結果
| 問題 |
No.407 鴨等素数間隔列の数え上げ
|
| ユーザー |
kei
|
| 提出日時 | 2018-12-02 18:34:11 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 317 ms / 1,000 ms |
| コード長 | 1,968 bytes |
| コンパイル時間 | 1,606 ms |
| コンパイル使用メモリ | 170,724 KB |
| 実行使用メモリ | 46,588 KB |
| 最終ジャッジ日時 | 2024-07-01 05:26:04 |
| 合計ジャッジ時間 | 14,257 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 5 |
| other | AC * 31 |
ソースコード
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int INF = 1e9;
const ll LINF = 1e18;
inline ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
inline ll lcm(ll a, ll b) { return a / gcd(a, b)*b; }
template<class S,class T> ostream& operator << (ostream& out,const pair<S,T>& o){ out << "(" << o.first << "," << o.second << ")"; return out; }
template<class T> ostream& operator << (ostream& out,const vector<T> V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; }
template<class T> ostream& operator << (ostream& out,const vector<vector<T> > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; }
template<class S,class T> ostream& operator << (ostream& out,const map<S,T> mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; }
/*
<url:https://yukicoder.me/problems/no/407>
問題文============================================================
=================================================================
解説=============================================================
================================================================
*/
const ll MAX_PRIME = 10000000;
vector<int> primes;
vector<int> is_prime(MAX_PRIME + 1,true);
void init_primes(){
is_prime[0] = is_prime[1] = false;
for(int i = 2; i <= MAX_PRIME;i++){
if(is_prime[i]){
primes.push_back(i);
for(int j = i*2; j <= MAX_PRIME; j+=i) is_prime[j] = false;
}
}
}
ll solve(){
init_primes();
ll res = 0;
ll N,L; cin >> N >> L;
for(auto p:primes){
res += max(L-p*(N-1)+1,0LL);
}
return res;
}
int main(void) {
cin.tie(0); ios_base::sync_with_stdio(false);
cout << solve() << endl;
return 0;
}
kei