結果
| 問題 | No.288 貯金箱の仕事 |
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-10-05 23:56:58 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,126 bytes |
| コンパイル時間 | 1,630 ms |
| コンパイル使用メモリ | 170,524 KB |
| 実行使用メモリ | 6,820 KB |
| 最終ジャッジ日時 | 2024-10-12 13:29:16 |
| 合計ジャッジ時間 | 6,581 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 16 WA * 37 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = LLONG_MAX;
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:https://yukicoder.me/problems/no/288>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
ll solve(){
ll res = LINF;
ll N,M; cin >> N >> M;
vector<ll> A(N),K(N);
for(auto& in:A) cin >> in;
for(auto& in:K) cin >> in;
ll T = 0;
for(int i = 0; i < N;i++) T += A[i]*K[i];
if(T < M) return -1;
T -= M;
ll MaxA = A[N-1];
vector<ll> min_ret(MaxA*MaxA+1,LINF);
min_ret[0] = 0;
for(int i = 0; i <= MaxA*MaxA;i++){
if(min_ret[i] == LINF) continue;
for(int j = 0; j < N;j++){
if(i+A[j]<=MaxA*MaxA){
min_ret[i+A[j]] = min(min_ret[i+A[j]],min_ret[i]+1);
}
}
}
ll C = 0;
if(T>=MaxA*MaxA){
C = (T-MaxA*MaxA)/MaxA;
T -= MaxA*C;
}
if(min_ret[T] == LINF) return -1;
res = min_ret[T] + C;
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei