結果

問題 No.807 umg tours
ユーザー ikdikd
提出日時 2019-03-22 22:49:57
言語 Nim
(2.0.2)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 4,005 bytes
コンパイル時間 5,102 ms
コンパイル使用メモリ 69,644 KB
実行使用メモリ 68,480 KB
最終ジャッジ日時 2024-05-02 23:30:02
合計ジャッジ時間 17,726 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
13,892 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 2 ms
6,820 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,940 KB
testcase_05 AC 2 ms
6,944 KB
testcase_06 AC 2 ms
6,940 KB
testcase_07 AC 2 ms
6,944 KB
testcase_08 AC 1 ms
6,940 KB
testcase_09 AC 2 ms
6,940 KB
testcase_10 AC 1 ms
6,944 KB
testcase_11 AC 486 ms
30,796 KB
testcase_12 AC 461 ms
44,032 KB
testcase_13 AC 491 ms
36,608 KB
testcase_14 AC 236 ms
22,528 KB
testcase_15 AC 209 ms
17,792 KB
testcase_16 AC 614 ms
51,968 KB
testcase_17 AC 1,093 ms
68,480 KB
testcase_18 AC 821 ms
55,168 KB
testcase_19 AC 676 ms
46,464 KB
testcase_20 AC 292 ms
19,840 KB
testcase_21 AC 292 ms
20,480 KB
testcase_22 AC 120 ms
10,624 KB
testcase_23 AC 95 ms
8,960 KB
testcase_24 TLE -
testcase_25 -- -
権限があれば一括ダウンロードができます

ソースコード

diff # 

type HeapQueue*[T] = distinct seq[T]

proc newHeapQueue*[T](): HeapQueue[T] {.inline.} = HeapQueue[T](newSeq[T]())
proc newHeapQueue*[T](h: var HeapQueue[T]) {.inline.} = h = HeapQueue[T](
    newSeq[T]())

proc len*[T](h: HeapQueue[T]): int {.inline.} = seq[T](h).len
proc `[]`*[T](h: HeapQueue[T], i: int): T {.inline.} = seq[T](h)[i]
proc `[]=`[T](h: var HeapQueue[T], i: int,
  v: T) {.inline.} = seq[T](h)[i] = v
proc add[T](h: var HeapQueue[T], v: T) {.inline.} = seq[T](h).add(v)

proc heapCmp[T](x, y: T): bool {.inline.} =
    return (x < y)

# 'heap' is a heap at all indices >= startpos, except possibly for pos.  pos
# is the index of a leaf with a possibly out-of-order value.  Restore the
# heap invariant.
proc siftdown[T](heap: var HeapQueue[T], startpos, p: int) =
    var pos = p
    var newitem = heap[pos]
    # Follow the path to the root, moving parents down until finding a place
# newitem fits.
    while pos > startpos:
        let parentpos = (pos - 1) shr 1
        let parent = heap[parentpos]
        if heapCmp(newitem, parent):
            heap[pos] = parent
            pos = parentpos
        else:
            break
    heap[pos] = newitem

proc siftup[T](heap: var HeapQueue[T], p: int) =
    let endpos = len(heap)
    var pos = p
    let startpos = pos
    let newitem = heap[pos]
    # Bubble up the smaller child until hitting a leaf.
    var childpos = 2*pos + 1  # leftmost child position
    while childpos < endpos:
        # Set childpos to index of smaller child.
        let rightpos = childpos + 1
        if rightpos < endpos and not heapCmp(heap[childpos], heap[rightpos]):
            childpos = rightpos
        # Move the smaller child up.
        heap[pos] = heap[childpos]
        pos = childpos
        childpos = 2*pos + 1
    # The leaf at pos is empty now.  Put newitem there, and bubble it up
# to its final resting place (by sifting its parents down).
    heap[pos] = newitem
    siftdown(heap, startpos, pos)

proc push*[T](heap: var HeapQueue[T], item: T) =
    ## Push item onto heap, maintaining the heap invariant.
    (seq[T](heap)).add(item)
    siftdown(heap, 0, len(heap)-1)

proc pop*[T](heap: var HeapQueue[T]): T =
    ## Pop the smallest item off the heap, maintaining the heap invariant.
    let lastelt = seq[T](heap).pop()
    if heap.len > 0:
        result = heap[0]
        heap[0] = lastelt
        siftup(heap, 0)
    else:
        result = lastelt

# https://github.com/nim-lang/Nim/blob/master/lib/pure/collections/heapqueue.nim
# ---------------------------------------------------------------------------------------------- #
# ---------------------------------------------------------------------------------------------- #

import strutils, sequtils, math

proc `<`[T](a, b: T): bool {.inline.} =
    return a.dist < b.dist

proc main() =
    let
        nm = stdin.readLine.strip.split.map(parseInt)
        (n, m) = (nm[0], nm[1])
        abci = (0..<m).mapIt(stdin.readLine.strip.split.map(parseInt))

    type Edge = object
        to: int
        cost: int64
    var g = newSeqWith(n, newSeq[Edge]())
    for abc in abci:
        g[abc[0] - 1].add(Edge(to: abc[1] - 1, cost: abc[2]))
        g[abc[1] - 1].add(Edge(to: abc[0] - 1, cost: abc[2]))
    type T = object
        node: int
        dist: int64
        used: int
    var
        q = newHeapQueue[T]()
        dist = newSeqWith(n, newSeqWith(2, 100000000000000000))
    dist[0][0] = 0
    dist[0][1] = 0
    q.add(T(node: 0, dist: 0, used: 0))
    while q.len > 0:
        let cur = q.pop
        for e in g[cur.node]:
            if cur.dist + e.cost < dist[e.to][cur.used]:
                dist[e.to][cur.used] = cur.dist + e.cost
                q.add(T(node: e.to,
        dist: dist[e.to][cur.used],
         used: cur.used))
            if (cur.used == 0) and (cur.dist < dist[e.to][1]):
                dist[e.to][1] = cur.dist
                q.add(T(node: e.to, dist: dist[e.to][1], used: 1))
    for i in 0..<n:
        echo dist[i].sum

main()
0