結果
| 問題 |
No.255 Splarrraaay スプラーレェーーイ
|
| コンテスト | |
| ユーザー |
omochanal
|
| 提出日時 | 2018-11-20 23:40:48 |
| 言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 4,676 bytes |
| コンパイル時間 | 1,919 ms |
| コンパイル使用メモリ | 169,856 KB |
| 実行使用メモリ | 5,248 KB |
| 最終ジャッジ日時 | 2024-12-24 15:51:28 |
| 合計ジャッジ時間 | 2,650 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 1 WA * 9 |
ソースコード
#include <bits/stdc++.h>
#define ADD(a, b) a = (a + ll(b)) % mod
#define MUL(a, b) a = (a * ll(b)) % mod
#define MAX(a, b) a = max(a, b)
#define MIN(a, b) a = min(a, b)
#define rep(i, a, b) for(int i = int(a); i < int(b); i++)
#define rer(i, a, b) for(int i = int(a) - 1; i >= int(b); i--)
#define all(a) (a).begin(), (a).end()
#define sz(v) (int)(v).size()
#define pb push_back
#define sec second
#define fst first
#define debug(fmt, ...) Debug(__LINE__, ":", fmt, ##__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<int, pi> ppi;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<vl> mat;
typedef complex<double> comp;
void Debug() {cout << '\n'; }
template<class FIRST, class... REST>void Debug(FIRST arg, REST... rest){
cout<<arg<<" ";Debug(rest...);}
template<class T>ostream& operator<<(ostream& out,const vector<T>& v) {
out<<"[";if(!v.empty()){rep(i,0,sz(v)-1)out<<v[i]<<", ";out<<v.back();}out<<"]";return out;}
template<class S, class T>ostream& operator<<(ostream& out,const pair<S, T>& v){
out<<"("<<v.first<<", "<<v.second<<")";return out;}
const int MAX_N = 300010;
const int MAX_V = 100010;
const double eps = 1e-6;
const ll mod = 1000000007;
const int inf = 1 << 30;
const ll linf = 1LL << 60;
const double PI = 3.14159265358979323846;
///////////////////////////////////////////////////////////////////////////////////////////////////
vector<ll> vx;
struct segtree { // this is piece of shit. use BIT
int n; vl sum, lazy, zero;
void init(int mx) {
n = 1;
while(n < mx) n *= 2;
sum = vl(n * 2, 0);
lazy = vl(n * 2, 0);
zero = vl(n * 2, 0);
}
segtree(int mx = 0) { init(mx); }
inline void lazy_eval(int k, int l, int r) {
int m = (l + r) / 2;
if(lazy[k]) {
sum[k * 2 + 1] += (vx[m] - vx[l]) * lazy[k];//if range_min, erase (m - l)
lazy[k * 2 + 1] += lazy[k];
sum[k * 2 + 2] += (vx[r] - vx[m]) * lazy[k];//here too
lazy[k * 2 + 2] += lazy[k];
lazy[k] = 0;
}
}
void app(int a, int b, ll s, int k, int l, int r) {
if(b <= l || r <= a) return;
if(a <= l && r <= b) {
sum[k] += (vx[r] - vx[l]) * s; //here too
lazy[k] = lazy[k] + s;
}
else {
zero[k] = 1;
lazy_eval(k, l, r);
app(a, b, s, k * 2 + 1, l, (l + r) / 2);
app(a, b, s, k * 2 + 2, (l + r) / 2, r);
sum[k] = sum[k * 2 + 1] + sum[k * 2 + 2];
}
}
void cln(int a, int b, int k, int l, int r) {
if(b <= l || r <= a) return;
if(a <= l && r <= b) {
if(zero[k]) {
cln(a, b, k * 2 + 1, l, (l + r) / 2);
cln(a, b, k * 2 + 2, (l + r) / 2, r);
}
zero[k] = 0;
sum[k] = 0; lazy[k] = 0;
}
else {
lazy_eval(k, l, r);
cln(a, b, k * 2 + 1, l, (l + r) / 2);
cln(a, b, k * 2 + 2, (l + r) / 2, r);
sum[k] = sum[k * 2 + 1] + sum[k * 2 + 2];
}
}
ll ga(int a, int b, int k, int l, int r) {
if(b <= l || r <= a) return ll();
if(a <= l && r <= b) return sum[k];
else {
lazy_eval(k, l, r);
ll lv = ga(a, b, k * 2 + 1, l, (l + r) / 2);
ll rv = ga(a, b, k * 2 + 2, (l + r) / 2, r);
return lv + rv;
}
}
void show() {
vector<ll> tmp;
rep(i, 0, n) tmp.push_back(get(i, i + 1));
debug(tmp);
}
ll get(int a, int b) { return ga(a, b, 0, 0, n); } //[a, b)
void update(int a, int b, ll s) { app(a, b, s, 0, 0, n); } //[a, b)
void clean(int a, int b) { cln(a, b, 0, 0, n); }
};
int fd(ll a) {
return lower_bound(all(vx), a) - vx.begin();
}
int N, Q;
ll X[MAX_N], L[MAX_N], R[MAX_N];
ll ans[MAX_N];
segtree seg[5];
void solve() {
cin >> N >> Q;
rep(i, 0, Q) {
cin >> X[i] >> L[i] >> R[i]; R[i]++;
vx.pb(L[i]); vx.pb(R[i]);
}
sort(all(vx)); vx.erase(unique(all(vx)), vx.end());
rep(i, 0, 5) seg[i].init(sz(vx));
// debug(vx);
rep(i, 0, Q) {
int l = fd(L[i]), r = fd(R[i]);
// debug(l, r, L[i], R[i]);
if(X[i] == 0) {
vector<ll> vec(5);
rep(j, 0, 5) vec[j] = seg[j].get(l, r);
int at = -1; ll mv = -linf;
rep(j, 0, 5) {
if(mv < vec[j]) {
at = j; mv = vec[j];
}
else if(mv == vec[j]) at = -1;
}
if(at != -1) ans[at] += vec[at];
}
else {
rep(j, 0, 5) {
if(j == X[i] - 1) seg[j].update(l, r, 1);
else seg[j].clean(l, r);
}
}
}
rep(j, 0, 5) {
ans[j] += seg[j].get(0, sz(vx));
cout << ans[j] << (j == 4 ? '\n' : ' ');
}
}
int main() {
#ifndef LOCAL
ios::sync_with_stdio(false);
cin.tie(0);
#endif
cout << fixed;
cout.precision(20);
srand((unsigned int)time(NULL));
#ifdef LOCAL
//freopen("in.txt", "wt", stdout); //for tester
freopen("in.txt", "rt", stdin);
#endif
solve();
#ifdef LOCAL
cerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";
#endif
return 0;
}
omochanal