結果
| 問題 |
No.393 2本の竹
|
| コンテスト | |
| ユーザー |
kei
|
| 提出日時 | 2018-12-01 13:54:16 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 102 ms / 1,000 ms |
| コード長 | 2,248 bytes |
| コンパイル時間 | 1,741 ms |
| コンパイル使用メモリ | 178,092 KB |
| 実行使用メモリ | 24,588 KB |
| 最終ジャッジ日時 | 2024-06-26 23:58:22 |
| 合計ジャッジ時間 | 3,203 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 28 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:https://yukicoder.me/problems/no/393>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
ll solve(){
ll res = 0;
ll n[2]; cin >> n[0] >> n[1];
ll m; cin >> m;
vector<ll> A(m); for(auto &in:A) cin >> in;
sort(A.begin(),A.end());
vector<ll> cusum(m+1);
for(int i = 0; i < m;i++) cusum[i+1] = cusum[i] + A[i];
vector<vector<int>> dp(m+1,vector<int>(n[0]+1));
dp[0][0] = true;
for(ll i = 0; i < m;i++){
for(int j = 0; j <= n[0];j++){
if(dp[i][j]){
if(j+A[i]<=n[0]){
res = max(res,i+1);
dp[i+1][j+A[i]] = true;
}
if(cusum[i]-j+A[i]<=n[1]){
res = max(res,i+1);
dp[i+1][j] = true;
}
}
}
}
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
int n; cin >> n;
while(n--){ cout << solve() << endl; }
return 0;
}
kei