結果
| 問題 |
No.335 門松宝くじ
|
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-10-19 01:10:02 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 404 ms / 2,000 ms |
| コード長 | 2,913 bytes |
| コンパイル時間 | 1,876 ms |
| コンパイル使用メモリ | 179,160 KB |
| 実行使用メモリ | 5,248 KB |
| 最終ジャッジ日時 | 2024-11-07 19:11:41 |
| 合計ジャッジ時間 | 5,314 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 4 |
| other | AC * 10 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
ll solve(){
ll res(0);
int N,M; cin >> N >> M;
vector<vector<int>> E(M,vector<int>(N));
for(auto& vec:E) for(auto& in:vec) cin >> in;
int maxv = 0;
for(int _ = 0; _ < M; _++){
int T = 0;
const vector<int>& e = E[_];
for(int i = 0; i < N;i++){
set<int> lsec,msec,rsec;
for(int j = 0; j < i; j++) lsec.insert(e[j]);
for(int j = i+1; j < N;j++) rsec.insert(e[j]);
for(int j = i+1; j < N;j++){
int t = 0;
rsec.erase(e[j]);
if(lsec.size()){
if(e[i] < e[j] && *lsec.rbegin() > e[i]) t = max({t,e[j],*lsec.rbegin()});
if(e[i] > e[j] && *lsec.begin() < e[i]) t = max({t,e[i]});
}
if(msec.size()){
if(*msec.rbegin()>max(e[i],e[j])) t = max(t,*msec.rbegin());
if(*msec.begin()<min(e[i],e[j])) t = max(t,max(e[i],e[j]));
}
if(rsec.size()){
if(e[i] > e[j] && *rsec.rbegin()>e[j]) t = max(t,max(e[i],*rsec.rbegin()));
if(e[i] < e[j] && *rsec.begin()<e[j]) t = max(t,e[j]);
}
T += t;
msec.insert(e[j]);
}
}
if(T > maxv){
maxv = T;
res = _;
}
}
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei