結果
| 問題 |
No.206 数の積集合を求めるクエリ
|
| コンテスト | |
| ユーザー |
Min_25
|
| 提出日時 | 2015-05-09 11:11:05 |
| 言語 | Python2 (2.7.18) |
| 結果 |
AC
|
| 実行時間 | 525 ms / 7,000 ms |
| コード長 | 1,712 bytes |
| コンパイル時間 | 444 ms |
| コンパイル使用メモリ | 7,068 KB |
| 実行使用メモリ | 26,912 KB |
| 最終ジャッジ日時 | 2024-07-05 21:10:03 |
| 合計ジャッジ時間 | 7,936 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 28 |
ソースコード
import sys
def ilog2(n):
if n <= 0:
return 0
else:
return n.bit_length() - 1
def _pack(pack, shamt):
size = len(pack)
while size > 1:
npack = []
for i in range(0, size - 1, 2):
npack.append(pack[i] | (pack[i+1] << shamt))
if size & 1:
npack.append(pack[-1])
pack = npack
size = (size + 1) >> 1
shamt <<= 1
return pack[0]
def _pack2(seq1, seq2, shamt):
M1 = _pack(seq1, shamt)
M2 = _pack(seq2, shamt)
size = len(seq1) + len(seq2) - 1
block_size = 1 << ilog2(size - 1)
return M1, M2, shamt * block_size
def pack_sequence2_mod(seq1, seq2, mod):
size = min(len(seq1), len(seq2))
max_value = (mod - 1) ** 2 * size
shamt = max_value.bit_length()
return _pack2(seq1, seq2, shamt)
def unpack_sequence(M, size, shamt):
needed_sizes = []
s = size
while s > 1:
needed_sizes.append(s)
s = (s + 1) >> 1
ret = [M]
for needed_size in needed_sizes[::-1]:
mask = (1 << shamt) - 1
nret = []
for c in ret:
nret.append(c & mask)
nret.append(c >> shamt)
ret = nret[:needed_size]
shamt >>= 1
return ret
def poly_mul_mod_builtin(poly1, poly2, mod):
M1, M2, shamt = pack_sequence2_mod(poly1, poly2, mod)
size = len(poly1) + len(poly2) - 1
seq = unpack_sequence(M1 * M2, size, shamt)
return seq # x % mod
def solve():
stdin = sys.stdin
write = sys.stdout.write
_, _, N = map(int, stdin.readline().split())
A = [0] * (N + 1)
B = [0] * (N + 1)
for n in map(int, stdin.readline().split()):
A[n] = 1
for n in map(int, stdin.readline().split()):
B[N - n] = 1
Q = int(stdin.readline())
C = poly_mul_mod_builtin(A, B, 2)
write("%s\n" % "\n".join(map(str, C[N:N+Q])))
solve()
Min_25