結果
| 問題 |
No.335 門松宝くじ
|
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-10-19 00:37:55 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,155 bytes |
| コンパイル時間 | 2,595 ms |
| コンパイル使用メモリ | 171,592 KB |
| 実行使用メモリ | 5,248 KB |
| 最終ジャッジ日時 | 2024-11-07 17:38:59 |
| 合計ジャッジ時間 | 7,197 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 5 WA * 5 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
bool kadomatsu(int a,int b,int c){
if(b>a&&b>c)return true;
if(b<a&&b<c)return true;
return false;
}
ll solve(){
ll res(0);
int N,M; cin >> N >> M;
vector<vector<int>> E(M,vector<int>(N));
for(auto& vec:E) for(auto& in:vec) cin >> in;
ll maxv = 0;
for(int _ = 0; _ < M; _++){
ll T = 0;
const vector<int>& e = E[_];
for(int i = 0; i < N;i++){
for(int j = i+1; j < N;j++){
for(int k = j+1; k < N;k++){
if(kadomatsu(e[i], e[j], e[k]))T += max({e[i],e[j],e[k]});
}
}
}
if(T > maxv){
maxv = T;
res = _;
}
}
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei