結果
問題 | No.803 Very Limited Xor Subset |
ユーザー |
|
提出日時 | 2019-03-23 20:37:50 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 3 ms / 2,000 ms |
コード長 | 3,251 bytes |
コンパイル時間 | 1,339 ms |
コンパイル使用メモリ | 120,648 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-09-24 17:54:29 |
合計ジャッジ時間 | 2,755 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 43 |
ソースコード
// includes#include <cstdio>#include <cstdint>#include <iostream>#include <iomanip>#include <string>#include <queue>#include <stack>#include <vector>#include <set>#include <map>#include <unordered_map>#include <algorithm>#include <utility>#include <functional>#include <cmath>#include <climits>#include <bitset>#include <list>#include <random>// macros#define ll long long int#define pb emplace_back#define mk make_pair#define pq priority_queue#define FOR(i, a, b) for(int i=(a);i<(b);++i)#define rep(i, n) FOR(i, 0, n)#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)#define all(x) (x).begin(),(x).end()#define sz(x) ((int)(x).size())#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())using namespace std;// typestypedef pair<int, int> P;typedef pair<ll, int> Pl;typedef pair<ll, ll> Pll;typedef pair<double, double> Pd;// constantsconst int inf = 1e9;const ll linf = 1LL << 50;const double EPS = 1e-10;const int mod = 1e9 + 7;// solvetemplate <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}template <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}const int MAX_H = 510, MAX_W = 510;struct MatrixB {int H, W;bitset<MAX_W> val[MAX_H];MatrixB(int m = 1, int n = 1): H(m), W(n){}inline bitset<MAX_W>& operator[](size_t i){return val[i];}int gauss_jordan(bool is_extended = false){int rank = 0;for(int col = 0; col < W; col++){if(col == W - 1 && is_extended)break;int pivot = -1;for(int row = rank; row < H; row++){if(val[row][col]){pivot = row;break;}}if(pivot == -1)continue;swap(val[pivot], val[rank]);for(int row = 0; row < H; row++){if(row != rank && val[row][col])val[row] ^= val[rank];}rank++;}return rank;}};int linear_eq(MatrixB &A, vector<int> b, vector<int> & res){int m = A.H, n = A.W;MatrixB M(m, n + 1);for(int i = 0; i < m; i++){for(int j = 0; j < n; j++){M[i][j] = A[i][j];}M[i][n] = b[i];}int rank = M.gauss_jordan(true);for(int row = rank; row < m; row++){if(M[row][n])return -1;}res.assign(n, 0);for(int i = 0; i < rank; i++)res[i] = M[i][n];return rank;}template <typename T>T power(T a, T n, T mod) {T res = 1;T tmp = n;T curr = a;while(tmp){if(tmp % 2 == 1){res = (T)((ll)res * curr % mod);}curr = (T)((ll)curr * curr % mod);tmp >>= 1;}return res;}int main(int argc, char const* argv[]){ios_base::sync_with_stdio(false);cin.tie(0);int n, m;ll X;cin >> n >> m >> X;vector<ll> a(n);rep(i, n)cin >> a[i];MatrixB M(30 + m, n);for(int i = 0; i < n; i++){for(int j = 0; j < 30; j++){M[j][i] = (a[i] >> j) % 2;}}vector<int> vec(30 + m);for(int i = 0; i < 30; i++)vec[i] = (X >> i) % 2;rep(i, m){int x = 0;cin >> x;int l, r;cin >> l >> r, l--, r--;for(int j = l; j <= r; j++)M[30+i][j] = 1;vec[30+i] = x;}vector<int> res;int rank = linear_eq(M, vec, res);if(rank == -1)cout << 0 << endl;else cout << power<ll>(2, n - rank, mod) << endl;return 0;}