結果
問題 | No.195 フィボナッチ数列の理解(2) |
ユーザー | kei |
提出日時 | 2018-09-18 12:15:33 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 21 ms / 5,000 ms |
コード長 | 4,240 bytes |
コンパイル時間 | 1,759 ms |
コンパイル使用メモリ | 181,308 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-07-18 07:55:29 |
合計ジャッジ時間 | 2,799 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 19 ms
5,376 KB |
testcase_03 | AC | 2 ms
5,376 KB |
testcase_04 | AC | 20 ms
5,376 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 1 ms
5,376 KB |
testcase_07 | AC | 1 ms
5,376 KB |
testcase_08 | AC | 2 ms
5,376 KB |
testcase_09 | AC | 1 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 2 ms
5,376 KB |
testcase_14 | AC | 2 ms
5,376 KB |
testcase_15 | AC | 20 ms
5,376 KB |
testcase_16 | AC | 20 ms
5,376 KB |
testcase_17 | AC | 20 ms
5,376 KB |
testcase_18 | AC | 20 ms
5,376 KB |
testcase_19 | AC | 20 ms
5,376 KB |
testcase_20 | AC | 20 ms
5,376 KB |
testcase_21 | AC | 20 ms
5,376 KB |
testcase_22 | AC | 20 ms
5,376 KB |
testcase_23 | AC | 20 ms
5,376 KB |
testcase_24 | AC | 21 ms
5,376 KB |
ソースコード
#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; const int INF = 1e9; const ll LINF = 1e18; template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; } template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; } template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; } template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; } /* <url:https://yukicoder.me/problems/no/195> 問題文============================================================ ================================================================= 解説============================================================= ================================================================ */ inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; } inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; } ll extgcd(ll a, ll b, ll& x, ll& y){ ll g = a; x = 1; y = 0; if(b!=0) { g = extgcd(b, a%b, y, x); y -= (a/b)*x;} return g; } vector<ll> fibA,fibB; pll calc1(ll i,vector<ll> v){ ll A = 1,B = LINF; ll D = v[0] - fibA[i]; if(D<=0||fibB[i]==0||D%fibB[i]!=0) return make_pair(LINF,LINF); B = D/fibB[i]; return make_pair(A, B); } pll calc2(ll i,ll j,vector<ll> v){ ll A = LINF,B = LINF; if(i == j) make_pair(LINF, LINF); if(i>j){ swap(i,j); swap(v[0],v[1]); } if(i==0&&j==1){ A = v[0]; B = v[1]; } if(i==0&&j>=2){ A = v[0]; ll D = v[1] - fibA[j]*A; if(D<=0 || D%fibB[j]!=0) return make_pair(LINF, LINF); B = D/fibB[j]; } if(i==1&&j>=2){ B = v[0]; ll D = v[1] - fibB[j]*B; if(D<=0 || D%fibA[j]!=0) return make_pair(LINF, LINF); A = D/fibA[j]; } if(i>=2&&j>=2){ ll LCM = lcm(fibA[i],fibA[j]); ll muli = LCM/fibA[i],mulj = LCM/fibA[j]; ll D1 = muli*v[0] - mulj*v[1]; ll D2 = muli*fibB[i] - mulj*fibB[j]; if(D2==0||D1%D2!=0) return make_pair(LINF, LINF); B = D1/D2; if(B<=0) return make_pair(LINF, LINF); ll D = v[1] - fibB[j]*B; if(D<=0 || D%fibA[j]!=0) return make_pair(LINF, LINF); A = D/fibA[j]; } return make_pair(A, B); } pll calc3(ll i,ll j,ll k,vector<ll> v){ ll A = LINF,B = LINF; tie(A,B) = calc2(i,j,v); if(A==LINF) return make_pair(LINF,LINF); if(v[2]!=fibA[k]*A+fibB[k]*B) return make_pair(LINF,LINF); return make_pair(A, B); } vector<ll> solve(){ vector<ll> res = {LINF,LINF}; fibA.resize(47); fibB.resize(47); fibA[0] = 1; fibA[1] = 0; fibB[0] = 0; fibB[1] = 1; for(int i = 2; i < fibA.size();i++){ fibA[i] = fibA[i-1] + fibA[i-2]; fibB[i] = fibB[i-1] + fibB[i-2];} // cout << fibA << endl; // cout << fibB << endl; ll X,Y,Z; cin >> X >> Y >> Z; vector<ll> v = {X,Y,Z}; sort(v.begin(),v.end()); v.erase(unique(v.begin(),v.end()),v.end()); for(int i = 0; i < fibA.size();i++){ if(v.size() == 1){ pll ret = calc1(i,v); res = min(res,vector<ll>{ret.first,ret.second}); continue; } for(int j = 0; j < fibA.size();j++){ if(v.size() == 2){ pll ret = calc2(i,j,v); res = min(res,vector<ll>{ret.first,ret.second}); continue; } for(int k = 0; k < fibA.size();k++){ pll ret = calc3(i,j,k,v); res = min(res,vector<ll>{ret.first,ret.second}); } } } if(res.front() == LINF) res = vector<ll>{-1}; return res; } int main(void) { cin.tie(0); ios_base::sync_with_stdio(false); cout << solve() << endl; return 0; }