結果

問題 No.768 Tapris and Noel play the game on Treeone
ユーザー はまやんはまやんはまやんはまやん
提出日時 2019-02-23 23:11:52
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 65 ms / 2,000 ms
コード長 6,017 bytes
コンパイル時間 1,968 ms
コンパイル使用メモリ 179,592 KB
実行使用メモリ 9,960 KB
最終ジャッジ日時 2024-12-14 19:21:22
合計ジャッジ時間 5,154 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 2 ms
5,248 KB
testcase_03 AC 2 ms
5,248 KB
testcase_04 AC 2 ms
5,248 KB
testcase_05 AC 2 ms
5,248 KB
testcase_06 AC 2 ms
5,248 KB
testcase_07 AC 34 ms
7,040 KB
testcase_08 AC 18 ms
5,248 KB
testcase_09 AC 22 ms
5,632 KB
testcase_10 AC 17 ms
5,248 KB
testcase_11 AC 56 ms
9,088 KB
testcase_12 AC 60 ms
9,088 KB
testcase_13 AC 59 ms
8,832 KB
testcase_14 AC 57 ms
8,960 KB
testcase_15 AC 65 ms
9,088 KB
testcase_16 AC 62 ms
9,088 KB
testcase_17 AC 62 ms
9,344 KB
testcase_18 AC 54 ms
9,796 KB
testcase_19 AC 53 ms
9,960 KB
testcase_20 AC 59 ms
9,592 KB
testcase_21 AC 54 ms
9,224 KB
20evil_special_uni1.txt AC 61 ms
9,472 KB
20evil_special_uni2.txt AC 58 ms
9,088 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#define rep(i,a,b) for(int i=a;i<b;i++)
#define rrep(i,a,b) for(int i=a;i>=b;i--)
#define fore(i,a) for(auto &i:a)
#define all(x) (x).begin(),(x).end()
//#pragma GCC optimize ("-O3")
using namespace std; void _main(); int main() { cin.tie(0); ios::sync_with_stdio(false); _main(); }
typedef long long ll; const int inf = INT_MAX / 2; const ll infl = 1LL << 60;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a = b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a = b; return 1; } return 0; }
//---------------------------------------------------------------------------------------------------
struct Reroot {
    using T = bool;
    T def = true;
    T comp(T from, T to) {
        if (to) return false;
        return from;
    }








    int N; vector<vector<int>> E; vector<T> dp, res;
    Reroot() { }
    Reroot(int n) { N = n; E.clear(); E.resize(0); E.resize(n); }
    void add(int a, int b) { E[a].push_back(b); E[b].push_back(a); }
    vector<T> build() {
        dp.resize(N);
        res.resize(N);
        dfs1(0);
        dfs2(0);
        return res;
    }
    void dfs1(int cu, int pa = -1) {
        dp[cu] = def;
        fore(to, E[cu]) if (to != pa) {
            dfs1(to, cu);
            dp[cu] = comp(dp[cu], dp[to]);
        }
    }
    void dfs2(int cu, int pa = -1) {
        res[cu] = def;
        fore(to, E[cu]) res[cu] = comp(res[cu], dp[to]);

        int cnt = 0;
        fore(to, E[cu]) if (dp[to]) cnt++;
        T bak = dp[cu];
        fore(to, E[cu]) if (to != pa) {
            if (dp[to]) cnt--;

            if (cnt == 0) dp[cu] = true;
            else dp[cu] = false;

            dfs2(to, cu);

            if (dp[to]) cnt++;
        }
        dp[cu] = bak;

        /*int n = E[cu].size();
        vector<T> lft(n), rht(n);
        lft[0] = dp[E[cu][0]];
        rep(i, 1, n) lft[i] = comp(lft[i - 1], dp[E[cu][i]]);
        rht[n-1] = dp[E[cu][n-1]];
        rrep(i, n-2, 0) rht[i] = comp(rht[i + 1], dp[E[cu][i]]);

        T bak = dp[cu];
        rep(i, 0, n) if (E[cu][i] != pa) {
            if (n == 1) dp[cu] = def;
            else if (i == 0) dp[cu] = rht[1];
            else if (i == n - 1) dp[cu] = lft[n - 2];
            else dp[cu] = comp(lft[i - 1], rht[i + 1]);

            dfs2(E[cu][i], cu);
        }
        dp[cu] = bak;*/
    }
};
template<class V> struct BIT {
    BIT() {}  // [L, R)
    int NV;vector<V> bit;
    BIT(int n){ init(n); }
    void init(int n) { NV = 1; while (NV < n)NV *= 2; bit.resize(NV); clear(); }
    V operator[](int e) { V s = 0; e++; while (e) s += bit[e - 1], e -= e&-e; return s; }
    void add(int e, V v) { e++; while (e <= NV) bit[e - 1] += v, e += e&-e; }
    int lower_bound(V val) { 
        V tv = 0; int i, ent = 0; for (i = NV - 1; i >= 0; i--)
        if(tv+bit[ent+(1<<i)-1]<=val)tv+=bit[ent+(1<<i)-1],ent += (1 << i);return ent;
    }
    V get(int L, int R) {
        assert(0 <= L); assert(R <= NV); assert(L <= R);
        V res = 0; if(R) res += operator[](R - 1); if (L) res -= operator[](L - 1);return res;
    }
    void clear() { rep(i, 0, NV) bit[i] = 0; }
};
/*---------------------------------------------------------------------------------------------------
            ∧_∧  
      ∧_∧  (´<_` )  Welcome to My Coding Space!
     ( ´_ゝ`) /  ⌒i     
    /   \     | |     
    /   / ̄ ̄ ̄ ̄/  |  
  __(__ニつ/     _/ .| .|____  
     \/____/ (u ⊃  
---------------------------------------------------------------------------------------------------*/






//---------------------------------------------------------------------------------------------------
/*void solve(TreeDiameter &td, HLDecomposition &hld, int N, vector<ll> &dist) {
    rep(i, 0, N) {
        ll d = -1;
        if (td.dia % 2 == 0) {
            chmax(d, (ll)hld.distance(i, td.leaf_even[0]));
            chmax(d, (ll)hld.distance(i, td.leaf_even[1]));
        }
        else {
            chmax(d, (ll)hld.distance(i, td.leaf_odd.first[0]));
            chmax(d, (ll)hld.distance(i, td.leaf_odd.second[0]));
        }
        dist[i] = d;
    }
}*/
//---------------------------------------------------------------------------------------------------
void _main() {
    /*int N, M;

    cin >> N;
    TreeDiameter td1; td1.init(N);
    HLDecomposition hld1; hld1.init(N);
    rep(i, 0, N - 1) {
        int a, b; cin >> a >> b;
        a--; b--;
        td1.add_edge(a, b);
        hld1.add(a, b);
    }
    td1.build();
    hld1.build();

    cin >> M;
    TreeDiameter td2; td2.init(M);
    HLDecomposition hld2; hld2.init(M);
    rep(i, 0, M - 1) {
        int a, b; cin >> a >> b;
        a--; b--;
        td2.add_edge(a, b);
        hld2.add(a, b);
    }
    td2.build();
    hld2.build();

    ll ma = -1;
    chmax(ma, 1LL * td1.dia);
    chmax(ma, 1LL * td2.dia);

    vector<ll> dist1(N), dist2(M);
    solve(td1, hld1, N, dist1);
    solve(td2, hld2, M, dist2);

    BIT<ll> bit1(101010), bit2(101010);
    rep(i, 0, N) bit1.add(dist1[i], 1);
    rep(i, 0, M) bit2.add(dist2[i], 1);
    ll other = 0;

    ll ans = 0;
    rep(i, 0, N) {
        ll ng = 0;
        if(0 <= ma - dist1[i]) ng = bit2.get(0, ma - dist1[i]);
        other += ng;
        ans += dist1[i] * (M - ng);
    }
    rep(i, 0, M) {
        ll ng = 0;
        if (0 <= ma - dist2[i]) ng = bit1.get(0, ma - dist2[i]);
        other += ng;
        ans += dist2[i] * (N - ng);
    }
    ans += ma * other / 2;
    ans += 1LL * (1LL * N * M - other / 2);
    cout << ans << endl;*/

    int N;
    cin >> N;
    Reroot rr(N);
    rep(i, 0, N - 1) {
        int a, b; cin >> a >> b;
        a--; b--;
        rr.add(a, b);
    }
    auto dp = rr.build();
    vector<int> ans;

    rep(i, 0, N) if (dp[i]) ans.push_back(i);
    int n = ans.size();
    printf("%d\n", n);
    fore(i, ans) printf("%d\n", i + 1);
}
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