結果
問題 | No.802 だいたい等差数列 |
ユーザー |
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提出日時 | 2019-03-18 06:43:37 |
言語 | C++11 (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 85 ms / 2,000 ms |
コード長 | 2,873 bytes |
コンパイル時間 | 1,411 ms |
コンパイル使用メモリ | 161,612 KB |
実行使用メモリ | 36,376 KB |
最終ジャッジ日時 | 2024-07-16 01:33:15 |
合計ジャッジ時間 | 5,121 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 30 |
ソースコード
#include <bits/stdc++.h>#define ADD(a, b) a = (a + ll(b)) % mod#define MUL(a, b) a = (a * ll(b)) % mod#define MAX(a, b) a = max(a, b)#define MIN(a, b) a = min(a, b)#define rep(i, a, b) for(int i = int(a); i < int(b); i++)#define rer(i, a, b) for(int i = int(a) - 1; i >= int(b); i--)#define all(a) (a).begin(), (a).end()#define sz(v) (int)(v).size()#define pb push_back#define sec second#define fst first#define debug(fmt, ...) Debug(__LINE__, ":", fmt, ##__VA_ARGS__)using namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair<int, int> pi;typedef pair<ll, ll> pl;typedef pair<int, pi> ppi;typedef vector<int> vi;typedef vector<ll> vl;typedef vector<vl> mat;typedef complex<double> comp;void Debug() {cout << '\n'; }template<class FIRST, class... REST>void Debug(FIRST arg, REST... rest){cout<<arg<<" ";Debug(rest...);}template<class T>ostream& operator<<(ostream& out,const vector<T>& v) {out<<"[";if(!v.empty()){rep(i,0,sz(v)-1)out<<v[i]<<", ";out<<v.back();}out<<"]";return out;}template<class S, class T>ostream& operator<<(ostream& out,const pair<S, T>& v){out<<"("<<v.first<<", "<<v.second<<")";return out;}const int MAX_N = 1400010;const int MAX_V = 100010;const double eps = 1e-6;const ll mod = 1000000007;const int inf = 1 << 30;const ll linf = 1LL << 60;const double PI = 3.14159265358979323846;///////////////////////////////////////////////////////////////////////////////////////////////////ll fac[MAX_N], inv[MAX_N], fiv[MAX_N]; //fiv:inv(fac(i))ll mod_pow(ll a, ll n) {if(n == 0) return 1;ll res = mod_pow(a, n / 2);if(n % 2 == 0) return res * res % mod;else return a * res % mod * res % mod;}ll invf(ll a) {return mod_pow(a, mod - 2);}void C_init(int n) {fac[0] = fac[1] = 1; inv[1] = 1;fiv[0] = fiv[1] = 1;rep(i, 2, n + 1) {fac[i] = fac[i - 1] * i % mod;inv[i] = mod - inv[mod % i] * (mod / i) % mod;fiv[i] = fiv[i - 1] * inv[i] % mod;}}ll C(int a, int b) { //assume a >= bif(a < b || a < 0 || b < 0) return 0;return fac[a] * fiv[b] % mod * fiv[a - b] % mod;}int N, M, L, R;void solve() {cin >> N >> M >> L >> R;C_init(1400000);ll O = M - 1ll * (N - 1) * L - 1;if(O < 0) {cout << 0 << "\n"; return;}ll res = 0;rep(p, 0, N) {ll l = O - 1ll * p * (R - L + 1);if(l < 0) continue;if(p % 2 == 0) {ADD(res, C(N - 1, p) * C(l + N, N) % mod);}else {ADD(res, mod - C(N - 1, p) * C(l + N, N) % mod);}}cout << res << "\n";}int main() {#ifndef LOCALios::sync_with_stdio(false);cin.tie(0);#endifcout << fixed;cout.precision(20);srand((unsigned int)time(NULL));#ifdef LOCAL//freopen("in.txt", "wt", stdout); //for testerfreopen("in.txt", "rt", stdin);#endifsolve();#ifdef LOCALcerr << "Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";#endifreturn 0;}