結果
| 問題 |
No.5002 stick xor
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2018-05-25 23:35:42 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 6 ms / 1,000 ms |
| コード長 | 2,738 bytes |
| コンパイル時間 | 5,171 ms |
| 実行使用メモリ | 1,536 KB |
| スコア | 15,635 |
| 最終ジャッジ日時 | 2018-05-25 23:35:49 |
|
ジャッジサーバーID (参考情報) |
judge7 / |
| 純コード判定しない問題か言語 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 32 |
ソースコード
#include <bits/stdc++.h>
#define REP(i, n) for (int i = 0; (i) < int(n); ++ (i))
#define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i))
#define REP_R(i, n) for (int i = int(n) - 1; (i) >= 0; -- (i))
#define REP3R(i, m, n) for (int i = int(n) - 1; (i) >= int(m); -- (i))
#define ALL(x) begin(x), end(x)
#define dump(x) cerr << #x " = " << x << endl
#define unittest_name_helper(counter) unittest_ ## counter
#define unittest_name(counter) unittest_name_helper(counter)
#define unittest __attribute__((constructor)) void unittest_name(__COUNTER__) ()
using ll = long long;
using namespace std;
template <class T> using reversed_priority_queue = priority_queue<T, vector<T>, greater<T> >;
template <class T> inline void chmax(T & a, T const & b) { a = max(a, b); }
template <class T> inline void chmin(T & a, T const & b) { a = min(a, b); }
template <typename X, typename T> auto vectors(X x, T a) { return vector<T>(x, a); }
template <typename X, typename Y, typename Z, typename... Zs> auto vectors(X x, Y y, Z z, Zs... zs) { auto cont = vectors(y, z, zs...); return vector<decltype(cont)>(x, cont); }
template <typename T> ostream & operator << (ostream & out, vector<T> const & xs) { REP (i, int(xs.size()) - 1) out << xs[i] << ' '; if (not xs.empty()) out << xs.back(); return out; }
vector<tuple<int, int, bool> > solve(int n, int k, vector<int> const & l, vector<vector<bool> > a) {
vector<vector<int> > lookup(n + 1);
REP (i, k) lookup[l[i]].push_back(i);
REP (len, n + 1) reverse(ALL(lookup[len])); // for better visualization
vector<tuple<int, int, bool> > result(k, make_tuple(n - 1, 0, true));
REP (y, n) {
REP (x, n) if (a[y][x]) {
int len = 1;
while (y + len < n and a[y + len][x]) ++ len;
while (len and lookup[len].empty()) -- len;
if (not len) continue;
// use len vertically
int i = lookup[len].back();
lookup[len].pop_back();
result[i] = make_tuple(y, x, false);
REP3 (y1, y, y + len) {
a[y1][x] = not a[y1][x];
}
}
}
return result;
}
int main() {
// input
int n, k; cin >> n >> k;
vector<int> l(k);
REP (i, k) cin >> l[i];
auto a = vectors(n, n, bool());
REP (y, n) REP (x, n) {
char c; cin >> c;
a[y][x] = c - '0';
}
// solve
vector<tuple<int, int, bool> > result = solve(n, k, l, a);
// output
REP (i, k) {
int y, x; bool is_vertical; tie(y, x, is_vertical) = result[i];
int ny = y;
int nx = x;
(is_vertical ? nx : ny) += l[i] - 1;
cout << y + 1 << ' ' << x + 1 << ' ' << ny + 1 << ' ' << nx + 1 << endl;
}
return 0;
}