結果
| 問題 |
No.229 線分上を往復する3つの動点の一致
|
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-09-24 23:03:03 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,977 bytes |
| コンパイル時間 | 1,843 ms |
| コンパイル使用メモリ | 173,820 KB |
| 実行使用メモリ | 6,944 KB |
| 最終ジャッジ日時 | 2024-09-24 17:28:06 |
| 合計ジャッジ時間 | 2,843 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 39 WA * 4 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:https://yukicoder.me/problems/no/229>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }
string solve(){
string res;
ll t1,t2,t3; cin >> t1 >> t2 >> t3;
ll X = t1*t2*t3;
vector<ll> Y1 = {(t3-t1)*t2,(t3-t1)*t2,(t3+t1)*t2,(t3-t1)*t2};
vector<ll> Y2 = {(t3-t2)*t1,(t3+t2)*t1,(t3-t2)*t1,(t3+t2)*t1};
ll maxbunbo = 0;
for(int i = 0; i < Y1.size();i++){
ll bunbo = gcd(Y1[i],Y2[i]);
maxbunbo = max(bunbo,maxbunbo);
}
ll waru = gcd(X,maxbunbo);
X /= waru;
maxbunbo /= waru;
res = to_string(X) + "/" + to_string(maxbunbo);
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei