結果
| 問題 | No.5002 stick xor | 
| コンテスト | |
| ユーザー |  | 
| 提出日時 | 2018-05-25 23:35:42 | 
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 6 ms / 1,000 ms | 
| コード長 | 2,738 bytes | 
| コンパイル時間 | 5,171 ms | 
| 実行使用メモリ | 1,536 KB | 
| スコア | 15,635 | 
| 最終ジャッジ日時 | 2018-05-25 23:35:49 | 
| ジャッジサーバーID (参考情報) | judge7 / | 
| 純コード判定しない問題か言語 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 32 | 
ソースコード
#include <bits/stdc++.h>
#define REP(i, n) for (int i = 0; (i) < int(n); ++ (i))
#define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i))
#define REP_R(i, n) for (int i = int(n) - 1; (i) >= 0; -- (i))
#define REP3R(i, m, n) for (int i = int(n) - 1; (i) >= int(m); -- (i))
#define ALL(x) begin(x), end(x)
#define dump(x) cerr << #x " = " << x << endl
#define unittest_name_helper(counter) unittest_ ## counter
#define unittest_name(counter) unittest_name_helper(counter)
#define unittest __attribute__((constructor)) void unittest_name(__COUNTER__) ()
using ll = long long;
using namespace std;
template <class T> using reversed_priority_queue = priority_queue<T, vector<T>, greater<T> >;
template <class T> inline void chmax(T & a, T const & b) { a = max(a, b); }
template <class T> inline void chmin(T & a, T const & b) { a = min(a, b); }
template <typename X, typename T> auto vectors(X x, T a) { return vector<T>(x, a); }
template <typename X, typename Y, typename Z, typename... Zs> auto vectors(X x, Y y, Z z, Zs... zs) { auto cont = vectors(y, z, zs...); return vector<decltype(cont)>(x, cont); }
template <typename T> ostream & operator << (ostream & out, vector<T> const & xs) { REP (i, int(xs.size()) - 1) out << xs[i] << ' '; if (not xs.empty()) out << xs.back(); return out; }
vector<tuple<int, int, bool> > solve(int n, int k, vector<int> const & l, vector<vector<bool> > a) {
    vector<vector<int> > lookup(n + 1);
    REP (i, k) lookup[l[i]].push_back(i);
    REP (len, n + 1) reverse(ALL(lookup[len]));  // for better visualization
    vector<tuple<int, int, bool> > result(k, make_tuple(n - 1, 0, true));
    REP (y, n) {
        REP (x, n) if (a[y][x]) {
            int len = 1;
            while (y + len < n and a[y + len][x]) ++ len;
            while (len and lookup[len].empty()) -- len;
            if (not len) continue;
            // use len vertically
            int i = lookup[len].back();
            lookup[len].pop_back();
            result[i] = make_tuple(y, x, false);
            REP3 (y1, y, y + len) {
                a[y1][x] = not a[y1][x];
            }
        }
    }
    return result;
}
int main() {
    // input
    int n, k; cin >> n >> k;
    vector<int> l(k);
    REP (i, k) cin >> l[i];
    auto a = vectors(n, n, bool());
    REP (y, n) REP (x, n) {
        char c; cin >> c;
        a[y][x] = c - '0';
    }
    // solve
    vector<tuple<int, int, bool> > result = solve(n, k, l, a);
    // output
    REP (i, k) {
        int y, x; bool is_vertical; tie(y, x, is_vertical) = result[i];
        int ny = y;
        int nx = x;
        (is_vertical ? nx : ny) += l[i] - 1;
        cout << y + 1 << ' ' << x + 1 << ' ' << ny + 1 << ' ' << nx + 1 << endl;
    }
    return 0;
}
            
            
            
        