結果
| 問題 | No.206 数の積集合を求めるクエリ |
| ユーザー |
 smiken_61
|
| 提出日時 | 2018-10-31 19:07:17 |
| 言語 | C++11 (gcc 11.4.0) |
| 結果 |
AC
|
| 実行時間 | 208 ms / 7,000 ms |
| コード長 | 13,629 bytes |
| コンパイル時間 | 2,459 ms |
| コンパイル使用メモリ | 168,376 KB |
| 実行使用メモリ | 16,920 KB |
| 最終ジャッジ日時 | 2024-11-19 12:43:20 |
| 合計ジャッジ時間 | 7,474 ms |
|
ジャッジサーバーID （参考情報） |
judge5 / judge2 |
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テストケース
テストケース表示| 入力 | 結果 | 実行時間 実行使用メモリ |
|---|---|---|
| testcase_00 | AC | 63 ms
16,384 KB |
| testcase_01 | AC | 64 ms
15,944 KB |
| testcase_02 | AC | 63 ms
15,960 KB |
| testcase_03 | AC | 65 ms
16,920 KB |
| testcase_04 | AC | 63 ms
15,776 KB |
| testcase_05 | AC | 64 ms
15,656 KB |
| testcase_06 | AC | 64 ms
15,632 KB |
| testcase_07 | AC | 63 ms
15,148 KB |
| testcase_08 | AC | 64 ms
15,904 KB |
| testcase_09 | AC | 64 ms
15,520 KB |
| testcase_10 | AC | 63 ms
15,784 KB |
| testcase_11 | AC | 65 ms
16,624 KB |
| testcase_12 | AC | 69 ms
16,896 KB |
| testcase_13 | AC | 69 ms
16,684 KB |
| testcase_14 | AC | 68 ms
15,640 KB |
| testcase_15 | AC | 68 ms
16,072 KB |
| testcase_16 | AC | 67 ms
16,068 KB |
| testcase_17 | AC | 82 ms
15,500 KB |
| testcase_18 | AC | 74 ms
15,528 KB |
| testcase_19 | AC | 81 ms
15,532 KB |
| testcase_20 | AC | 73 ms
15,828 KB |
| testcase_21 | AC | 74 ms
15,396 KB |
| testcase_22 | AC | 76 ms
16,012 KB |
| testcase_23 | AC | 82 ms
15,832 KB |
| testcase_24 | AC | 208 ms
15,176 KB |
| testcase_25 | AC | 208 ms
16,668 KB |
| testcase_26 | AC | 195 ms
16,456 KB |
| testcase_27 | AC | 164 ms
15,672 KB |
| testcase_28 | AC | 199 ms
15,480 KB |
| testcase_29 | AC | 203 ms
15,812 KB |
| testcase_30 | AC | 197 ms
16,224 KB |
ソースコード
#include <bits/stdc++.h>
// #include <boost/multiprecision/cpp_int.hpp>
#define int long long
#define inf 1000000007
#define pa pair<int,int>
#define ll long long
#define pal pair<double,double>
#define ppap pair<pa,int>
// #define PI 3.14159265358979323846
#define paa pair<int,char>
#define mp make_pair
#define pb push_back
#define EPS (1e-10)
int dx[8]={0,1,0,-1,1,1,-1,-1};
int dy[8]={1,0,-1,0,-1,1,1,-1};
using namespace std;
class pa3{
public:
int x,y,z;
pa3(int x=0,int y=0,int z=0):x(x),y(y),z(z) {}
bool operator < (const pa3 &p) const{
if(x!=p.x) return x<p.x;
if(y!=p.y) return y<p.y;
return z<p.z;
//return x != p.x ? x<p.x: y<p.y;
}
bool operator > (const pa3 &p) const{
if(x!=p.x) return x>p.x;
if(y!=p.y) return y>p.y;
return z>p.z;
//return x != p.x ? x<p.x: y<p.y;
}
bool operator == (const pa3 &p) const{
return x==p.x && y==p.y && z==p.z;
}
bool operator != (const pa3 &p) const{
return !( x==p.x && y==p.y && z==p.z);
}
};
class pa4{
public:
int x;
int y,z,w;
pa4(int x=0,int y=0,int z=0,int w=0):x(x),y(y),z(z),w(w) {}
bool operator < (const pa4 &p) const{
if(x!=p.x) return x<p.x;
if(y!=p.y) return y<p.y;
if(z!=p.z)return z<p.z;
return w<p.w;
//return x != p.x ? x<p.x: y<p.y;
}
bool operator > (const pa4 &p) const{
if(x!=p.x) return x>p.x;
if(y!=p.y) return y>p.y;
if(z!=p.z)return z>p.z;
return w>p.w;
//return x != p.x ? x<p.x: y<p.y;
}
bool operator == (const pa4 &p) const{
return x==p.x && y==p.y && z==p.z &&w==p.w;
}
};
class pa2{
public:
int x,y;
pa2(int x=0,int y=0):x(x),y(y) {}
pa2 operator + (pa2 p) {return pa2(x+p.x,y+p.y);}
pa2 operator - (pa2 p) {return pa2(x-p.x,y-p.y);}
bool operator < (const pa2 &p) const{
return y != p.y ? y<p.y: x<p.x;
}
bool operator > (const pa2 &p) const{
return x != p.x ? x<p.x: y<p.y;
}
bool operator == (const pa2 &p) const{
return abs(x-p.x)==0 && abs(y-p.y)==0;
}
bool operator != (const pa2 &p) const{
return !(abs(x-p.x)==0 && abs(y-p.y)==0);
}
};
/*
class Point{
public:
double x,y;
Point(double x=0,double y=0):x(x),y(y) {}
Point operator + (Point p) {return Point(x+p.x,y+p.y);}
Point operator - (Point p) {return Point(x-p.x,y-p.y);}
Point operator * (double a) {return Point(x*a,y*a);}
Point operator / (double a) {return Point(x/a,y/a);}
double absv() {return sqrt(norm());}
double norm() {return x*x+y*y;}
bool operator < (const Point &p) const{
return x != p.x ? x<p.x: y<p.y;
}
bool operator == (const Point &p) const{
return fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;
}
};
typedef Point Vector;
#define pl pair<int,pas>
struct Segment{
Point p1,p2;
};
double dot(Vector a,Vector b){
return a.x*b.x+a.y*b.y;
}
double cross(Vector a,Vector b){
return a.x*b.y-a.y*b.x;
}
bool parareru(Point a,Point b,Point c,Point d){
// if(abs(cross(a-b,d-c))<EPS)cout<<"dd "<<cross(a-b,d-c)<<endl;
return abs(cross(a-b,d-c))<EPS;
}
double distance_ls_p(Point a, Point b, Point c) {
if ( dot(b-a, c-a) < EPS ) return (c-a).absv();
if ( dot(a-b, c-b) < EPS ) return (c-b).absv();
return abs(cross(b-a, c-a)) / (b-a).absv();
}
bool is_intersected_ls(Segment a,Segment b) {
if(a.p1==b.p1||a.p2==b.p1||a.p1==b.p2||a.p2==b.p2) return false;
if(parareru((a.p2),(a.p1),(a.p1),(b.p2))&¶reru((a.p2),(a.p1),(a.p1),(b.p1))){
// cout<<"sss"<<endl;
if(dot(a.p1-b.p1,a.p1-b.p2)<EPS) return true;
if(dot(a.p2-b.p1,a.p2-b.p2)<EPS) return true;
if(dot(a.p1-b.p1,a.p2-b.p1)<EPS) return true;
if(dot(a.p1-b.p2,a.p2-b.p2)<EPS) return true;
return false;
}
else return ( cross(a.p2-a.p1, b.p1-a.p1) * cross(a.p2-a.p1, b.p2-a.p1) < EPS ) && ( cross(b.p2-b.p1, a.p1-b.p1) * cross(b.p2-b.p1, a.p2-b.p1) < EPS );
}
double segment_dis(Segment a,Segment b){
if(is_intersected_ls(a,b))return 0;
double r=distance_ls_p(a.p1, a.p2, b.p1);
r=min(r,distance_ls_p(a.p1, a.p2, b.p2));
r=min(r,distance_ls_p(b.p1, b.p2, a.p2));
r=min(r,distance_ls_p(b.p1, b.p2, a.p1));
return r;
}
Point intersection_ls(Segment a, Segment b) {
Point ba = b.p2-b.p1;
double d1 = abs(cross(ba, a.p1-b.p1));
double d2 = abs(cross(ba, a.p2-b.p1));
double t = d1 / (d1 + d2);
return a.p1 + (a.p2-a.p1) * t;
}
*/
string itos( int i ) {
ostringstream s ;
s << i ;
return s.str() ;
}
int gcd(int v,int b){
if(v>b) return gcd(b,v);
if(v==b) return b;
if(b%v==0) return v;
return gcd(v,b%v);
}
double distans(double x1,double y1,double x2,double y2){
double rr=(x1-x2)*(x1-x2)+(y1-y2)*(y1-y2);
return sqrt(rr);
}
int mod;
int pr[500010];
int inv[500010];
int beki(int wa,int rr,int warukazu){
if(rr==0) return 1%warukazu;
if(rr==1) return wa%warukazu;
wa%=warukazu;
if(rr%2==1) return ((ll)beki(wa,rr-1,warukazu)*(ll)wa)%warukazu;
ll zx=beki(wa,rr/2,warukazu);
return (zx*zx)%warukazu;
}
double bekid(double w,int r){
if(r==0) return 1.0;
if(r==1) return w;
if(r%2) return bekid(w,r-1)*w;
double f=bekid(w,r/2);
return f*f;
}
int comb(int nn,int rr){
int r=pr[nn]*inv[rr];
r%=mod;
r*=inv[nn-rr];
r%=mod;
return r;
}
/*
void gya(int ert){
pr[0]=1;
for(int i=1;i<ert;i++){
pr[i]=(pr[i-1]*i)%mod;
}
for(int i=0;i<ert;i++) inv[i]=beki(pr[i],mod-2,mod);
}
*/
// cin.tie(0);
// ios::sync_with_stdio(false);
//priority_queue<pa3,vector<pa3>,greater<pa3>> pq;
//sort(ve.begin(),ve.end(),greater<int>());
//----------------kokomade tenpure------------
//vector<double> ans(100000000),ans2(100000000)
int D[1000000];
void fourie(int N,int d,vector<int> &vec ){// 1<<d == N
// Uは順方向ではexp(2pi*I/N)逆だとexp(-2pi*I/N)
if(N==1){
return;
}
int gyaku=0;
for(int i=1;i<N;i++){
int e=1<<(d-1);
while(gyaku&e){
gyaku^=e;
e>>=1;
}
gyaku^=e;
if(i<gyaku)swap(vec[i],vec[gyaku]);
}
for(int c=0;c<d;c++){
int f=1<<c;
for(int i=0;i<N;i+=(f<<1)){
for(int j=i;j<i+f;j++){
int A1=(vec[j]+vec[j+f]*D[(j-i)<<(d-c-1)])%998244353;
int A2=(vec[j]-(vec[j+f]*D[(j-i)<<(d-c-1)]%998244353)+998244353)%998244353;
vec[j]=A1;
vec[j+f]=A2;
}
}
}
return;
}
vector<int> FFT(vector<int> input1,vector<int> input2){
int N=1;
int d=0;
int size1=input1.size(),size2=input2.size();
while(N<size1+size2){
N*=2;
d++;
}
assert(N==(1<<d));
while(input1.size()<N)input1.pb(0);
while(input2.size()<N)input2.pb(0);
// (3^119)^(2^23)=1 mod 998244353
int g=beki(3,119,998244353);
for(int i=0;i<23-d;i++)g=(g*g)%998244353;
//cout<<" "<<beki(g,N,998244353)<<endl;
D[0]=1;
for(int i=1;i<N;i++){
D[i]=D[i-1]*g%998244353;
}
fourie(N,d,input1);
fourie(N,d,input2);
vector<int> ANS;
for(int i=0;i<N;i++)input1[i]=input1[i]*input2[i]%998244353;
for(int i=1;i<N/2;i++)swap(D[i],D[N-i]);
fourie(N,d,input1);
int ninv=beki(N,998244353-2,998244353);
for(int i=0;i<N;i++)input1[i]=input1[i]*ninv%998244353;
for(int i=0;i<N;i++){
ANS.pb(input1[i]);
}
return ANS;
}
signed main(){
cin.tie(0);
ios::sync_with_stdio(false);
int l,m,n;
cin>>l>>m>>n;
vector<int> ve1(100001,0);
vector<int> ve2(100001,0);
for(int i=0;i<l;i++){
int y;
cin>>y;
ve1[y]=1;
}
for(int i=0;i<m;i++){
int y;
cin>>y;
ve2[y]=1;
}
reverse(ve2.begin(),ve2.end());
vector<int> ve=FFT(ve1,ve2);
int q;
cin>>q;
for(int i=0;i<q;i++)cout<<ve[100000+i]<<endl;
return 0;
}