結果

問題 No.5002 stick xor
ユーザー packer_jppacker_jp
提出日時 2018-05-27 00:46:57
言語 C++11
(gcc 11.4.0)
結果
AC  
実行時間 977 ms / 1,000 ms
コード長 3,172 bytes
コンパイル時間 34,605 ms
実行使用メモリ 1,548 KB
スコア -39,789
最終ジャッジ日時 2018-05-27 00:47:33
ジャッジサーバーID
(参考情報)
judge8 /
純コード判定しない問題か言語
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 974 ms
1,544 KB
testcase_01 AC 974 ms
1,544 KB
testcase_02 AC 974 ms
1,544 KB
testcase_03 AC 974 ms
1,544 KB
testcase_04 AC 974 ms
1,544 KB
testcase_05 AC 973 ms
1,544 KB
testcase_06 AC 974 ms
1,544 KB
testcase_07 AC 974 ms
1,548 KB
testcase_08 AC 974 ms
1,548 KB
testcase_09 AC 974 ms
1,544 KB
testcase_10 AC 974 ms
1,548 KB
testcase_11 AC 973 ms
1,544 KB
testcase_12 AC 974 ms
1,544 KB
testcase_13 AC 973 ms
1,544 KB
testcase_14 AC 974 ms
1,548 KB
testcase_15 AC 977 ms
1,544 KB
testcase_16 AC 974 ms
1,548 KB
testcase_17 AC 973 ms
1,548 KB
testcase_18 AC 974 ms
1,548 KB
testcase_19 AC 974 ms
1,548 KB
testcase_20 AC 974 ms
1,544 KB
testcase_21 AC 974 ms
1,544 KB
testcase_22 AC 973 ms
1,544 KB
testcase_23 AC 974 ms
1,548 KB
testcase_24 AC 973 ms
1,544 KB
testcase_25 AC 974 ms
1,544 KB
testcase_26 AC 975 ms
1,548 KB
testcase_27 AC 974 ms
1,548 KB
testcase_28 AC 973 ms
1,544 KB
testcase_29 AC 973 ms
1,548 KB
testcase_30 AC 975 ms
1,544 KB
testcase_31 AC 974 ms
1,548 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <bits/stdc++.h>
using namespace std;

#define int long long
typedef pair<int, int> P;
int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};
int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};

/*
ifstream ifs("in.txt");
ofstream ofs("out.txt");
#define cin ifs
#define cout ofs
//*/

// xorshiftを用いた乱数
long long xor64(long long range) {
    static unsigned long long x = 88172645463325252ULL;
    x ^= x << 13;
    x ^= x >> 7;
    return (x ^= x << 17) % range;
}

// タイマー
struct Timer {
    unsigned long long begin_cycle;
    double cycle_per_sec = 2.8e9;
    unsigned long long getCycle() {
        unsigned low, high;
        __asm__ volatile("rdtsc"
                         : "=a"(low), "=d"(high));
        return ((unsigned long long)low) | ((unsigned long long)high << 32);
    }
    double getTime() {
        return (getCycle() - begin_cycle) / cycle_per_sec;
    }
    void init() {
        begin_cycle = getCycle();
    }
};

int N, K;
int L[550];
bool A[66][66];
int a[550], b[550], c[550], d[550];
double T = 0.9;
Timer timer;

signed main() {
    cin >> N >> K;
    for (int i = 0; i < K; i++) {
        cin >> L[i];
    }
    for (int i = 0; i < N; i++) {
        string s;
        cin >> s;
        for (int j = 0; j < N; j++) {
            A[i][j] = s[j] == '1';
        }
    }
    timer.init();
    for (int i = 0; i < K; i++) {
        if (xor64(2) == 0) {
            a[i] = xor64(N);
            b[i] = xor64(N - L[i] + 1);
            c[i] = a[i];
            d[i] = b[i] + L[i] - 1;
        } else {
            a[i] = xor64(N - L[i] + 1);
            b[i] = xor64(N);
            c[i] = a[i] + L[i] - 1;
            d[i] = b[i];
        }
        for (int j = a[i]; j <= c[i]; j++) {
            for (int k = b[i]; k <= d[i]; k++) {
                A[j][k] ^= 1;
            }
        }
    }
    while (timer.getTime() < T) {
        int i = xor64(K);
        int diff = 0;
        for (int j = a[i]; j <= c[i]; j++) {
            for (int k = b[i]; k <= d[i]; k++) {
                A[j][k] ^= 1;
                diff += A[j][k] * 2 - 1;
            }
        }
        int na, nb, nc, nd;
        if (xor64(2) == 0) {
            na = xor64(N);
            nb = xor64(N - L[i] + 1);
            nc = na;
            nd = nb + L[i] - 1;
        } else {
            na = xor64(N - L[i] + 1);
            nb = xor64(N);
            nc = na + L[i] - 1;
            nd = nb;
        }
        for (int j = na; j <= nc; j++) {
            for (int k = nb; k <= nd; k++) {
                A[j][k] ^= 1;
                diff += A[j][k] * 2 - 1;
            }
        }
        if (diff < 0) {
            for (int j = a[i]; j <= c[i]; j++) {
                for (int k = b[i]; k <= d[i]; k++) {
                    A[j][k] ^= 1;
                }
            }
            for (int j = na; j <= nc; j++) {
                for (int k = nb; k <= nd; k++) {
                    A[j][k] ^= 1;
                }
            }
        } else {
            a[i] = na, b[i] = nb, c[i] = nc, d[i] = nd;
        }
    }
    for (int i = 0; i < K; i++) {
        cout << a[i] + 1 << " " << b[i] + 1 << " " << c[i] + 1 << " " << d[i] + 1 << endl;
    }
}
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