map(int, stdin.readline().split()): A[n] = 1 for n in map(int, stdin.readline().split()): B[N - n] = 1 Q = int(stdin.readline()) C = poly_mul_mod_builtin(A, B, 2) write("%s\n" % "\n".join(map(str, C[N:N+Q]))) solve()