結果
問題 | No.8039 April Fool Tekitou |
ユーザー |
👑 |
提出日時 | 2019-01-13 07:26:21 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 1 ms / 2,000 ms |
コード長 | 4,854 bytes |
コンパイル時間 | 2,471 ms |
コンパイル使用メモリ | 160,516 KB |
実行使用メモリ | 5,248 KB |
最終ジャッジ日時 | 2024-06-13 02:43:14 |
合計ジャッジ時間 | 2,687 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
other | AC * 1 |
ソースコード
import std.conv, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.container, std.math, std.range, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken().to!int; }long readLong() { return readToken().to!long; }real readReal() { return readToken().to!real; }void chmin(T)(ref T t, in T f) { if (t > f) t = f; }void chmax(T)(ref T t, in T f) { if (t < f) t = f; }int binarySearch(T)(in T[] as, in bool delegate(T) test) { int low = -1, upp = cast(int)(as.length); for (; low + 1 < upp; ) { int mid = (low + upp)>> 1; (test(as[mid]) ? low : upp) = mid; } return upp; }int lowerBound(T)(in T[] as, in T val) { return as.binarySearch((T a) => (a < val)); }int upperBound(T)(in T[] as, in T val) { return as.binarySearch((T a) => (a <= val)); }immutable LIM = 3 * 10L^^10;immutable DATA = [24,24,4,16,80,12,32,16,24,12,96,8,32,4,96,2,48,16,4,80,24,16,16,8,48,32,8,2,48,8,16,16,12,4,48,8,60,24,8,8,48,4,8,16,16,4,64,8,12,32,8,2,160,4,96,12,12,4,64,6,8,16,16,24,72,4,8,16,10,16,32,16,12,16,8,4,64,32,16,32,48,8,12,2,192,4,8,8,48,16,4,24,16,8,32,6,24,32,16,4];int numDivisors(long n) {int ret = 1;foreach (p; smallPrimes) {if (n % p == 0) {int e;do {n /= p;++e;} while (n % p == 0);ret *= (e + 1);}}if (n > 1) {ret *= (1 + 1);}return ret;}bool check(long x) {if (!(1 <= x && x <= LIM)) {return false;}foreach (k; 0 .. DATA.length) {if (numDivisors(x + k) != DATA[k]) {return false;}}return true;}int[] smallPrimes;long[] ans;// Find primes <= lim// isComposite[k][i]: (30 (offset + k) + D[i]) is compositevoid sieve(long lim) {enum SMALL_LIM = 2 * 10^^5;enum SIEVE_LENGTH = 10^^6;enum D = [1, 7, 11, 13, 17, 19, 23, 29];enum POS = [-1, 0, -1, -1, -1, -1,-1, 1, -1, -1, -1, 2,-1, 3, -1, -1, -1, 4,-1, 5, -1, -1, -1, 6,-1, -1, -1, -1, -1, 7,];enum INV = [0, 1, 0, 0, 0, 0,0, 13, 0, 0, 0, 11,0, 7, 0, 0, 0, 23,0, 19, 0, 0, 0, 17,0, 0, 0, 0, 0, 29,];assert((cast(long)(SMALL_LIM))^^2 > lim);// int[] smallPrimes;auto isCompositeSmall = new bool[SMALL_LIM];foreach (p; 2 .. SMALL_LIM) {if (!isCompositeSmall[p]) {smallPrimes ~= p;for (int q = 2 * p; q < SMALL_LIM; q += p) {isCompositeSmall[q] = true;}}}// auto isComposite = new ubyte[SIEVE_LENGTH];auto isComposite = new ubyte[SIEVE_LENGTH + 10];for (long offset = 0; 30 * offset <= lim; offset += SIEVE_LENGTH) {stderr.writefln("30 * offset = %s", 30 * offset);isComposite[] = 0u;foreach (p; smallPrimes) {if (p > 5) {foreach (i, d; D) {long k = (((d * INV[p % 30]) % 30) * p - d) / 30;if (30 * k + d == p) {k += p;}if (k < offset) {k += (offset - k + p - 1) / p * p;}// for (k -= offset; k < SIEVE_LENGTH; k += p) {for (k -= offset; k < SIEVE_LENGTH + 10; k += p) {isComposite[cast(size_t)(k)] |= 1u << i;}}}}bool isPrime(long n) {const j = POS[cast(size_t)(n % 30)];return (j >= 0 && !((isComposite[cast(size_t)(n / 30 - offset)] >> j) & 1));}foreach (k; 0 .. SIEVE_LENGTH) {foreach (i, d; D) {//if (d != 11) continue;//if (!((isComposite[k] >> i) & 1)) {const p = 30 * (offset + k) + d;// p is 1 or prime > 5if (5 < p && p < lim) {//if (isPrime(p + 12) && isPrime(p + 36) && isPrime(p + 68)) {if (check(p - 15)) {stderr.writefln(" found p = %s", p);ans ~= p - 15;}}//}}}}}}void main() {stderr.writefln("|DATA| = %s", DATA.length);foreach (k; 0 .. DATA.length) {if (DATA[k] % 2 != 0 || DATA[k] == 2) {stderr.writefln("DATA[%s] = %s", k, DATA[k]);}}// p (= x + 21), p + 12, p + 36, p + 68 are primesforeach (d; 0 .. 30) {bool ok = true;foreach (k; 0 .. DATA.length) {int cnt;if ((d + k) % 2 == 0) ++cnt;if ((d + k) % 3 == 0) ++cnt;if ((d + k) % 5 == 0) ++cnt;ok = ok && (DATA[k] > 1 << cnt);}if (ok) {stderr.writefln("d = %s, d + 15 == %s", d, (d + 15) % 30);}}// too small or p == 11 (30)// ~ 6 minutes :(// sieve(LIM + 100);// writeln(ans);writeln(20170387916);}