結果
問題 | No.125 悪の花弁 |
ユーザー |
![]() |
提出日時 | 2018-09-09 08:35:10 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 102 ms / 5,000 ms |
コード長 | 4,316 bytes |
コンパイル時間 | 2,012 ms |
コンパイル使用メモリ | 177,976 KB |
実行使用メモリ | 15,432 KB |
最終ジャッジ日時 | 2024-12-23 02:42:40 |
合計ジャッジ時間 | 3,014 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
other | AC * 6 |
ソースコード
#include<bits/stdc++.h>#define rep(i,a,b) for(int i=a;i<b;i++)#define rrep(i,a,b) for(int i=a;i>=b;i--)#define fore(i,a) for(auto &i:a)#define all(x) (x).begin(),(x).end()#pragma GCC optimize ("-O3")using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60;template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }//---------------------------------------------------------------------------------------------------vector<int> enumdiv(int n) {vector<int> S;for (int i = 1; 1LL*i*i <= n; i++) if (n%i == 0) { S.push_back(i); if (i*i != n) S.push_back(n / i); }sort(S.begin(), S.end());return S;}template<int MOD> struct ModInt {static const int Mod = MOD; unsigned x; ModInt() : x(0) { }ModInt(signed sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }ModInt(signed long long sig) { x = sig < 0 ? sig % MOD + MOD : sig % MOD; }int get() const { return (int)x; }ModInt &operator+=(ModInt that) { if ((x += that.x) >= MOD) x -= MOD; return *this; }ModInt &operator-=(ModInt that) { if ((x += MOD - that.x) >= MOD) x -= MOD; return *this; }ModInt &operator*=(ModInt that) { x = (unsigned long long)x * that.x % MOD; return *this; }ModInt &operator/=(ModInt that) { return *this *= that.inverse(); }ModInt operator+(ModInt that) const { return ModInt(*this) += that; }ModInt operator-(ModInt that) const { return ModInt(*this) -= that; }ModInt operator*(ModInt that) const { return ModInt(*this) *= that; }ModInt operator/(ModInt that) const { return ModInt(*this) /= that; }ModInt inverse() const { long long a = x, b = MOD, u = 1, v = 0;while (b) { long long t = a / b; a -= t * b; std::swap(a, b); u -= t * v; std::swap(u, v); }return ModInt(u); }bool operator==(ModInt that) const { return x == that.x; }bool operator!=(ModInt that) const { return x != that.x; }ModInt operator-() const { ModInt t; t.x = x == 0 ? 0 : Mod - x; return t; }};template<int MOD> ostream& operator<<(ostream& st, const ModInt<MOD> a) { st << a.get(); return st; };template<int MOD> ModInt<MOD> operator^(ModInt<MOD> a, unsigned long long k) {ModInt<MOD> r = 1; while (k) { if (k & 1) r *= a; a *= a; k >>= 1; } return r; }template<typename T, int FAC_MAX> struct Comb { vector<T> fac, ifac;Comb(){fac.resize(FAC_MAX,1);ifac.resize(FAC_MAX,1);rep(i,1,FAC_MAX)fac[i]=fac[i-1]*i;ifac[FAC_MAX-1]=T(1)/fac[FAC_MAX-1];rrep(i,FAC_MAX-2,1)ifac[i]=ifac[i+1]*T(i+1);}T aPb(int a, int b) { if (b < 0 || a < b) return T(0); return fac[a] * ifac[a - b]; }T aCb(int a, int b) { if (b < 0 || a < b) return T(0); return fac[a] * ifac[a - b] * ifac[b]; }T nHk(int n, int k) { if (n == 0 && k == 0) return T(1); if (n <= 0 || k < 0) return 0;return aCb(n + k - 1, k); }}; // nHk = (n+k-1)Cktypedef ModInt<1000000007> mint;/*---------------------------------------------------------------------------------------------------∧_∧∧_∧ (´<_` ) Welcome to My Coding Space!( ´_ゝ`) / ⌒i/ \ | |/ / ̄ ̄ ̄ ̄/ |__(__ニつ/ _/ .| .|____\/____/ (u ⊃---------------------------------------------------------------------------------------------------*/int K, C[101010], N;Comb<mint,1010101> com;mint memo[1010101];//---------------------------------------------------------------------------------------------------void _main() {cin >> K;rep(i, 0, K) cin >> C[i];N = 0;rep(i, 0, K) N += C[i];mint ans = 0;fore(_n, enumdiv(N)) {int n = N / _n;int ng = 0;rep(k, 0, K) if (C[k] % n != 0) ng = 1;if (ng) continue;memo[n] = com.fac[N / n];rep(k, 0, K) memo[n] *= com.ifac[C[k] / n];for (int nn = n * 2; nn <= N; nn += n) memo[n] -= memo[nn];ans += memo[n] / (N / n);}cout << ans << endl;}