結果

問題 No.759 悪くない忘年会にしような!
ユーザー omochanal
提出日時 2018-12-20 19:48:40
言語 C++11(廃止可能性あり)
(gcc 13.3.0)
結果
AC  
実行時間 85 ms / 2,000 ms
コード長 3,883 bytes
コンパイル時間 1,610 ms
コンパイル使用メモリ 176,744 KB
実行使用メモリ 7,948 KB
最終ジャッジ日時 2024-09-25 09:10:18
合計ジャッジ時間 5,831 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 64
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define ADD(a, b) a = (a + ll(b)) % mod
#define MUL(a, b) a = (a * ll(b)) % mod
#define MAX(a, b) a = max(a, b)
#define MIN(a, b) a = min(a, b)
#define rep(i, a, b) for(int i = int(a); i < int(b); i++)
#define rer(i, a, b) for(int i = int(a) - 1; i >= int(b); i--)
#define all(a) (a).begin(), (a).end()
#define sz(v) (int)(v).size()
#define pb push_back
#define sec second
#define fst first
#define debug(fmt, ...) Debug(__LINE__, ":", fmt, ##__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<int, pi> ppi;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<vl> mat;
typedef complex<double> comp;
void Debug() {cout << '\n'; }
template<class FIRST, class... REST>void Debug(FIRST arg, REST... rest){
cout<<arg<<" ";Debug(rest...);}
template<class T>ostream& operator<<(ostream& out,const vector<T>& v) {
out<<"[";if(!v.empty()){rep(i,0,sz(v)-1)out<<v[i]<<", ";out<<v.back();}out<<"]";return out;}
template<class S, class T>ostream& operator<<(ostream& out,const pair<S, T>& v){
out<<"("<<v.first<<", "<<v.second<<")";return out;}
const int MAX_N = 300010;
const int MAX_V = 100010;
const double eps = 1e-6;
const ll mod = 1000000007;
const int inf = 1 << 30;
const ll linf = 1LL << 60;
const double PI = 3.14159265358979323846;
///////////////////////////////////////////////////////////////////////////////////////////////////
struct T {
ll v;
T(ll v = -linf) : v(v) {}
T operator+(const T& t) { return T(max(v, t.v)); } //when getting value
void operator+=(const T& t) { v = max(v, t.v); } //when updating value
friend ostream& operator<<(ostream& out, const T& t) {
out << t.v; return out;
}
};
struct segtree { //use BIT if you can
int n; vector<T> sum, lazy;
void init(int mx) {
n = 1;
while(n < mx) n *= 2;
sum = vector<T>(n * 2);
lazy = vector<T>(n * 2);
}
segtree(int mx = 0) { init(mx); }
inline void lazy_eval(int k, int l, int r) {
if(lazy[k].v != T().v) {
sum[k * 2 + 1] += lazy[k];
lazy[k * 2 + 1] += lazy[k];
sum[k * 2 + 2] += lazy[k];
lazy[k * 2 + 2] += lazy[k];
lazy[k] = T();
}
}
void app(int a, int b, T s, int k, int l, int r) {
if(b <= l || r <= a) return;
if(a <= l && r <= b) {
sum[k] += s; //here too
lazy[k] += s;
}
else {
lazy_eval(k, l, r);
app(a, b, s, k * 2 + 1, l, (l + r) / 2);
app(a, b, s, k * 2 + 2, (l + r) / 2, r);
sum[k] = sum[k * 2 + 1] + sum[k * 2 + 2];
}
}
T ga(int a, int b, int k, int l, int r) {
if(b <= l || r <= a) return T();
if(a <= l && r <= b) return sum[k];
else {
lazy_eval(k, l, r);
T lv = ga(a, b, k * 2 + 1, l, (l + r) / 2);
T rv = ga(a, b, k * 2 + 2, (l + r) / 2, r);
return lv + rv;
}
}
void show() {
vector<T> tmp;
rep(i, 0, n) tmp.push_back(get(i, i + 1));
debug(tmp);
}
T get(int a, int b) { return ga(a, b, 0, 0, n); } //[a, b)
void update(int a, int b, T s) { app(a, b, s, 0, 0, n); } //[a, b)
};
int N;
pair<tuple<int, int, int>, int> P[MAX_N];
segtree seg;
void solve() {
cin >> N;
rep(i, 0, N) {
int a, b, c; cin >> a >> b >> c;
P[i] = make_pair(make_tuple(-a, -b, -c), i);
}
sort(P, P + N);
seg.init(10010);
vi ans;
rep(i, 0, N) {
int x = get<1>(P[i].fst) * -1;
int y = get<2>(P[i].fst) * -1;
int idx = P[i].sec;
if(seg.get(x, x + 1).v < y) {
ans.pb(idx);
seg.update(0, x + 1, T(y));
}
}
sort(all(ans));
rep(i, 0, sz(ans)) {
cout << ans[i] + 1 << "\n";
}
}
int main() {
#ifndef LOCAL
ios::sync_with_stdio(false);
cin.tie(0);
#endif
cout << fixed;
cout.precision(20);
srand((unsigned int)time(NULL));
#ifdef LOCAL
//freopen("in.txt", "wt", stdout); //for tester
freopen("in.txt", "rt", stdin);
#endif
solve();
#ifdef LOCAL
cerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";
#endif
return 0;
}
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