結果
問題 | No.738 平らな農地 |
ユーザー |
|
提出日時 | 2018-09-28 23:51:25 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 110 ms / 2,000 ms |
コード長 | 2,512 bytes |
コンパイル時間 | 1,676 ms |
コンパイル使用メモリ | 159,744 KB |
実行使用メモリ | 14,088 KB |
最終ジャッジ日時 | 2024-06-13 01:41:49 |
合計ジャッジ時間 | 9,967 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 87 |
ソースコード
import std.stdio, std.array, std.string, std.conv, std.algorithm;import std.typecons, std.range, std.random, std.math, std.container;import std.numeric, std.bigint, core.bitop, std.bitmanip;immutable long INF = 1L << 59;void main() {auto s = readln.split.map!(to!int);auto N = s[0];auto K = s[1];auto A = readln.split.map!(to!long).array;if (N == 1 || K == 1) {writeln(0);return;}auto rbt_small = new RedBlackTree!(long, "a < b", true)();auto rbt_large = new RedBlackTree!(long, "a < b", true)();rbt_small.insert(-INF);rbt_large.insert(INF);long sum_small = 0;long sum_large = 0;long ans = INF;foreach (i; 0..N) {if (i >= K) {if (!rbt_small.equalRange(A[i-K]).empty) {rbt_small.removeKey(A[i-K]);sum_small -= A[i-K];} else {rbt_large.removeKey(A[i-K]);sum_large -= A[i-K];}}rbt_small.insert(A[i]);sum_small += A[i];while (rbt_small.back > rbt_large.front) {auto x = rbt_small.back;rbt_small.removeKey(x);rbt_large.insert(x);sum_small -= x;sum_large += x;}while (rbt_small.length >= rbt_large.length + 2) {auto x = rbt_small.back;rbt_small.removeKey(x);rbt_large.insert(x);sum_small -= x;sum_large += x;}while (rbt_large.length >= rbt_small.length + 2) {auto x = rbt_large.front;rbt_large.removeKey(x);rbt_small.insert(x);sum_small += x;sum_large -= x;}if (i < K - 1) {continue;}long a = rbt_small.length.to!long;long b = rbt_large.length.to!long;long mid1, mid2 = -1;if (K % 2 && rbt_small.length > rbt_large.length) {mid1 = rbt_small.back;} else if (K % 2 && rbt_large.length > rbt_small.length) {mid2 = rbt_large.front;} else {mid1 = (rbt_small.back + rbt_large.front) / 2;if ((rbt_small.back + rbt_large.front) % 2) {mid2 = mid1 + 1;}}ans = min(ans, mid1 * a - sum_small + sum_large - mid1 * b);if (mid2 >= 0) {ans = min(ans, mid2 * a - sum_small + sum_large - mid2 * b);}}ans.writeln;}