結果

問題 No.209 Longest Mountain Subsequence
ユーザー Kmcode1
提出日時 2015-05-15 23:12:37
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 44 ms / 2,000 ms
コード長 2,314 bytes
コンパイル時間 1,003 ms
コンパイル使用メモリ 103,140 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-07-06 04:14:24
合計ジャッジ時間 1,431 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
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ファイルパターン 結果
other AC * 6
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:74:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   74 |         scanf("%d", &t);
      |         ~~~~~^~~~~~~~~~
main.cpp:76:22: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   76 |                 scanf("%d", &n);
      |                 ~~~~~^~~~~~~~~~
main.cpp:78:30: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   78 |                         scanf("%d", &a[i]);
      |                         ~~~~~^~~~~~~~~~~~~

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cctype>
#include<cstdlib>
#include<algorithm>
#include<bitset>
#include<vector>
#include<list>
#include<deque>
#include<queue>
#include<map>
#include<set>
#include<stack>
#include<cmath>
#include<sstream>
#include<fstream>
#include<iomanip>
#include<ctime>
#include<complex>
#include<functional>
#include<climits>
#include<cassert>
#include<iterator>
using namespace std;
int t;
int n;
#define MAX 102
int a[MAX];
vector<pair<int,int> > v[MAX];  //cost,go
bool use[MAX][MAX];
int dp[MAX][MAX];
inline void dfs(int aa, int b){
    if (use[aa][b]){
        return;
    }
    use[aa][b] = true;
    dp[aa][b] = 0;
    int pre = a[b] - a[aa];
    if (aa == b){
        pre = INT_MAX;
    }
    int ind = lower_bound(v[aa].begin(), v[aa].end(), make_pair(pre, -1))-v[aa].begin();
    ind--;
    for (int i = ind; i>=0; i--){
        dfs(v[aa][i].second, aa);
        dp[aa][b] = max(dp[aa][b], dp[v[aa][i].second][aa]);
    }
    dp[aa][b]++;
}
int dp2[MAX][MAX];
inline void dfs2(int aa, int b){
    if (use[aa][b]){
        return;
    }
    use[aa][b] = true;
    dp2[aa][b] = 0;
    int pre = a[b] - a[aa];
    if (aa == b){
        pre = INT_MAX;
    }
    int ind = lower_bound(v[aa].begin(), v[aa].end(), make_pair(pre, -1)) - v[aa].begin();
    ind--;
    for (int i = ind; i>=0; i--){
        dfs2(v[aa][i].second, aa);
        dp2[aa][b] = max(dp2[aa][b], dp2[v[aa][i].second][aa]);
    }
    dp2[aa][b]++;
}
int main(){
    scanf("%d", &t);
    while (t--){
        scanf("%d", &n);
        for (int i = 0; i < n; i++){
            scanf("%d", &a[i]);
        }
        for (int i = 0; i < n; i++){
            v[i].clear();
        }
        for (int i = 0; i < n; i++){
            for (int j = i + 1; j < n; j++){
                if (a[i] > a[j]){
                    v[i].push_back(make_pair(a[i] - a[j],j));
                }
            }
        }
        for (int i = 0; i < n; i++){
            sort(v[i].begin(), v[i].end());
        }
        memset(use, false, sizeof(use));
        for (int i = 0; i < n; i++){
            dfs2(i, i);
        }
        for (int i = 0; i < n; i++){
            v[i].clear();
        }
        for (int i = 0; i < n; i++){
            for (int j = i - 1; j >= 0; j--){
                if (a[i]>a[j]){
                    v[i].push_back(make_pair(a[i] - a[j], j));
                }
            }
        }
        for (int i = 0; i < n; i++){
            sort(v[i].begin(), v[i].end());
        }
        memset(use, false, sizeof(use));
        int maxt = 1;
        for (int i = 0; i < n; i++){
            dfs(i, i);
            maxt = max(maxt, dp[i][i] + dp2[i][i] - 1);
        }
        printf("%d\n", maxt);
    }
    return 0;
}
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