結果
| 問題 |
No.270 next_permutation (1)
|
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-10-01 22:10:30 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 22 ms / 2,000 ms |
| コード長 | 2,669 bytes |
| コンパイル時間 | 1,726 ms |
| コンパイル使用メモリ | 171,500 KB |
| 実行使用メモリ | 5,248 KB |
| 最終ジャッジ日時 | 2024-10-12 09:54:11 |
| 合計ジャッジ時間 | 3,046 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 15 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:https://yukicoder.me/problems/no/270>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
ll My_next_permutation(vector<ll>& p,vector<ll>& B,ll sum){
if(p.size() == 1) return sum;
ll i = p.size()-1;
for(;;){
ll ii = i; i--;
if(p[i] < p[ii]){
ll j = p.size();
while(!(p[i] < p[--j]));
sum -= abs(p[i] - B[i]);
sum -= abs(p[j] - B[j]);
swap(p[i],p[j]);
sum += abs(p[i] - B[i]);
sum += abs(p[j] - B[j]);
for(ll k = ii; k < p.size();k++) sum -= abs(p[k] - B[k]);
reverse(p.begin()+ii, p.end());
for(ll k = ii; k < p.size();k++) sum += abs(p[k] - B[k]);
return sum;
}
if(i == 0){
for(ll k = 0; k < p.size();k++) sum -= abs(p[k] - B[k]);
reverse(p.begin(), p.end());
for(ll k = 0; k < p.size();k++) sum += abs(p[k] - B[k]);
return sum;
}
}
return sum;
}
ll solve(){
ll res = 0;
ll N,K; cin >> N >> K;
if(K == 0) return res;
vector<ll> p(N); for(auto& in:p) cin >> in;
vector<ll> B(N); for(auto& in:B) cin >> in;
ll sum = 0;
for(int i = 0; i < N;i++) sum += abs(B[i]-p[i]);
res += sum;
for(int i = 1; i < K;i++){
sum = My_next_permutation(p,B,sum);
res += sum;
}
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei