結果
問題 | No.489 株に挑戦 |
ユーザー | むらため |
提出日時 | 2019-02-04 08:43:43 |
言語 | Nim (2.0.2) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,253 bytes |
コンパイル時間 | 2,759 ms |
コンパイル使用メモリ | 61,708 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-07-01 11:21:46 |
合計ジャッジ時間 | 4,549 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 43 ms
6,812 KB |
testcase_01 | WA | - |
testcase_02 | AC | 1 ms
6,944 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | WA | - |
testcase_05 | AC | 1 ms
6,940 KB |
testcase_06 | AC | 1 ms
6,940 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 1 ms
6,940 KB |
testcase_09 | AC | 2 ms
6,940 KB |
testcase_10 | AC | 2 ms
6,944 KB |
testcase_11 | AC | 2 ms
6,940 KB |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | AC | 2 ms
6,944 KB |
testcase_15 | AC | 4 ms
6,940 KB |
testcase_16 | AC | 36 ms
6,944 KB |
testcase_17 | AC | 7 ms
6,940 KB |
testcase_18 | AC | 27 ms
6,940 KB |
testcase_19 | WA | - |
testcase_20 | AC | 34 ms
6,940 KB |
testcase_21 | AC | 6 ms
6,940 KB |
testcase_22 | AC | 6 ms
6,940 KB |
testcase_23 | AC | 29 ms
6,944 KB |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | AC | 59 ms
6,944 KB |
testcase_28 | AC | 2 ms
6,944 KB |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | AC | 16 ms
6,940 KB |
testcase_32 | AC | 30 ms
6,944 KB |
testcase_33 | AC | 44 ms
6,940 KB |
testcase_34 | WA | - |
testcase_35 | AC | 18 ms
6,940 KB |
testcase_36 | AC | 4 ms
6,944 KB |
testcase_37 | AC | 15 ms
6,944 KB |
ソースコード
import sequtils,math template times*(n:int,body) = (for _ in 0..<n: body) template `max=`*(x,y) = x = max(x,y) template `min=`*(x,y) = x = min(x,y) template useSegmentTree() = # 区間[s,t)の最小(最大)値 / 更新 O(log(N)) proc minimpl[T](x,y:T): T = (if x <= y: x else: y) proc maximpl[T](x,y:T): T = (if x >= y: x else: y) type SegmentTree[T] = ref object data:seq[T] # import math n : int rawSize:int infinity: T cmp:proc(x,y:T):T proc initSegmentTree[T]( size:int, infinity:T = T(1e10), cmp: proc (x,y:T):T = minimpl[T]) : SegmentTree[T] = new(result) result.infinity = infinity result.cmp = cmp result.n = size.nextPowerOfTwo() result.rawSize = size result.data = newSeqWith(result.n * 2,result.infinity) proc `[]=`[T](self:var SegmentTree[T],i:int,val:T) = var i = i + self.n - 1 self.data[i] = val while i > 0: i = (i - 1) shr 1 self.data[i] = self.cmp(self.data[i * 2 + 1],self.data[i * 2 + 2]) proc `[]`[T](self:SegmentTree[T],slice:Slice[int]): T = proc impl(a,b,k,l,r:int):T = if r <= a or b <= l : return self.infinity if a <= l and r <= b : return self.data[k] let vl = impl(a,b,k*2+1,l,(l+r) shr 1) let vr = impl(a,b,k*2+2,(l+r) shr 1,r) return self.cmp(vl,vr) return impl(slice.a,slice.b+1,0,0,self.n) proc `$`[T](self:SegmentTree[T]): string = var arrs : seq[seq[int]] = @[] var l = 0 var r = 1 while r <= self.data.len: arrs &= self.data[l..<r] l = l * 2 + 1 r = r * 2 + 1 return $arrs useSegmentTree() proc getchar_unlocked():char {. importc:"getchar_unlocked",header: "<stdio.h>" .} proc scan(): int = while true: let k = getchar_unlocked() if k < '0': return result = 10 * result + k.ord - '0'.ord let n = scan() let d = scan() let k = scan() let S = newSeqWith(n,scan()) var smax = initSegmentTree[int](n,-1e10.int,maximpl[int]) for i in 0..<n: smax[i] = S[i] var ans = 0 var time = 0 for i in 0..<n: if i+d >= n : break let v = smax[i+1..i+d] - S[i] if v <= ans : continue ans = v time = i if ans <= 0 : quit "0",0 echo ans * k stdout.write time," " for i in time+1..<n: if S[i] == ans + S[time] : echo i quit 0