結果

問題 No.168 ものさし
ユーザー rpy3cpprpy3cpp
提出日時 2015-05-21 12:48:01
言語 Python3
(3.12.2 + numpy 1.26.4 + scipy 1.12.0)
結果
AC  
実行時間 439 ms / 2,000 ms
コード長 1,941 bytes
コンパイル時間 173 ms
コンパイル使用メモリ 12,800 KB
実行使用メモリ 46,336 KB
最終ジャッジ日時 2024-06-06 14:58:36
合計ジャッジ時間 4,359 ms
ジャッジサーバーID
(参考情報)
judge3 / judge1
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 130 ms
19,456 KB
testcase_01 AC 31 ms
11,008 KB
testcase_02 AC 30 ms
10,880 KB
testcase_03 AC 31 ms
10,880 KB
testcase_04 AC 32 ms
10,880 KB
testcase_05 AC 32 ms
11,008 KB
testcase_06 AC 31 ms
11,008 KB
testcase_07 AC 31 ms
11,008 KB
testcase_08 AC 31 ms
11,008 KB
testcase_09 AC 33 ms
11,136 KB
testcase_10 AC 41 ms
12,032 KB
testcase_11 AC 125 ms
18,176 KB
testcase_12 AC 334 ms
34,560 KB
testcase_13 AC 439 ms
44,288 KB
testcase_14 AC 272 ms
40,960 KB
testcase_15 AC 32 ms
11,008 KB
testcase_16 AC 33 ms
11,264 KB
testcase_17 AC 39 ms
11,520 KB
testcase_18 AC 49 ms
12,928 KB
testcase_19 AC 428 ms
45,568 KB
testcase_20 AC 332 ms
46,336 KB
testcase_21 AC 428 ms
45,696 KB
testcase_22 AC 327 ms
45,568 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

import heapq


def read_data():
    N = int(input())
    ps = [list(map(int, input().split())) for i in range(N)]
    return N, ps


def solve(N, ps):
    dist = set_dist(ps)
    tick = 10
    start = 0
    goal = N - 1
    dist_s = [dist[start][v] for v in range(N)]
    dist_g = [dist[goal][v] for v in range(N)]
    pq_s = [(dist_s[v], v) for v in range(1, N)]
    pq_g = [(dist_g[v], v) for v in range(0, N - 1)]
    heapq.heapify(pq_s)
    heapq.heapify(pq_g)
    max_scale2 = 0
    found = False
    while not found:
        d_s, vs = get_next(pq_s, dist_s)
        d_g, vg = get_next(pq_g, dist_g)
        if d_s < d_g:
            if d_s > max_scale2:
                max_scale2 = d_s
            found = process(dist_s, dist_g, pq_s, vs, dist[vs])
        else:
            if d_g > max_scale2:
                max_scale2 = d_g
            found = process(dist_g, dist_s, pq_g, vg, dist[vg])
    return square_round(max_scale2, tick)


def set_dist(ps):
    N = len(ps)
    dist = [[0] * N for v in range(N)]
    for i in range(N-1):
        x0, y0 = ps[i]
        for j in range(i + 1, N):
            x1, y1 = ps[j]
            d = (x0 - x1) * (x0 - x1) + (y0 - y1) * (y0 - y1)
            dist[i][j] = d
            dist[j][i] = d
    return dist


def get_next(pq, dist_x):
    d, v = pq[0]
    while not dist_x[v]:
        heapq.heappop(pq)
        d, v = pq[0]
    return d, v


def process(dist_0, dist_1, pq_0, v0, dist_v0):
    heapq.heappop(pq_0)
    if not dist_1[v0]:
        return True
    dist_0[v0] = 0
    for new_v, (d, new_d) in enumerate(zip(dist_0, dist_v0)):
        if new_d < d:
            heapq.heappush(pq_0, (new_d, new_v))
            dist_0[new_v] = new_d
    return False


def square_round(x_sq, tick):
    x = x_sq ** 0.5
    x_int = (int(x) // tick) * tick
    if x_int ** 2 < x_sq:
        x_int += tick
    return x_int


if __name__ == '__main__':
    N, ps = read_data()
    print(solve(N, ps))
0