結果

問題 No.703 ゴミ拾い Easy
ユーザー azbrugby
提出日時 2019-03-16 18:07:46
言語 C++11
(gcc 13.3.0)
結果
AC  
実行時間 108 ms / 1,500 ms
コード長 2,050 bytes
コンパイル時間 974 ms
コンパイル使用メモリ 90,080 KB
実行使用メモリ 13,292 KB
最終ジャッジ日時 2025-01-02 14:07:35
合計ジャッジ時間 5,380 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
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ファイルパターン 結果
sample AC * 4
other AC * 46
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:72:45: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘ll*’ {aka ‘long long int*’} [-Wformat=]
   72 |         for (int i = 1; i <= n; i++)scanf("%d", a + i);
      |                                            ~^   ~~~~~
      |                                             |     |
      |                                             int*  ll* {aka long long int*}
      |                                            %lld
main.cpp:73:45: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘long long int*’ [-Wformat=]
   73 |         for (int i = 1; i <= n; i++)scanf("%d", &xy[i].first);
      |                                            ~^   ~~~~~~~~~~~~
      |                                             |   |
      |                                             |   long long int*
      |                                             int*
      |                                            %lld
main.cpp:74:45: warning: format ‘%d’ expects argument of type ‘int*’, but argument 2 has type ‘long long int*’ [-Wformat=]
   74 |         for (int i = 1; i <= n; i++)scanf("%d", &xy[i].second);
      |                                            ~^   ~~~~~~~~~~~~~
      |                                             |   |
      |                                             |   long long int*
      |                                             int*
      |                                            %lld
main.cpp:72:42: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   72 |         for (int i = 1; i <= n; i++)scanf("%d", a + i);
      |                                     ~~~~~^~~~~~~~~~~~~
main.cpp:73:42: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
   73 |         for

ソースコード

diff # 

#include <iostream>
#include <algorithm>
#include <cstring>
#include <sstream>
#include <map>
#include <queue>
#include <set>
#include <vector>
#include <stack>
#include <cstdio>
#include <cmath>
#include <bitset>
#define mk make_pair
#define pb push_back
using namespace std;
typedef long long int ll;
typedef pair<ll, ll> pos;

const ll MOD = 1234567, N = 300010, dx[4] = { -1,1,0,0 }, dy[4] = { 0,0,-1,1 }, MIN = -72340172838, MAX = 72340172838;
const int S = 60;
ll mn(ll a, ll b) {
	if (a == -1)return b;
	if (b == -1)return a;
	return min(a, b);
}
static ll gcd(ll v1, ll v2) {
	if (v1 == 0)return v2; if (v2 == 0)return v1; if (v2 > v1)return gcd(v2%v1, v1); return gcd(v1%v2, v2);
}

ll pw(ll v1, ll v2) {
	ll v3 = 1;
	while (v2 > 0) {
		if (v2 % 2)v3 = (v3*v1) % MOD;
		v1 = (v1*v1) % MOD;
		v2 /= 2;
	}
	return v3;
}

ll n, a[N],dp[N];
pos xy[N];

struct ConvexHullTrick {
	std::deque<std::pair<long long, long long> > dq; //（傾き、切片）

	void add(long long a, long long b) {
		std::pair<long long, long long> p0 = std::make_pair(a, b);
		while (dq.size() >= 2) {
			int sz = dq.size();
			std::pair<long long, long long> p1 = dq[sz - 1];
			std::pair<long long, long long> p2 = dq[sz - 2];
			if ((p0.second - p1.second)*(p0.first - p2.first) < (p0.second - p2.second)*(p0.first - p1.first))break;//交点のx座標を比較
			dq.pop_back();
		}
		dq.push_back(p0);
	}

	long long query(long long x) {
		while (dq.size() >= 2) {
			long long v1 = dq[0].first*x + dq[0].second;
			long long v2 = dq[1].first*x + dq[1].second;
			if (v1 <= v2)break;
			dq.pop_front();
		}
		return dq[0].first*x + dq[0].second;
	}

};
ConvexHullTrick cht;
int main() {
	cin >> n;
	for (int i = 1; i <= n; i++)scanf("%d", a + i);
	for (int i = 1; i <= n; i++)scanf("%d", &xy[i].first);
	for (int i = 1; i <= n; i++)scanf("%d", &xy[i].second);
	for (int i = 1; i <= n; i++) {
		cht.add(-2*xy[i].first, dp[i - 1] + xy[i].first*xy[i].first + xy[i].second*xy[i].second);
		dp[i] = a[i] * a[i] + cht.query(a[i]);
	}
	cout << dp[n] << endl;
	return 0;
}
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