結果
問題 | No.318 学学学学学 |
ユーザー | kurenaif |
提出日時 | 2018-09-15 05:26:37 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 182 ms / 2,000 ms |
コード長 | 7,481 bytes |
コンパイル時間 | 1,532 ms |
コンパイル使用メモリ | 124,300 KB |
実行使用メモリ | 13,568 KB |
最終ジャッジ日時 | 2024-06-22 18:43:04 |
合計ジャッジ時間 | 5,019 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 12 ms
6,816 KB |
testcase_01 | AC | 24 ms
6,940 KB |
testcase_02 | AC | 27 ms
6,940 KB |
testcase_03 | AC | 17 ms
6,940 KB |
testcase_04 | AC | 25 ms
6,944 KB |
testcase_05 | AC | 182 ms
13,568 KB |
testcase_06 | AC | 156 ms
10,496 KB |
testcase_07 | AC | 125 ms
9,472 KB |
testcase_08 | AC | 108 ms
8,576 KB |
testcase_09 | AC | 85 ms
8,064 KB |
testcase_10 | AC | 61 ms
7,424 KB |
testcase_11 | AC | 164 ms
13,568 KB |
testcase_12 | AC | 115 ms
10,496 KB |
testcase_13 | AC | 95 ms
9,600 KB |
testcase_14 | AC | 74 ms
8,576 KB |
testcase_15 | AC | 63 ms
8,064 KB |
testcase_16 | AC | 49 ms
7,424 KB |
testcase_17 | AC | 120 ms
10,496 KB |
testcase_18 | AC | 96 ms
10,624 KB |
testcase_19 | AC | 122 ms
10,496 KB |
testcase_20 | AC | 48 ms
7,552 KB |
testcase_21 | AC | 2 ms
6,940 KB |
testcase_22 | AC | 2 ms
6,940 KB |
testcase_23 | AC | 2 ms
6,948 KB |
testcase_24 | AC | 2 ms
6,940 KB |
testcase_25 | AC | 2 ms
6,940 KB |
testcase_26 | AC | 2 ms
6,940 KB |
testcase_27 | AC | 1 ms
6,944 KB |
testcase_28 | AC | 2 ms
6,940 KB |
ソースコード
#include <iostream> #include <numeric> #include <queue> #include <map> #include <list> #include <vector> #include <string> #include <stack> #include <limits> #include <climits> #include <cassert> #include <fstream> #include <cstring> #include <cmath> #include <bitset> #include <iomanip> #include <algorithm> #include <functional> #include <cstdio> #include <ciso646> #include <set> #include <array> #include <unordered_map> #include <unordered_set> #include <type_traits> using namespace std; #define FOR(i,a,b) for (int i=(a);i<(b);i++) #define RFOR(i,a,b) for (int i=(b)-1;i>=(a);i--) #define REP(i,n) for (int i=0;i<(n);i++) #define RREP(i,n) for (int i=(n)-1;i>=0;i--) #define inf 0x3f3f3f3f3f3f3f3f #define ALL(a) (a).begin(),(a).end() #define DEBUG(x) cout<<#x<<": "<<x<<endl #define ll long long #define ull unsigned long long using pii = pair<ll, ll>; #define eps 1e-14 #define SETUP cin.tie(0), ios::sync_with_stdio(false), cout << setprecision(15) << std::fixed; template <class T> using vec2 = std::vector<vector<T>>; namespace { struct input_returnner { ll N; input_returnner(ll N_ = 0) :N(N_) {} template<typename T> operator vector<T>() const { vector<T> res(N); for (auto &a : res) cin >> a; return std::move(res); } template<typename T> operator T() const { T res; cin >> res; return res; } template<typename T> T operator - (T right) { return T(input_returnner()) - right; } template<typename T> T operator + (T right) { return T(input_returnner()) + right; } template<typename T> T operator * (T right) { return T(input_returnner()) * right; } template<typename T> T operator / (T right) { return T(input_returnner()) / right; } template<typename T> T operator << (T right) { return T(input_returnner()) << right; } template<typename T> T operator >> (T right) { return T(input_returnner()) >> right; } }; template<typename T> input_returnner in() { return in<T>(); } input_returnner in() { return input_returnner(); } input_returnner in(ll N) { return std::move(input_returnner(N)); } } template<typename T> istream& operator >> (istream& is, vector<T>& vec) { for (T& x : vec) is >> x; return is; } template < typename T > struct is_vector : std::false_type {}; template < typename T > struct is_vector<std::vector<T>> : std::true_type {}; template < typename T > constexpr bool is_vector_v = is_vector<T>::value; template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector<T>& v) { if (!v.empty()) { for (int i = 0; i < v.size(); ++i) { out << v[i] << (i == v.size() - 1 ? "\n" : (is_vector_v<T> ? "" : ", ")); } } return out; } namespace std { // ref: https://stackoverflow.com/questions/7110301/generic-hash-for-tuples-in-unordered-map-unordered-set template <class T> inline void hash_combine(std::size_t& seed, T const& v) { seed ^= std::hash<T>()(v) + 0x9e3779b9 + (seed << 6) + (seed >> 2); } // Recursive template code derived from Matthieu M. template <class Tuple, size_t Index = std::tuple_size<Tuple>::value - 1> struct HashValueImpl { static void apply(size_t& seed, Tuple const& tuple) { HashValueImpl<Tuple, Index - 1>::apply(seed, tuple); hash_combine(seed, std::get<Index>(tuple)); } }; template <class Tuple> struct HashValueImpl<Tuple, 0> { static void apply(size_t& seed, Tuple const& tuple) { hash_combine(seed, std::get<0>(tuple)); } }; template <typename ... TT> struct hash<std::tuple<TT...>> { size_t operator()(std::tuple<TT...> const& tt) const { size_t seed = 0; HashValueImpl<std::tuple<TT...> >::apply(seed, tt); return seed; } }; template <class T, class U> class hash<std::pair<T, U>> { public: size_t operator()(const std::pair<T, U>& x) const { return hash<std::tuple<T, U>>()(std::tie(x.first, x.second)); } }; } // ref: https://stackoverflow.com/questions/6245735/pretty-print-stdtuple namespace aux { template<std::size_t...> struct seq {}; template<std::size_t N, std::size_t... Is> struct gen_seq : gen_seq<N - 1, N - 1, Is...> {}; template<std::size_t... Is> struct gen_seq<0, Is...> : seq<Is...> {}; template<class Ch, class Tr, class Tuple, std::size_t... Is> void print_tuple(std::basic_ostream<Ch, Tr>& os, Tuple const& t, seq<Is...>) { using swallow = int[]; (void)swallow { 0, (void(os << (Is == 0 ? "" : ", ") << std::get<Is>(t)), 0)... }; } } // aux:: template<class Ch, class Tr, class... Args> auto operator<<(std::basic_ostream<Ch, Tr>& os, std::tuple<Args...> const& t) -> std::basic_ostream<Ch, Tr>& { os << "("; aux::print_tuple(os, t, aux::gen_seq<sizeof...(Args)>()); return os << ")"; } template<class S, class T> std::ostream & operator<<(std::ostream & os, const std::pair<S, T> & p) { return os << "(" << p.first << ", " << p.second << ")"; } // ref: https://stackoverflow.com/questions/8542591/c11-reverse-range-based-for-loo�Fp template <typename T> struct reversion_wrapper { T& iterable; }; template <typename T> auto begin(reversion_wrapper<T> w) { return std::rbegin(w.iterable); } template <typename T> auto end(reversion_wrapper<T> w) { return std::rend(w.iterable); } template <typename T> reversion_wrapper<T> REV(T&& iterable) { return { iterable }; } template<class T> bool inside(T left, T val, T right) { return left <= val and val < right; } int bitCount(int num) { int res = 0; while (num > 0) { num >>= 1; ++res; } return res; } ll MOD = 1e9 + 7; void solve(); signed main() { SETUP; solve(); #ifdef _DEBUGa //system("pause"); #endif return 0; } // template #define int long long template<class T> class LazySegtree { private: int n; vector<T> dat; vector<T> lazy; vector<bool> lazyFlag; void eval(int k, int l, int r){ if (lazyFlag[k]) { dat[k] = lazy[k]; if (r - l > 1) { lazy[2 * k + 1] = lazy[k]; lazy[2 * k + 2] = lazy[k]; lazyFlag[2 * k + 1] = lazyFlag[2 * k + 2] = true; } } lazyFlag[k] = false; } T query(int a, int b, int k, int l, int r) { eval(k, l, r); if (r <= a || b <= l) return numeric_limits<T>::max(); if (a <= l & r <= b) return dat[k]; T vl = query(a, b, k * 2 + 1, l, (l + r) / 2); T vr = query(a, b, k * 2 + 2, (l + r) / 2, r); return min(vl, vr); } // change [a,b) to value void update(int a, int b, T value, int k, int l, int r){ eval(k, l, r); if (b <= l or r <= a) return; if (a <= l and r <= b) { lazy[k] = value; lazyFlag[k] = true; eval(k, l, r); } else { update(a, b, value, 2 * k + 1, l, (l + r) / 2); update(a, b, value, 2 * k + 2, (l + r) / 2, r); dat[k] = min(dat[2 * k + 1], dat[2 * k + 2]); } } public: LazySegtree(int n_) { n = 1; while (n < n_) n *= 2; dat.resize(2 * n - 1); lazy.resize(2 * n - 1); lazyFlag.resize(2 * n - 1); for (int i = 0; i < 2 * n - 1; ++i) dat[i] = numeric_limits<T>::max(); } // change [a,b] to value void update(int a, int b, T value){ update(a, b, value, 0, 0, n); } // change k to value void update(int k, T value) { update(k, k + 1, value); } // get min value at [a, b) T query(int a, int b) { return query(a, b, 0, 0, n); } }; void solve() { int N; cin >> N; map<int, pair<int, int>> field; LazySegtree<int> seg(N); REP(i, N) { int a; cin >> a; auto it = field.find(a); if (it == field.end()) field[a] = {i, i}; field[a].second = i; } for (auto &a : field) { seg.update(a.second.first, a.second.second + 1, -(a.first)); } REP(i, N) { cout << -seg.query(i, i + 1) << " "; } }