結果

問題 No.3045 怪文書
ユーザー HaarHaar
提出日時 2019-04-01 22:06:10
言語 C++14
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,153 bytes
コンパイル時間 1,547 ms
コンパイル使用メモリ 169,892 KB
実行使用メモリ 4,384 KB
最終ジャッジ日時 2023-08-18 01:13:05
合計ジャッジ時間 2,562 ms
ジャッジサーバーID
（参考情報） 		judge12 / judge13
このコードへのチャレンジ（β）

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,376 KB
testcase_01 AC 2 ms
4,380 KB
testcase_02 AC 1 ms
4,380 KB
testcase_03 AC 2 ms
4,376 KB
testcase_04 AC 2 ms
4,380 KB
testcase_05 AC 1 ms
4,384 KB
testcase_06 AC 1 ms
4,384 KB
testcase_07 AC 3 ms
4,380 KB
testcase_08 AC 2 ms
4,384 KB
testcase_09 AC 2 ms
4,376 KB
testcase_10 AC 2 ms
4,380 KB
testcase_11 AC 1 ms
4,380 KB
testcase_12 AC 2 ms
4,376 KB
testcase_13 AC 1 ms
4,380 KB
testcase_14 AC 2 ms
4,376 KB
testcase_15 AC 2 ms
4,380 KB
testcase_16 AC 2 ms
4,384 KB
testcase_17 AC 1 ms
4,376 KB
testcase_18 AC 1 ms
4,380 KB
testcase_19 AC 2 ms
4,376 KB
testcase_20 AC 1 ms
4,380 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
#define FOR(v, a, b) for(int v = (a); v < (b); ++v)
#define FORE(v, a, b) for(int v = (a); v <= (b); ++v)
#define REP(v, n) FOR(v, 0, n)
#define REPE(v, n) FORE(v, 0, n)
#define REV(v, a, b) for(int v = (a); v >= (b); --v)
#define ALL(x) (x).begin(), (x).end()
#define ITR(it, c) for(auto it = (c).begin(); it != (c).end(); ++it)
#define RITR(it, c) for(auto it = (c).rbegin(); it != (c).rend(); ++it)
#define EXIST(c,x) ((c).find(x) != (c).end())
#define LLI long long int
#define fst first
#define snd second

#ifdef DEBUG
#include <misc/C++/Debug.cpp>
#else
#define dump(x)
#endif

#define gcd __gcd

using namespace std;
template <class T> constexpr T lcm(T m, T n){return m/gcd(m,n)*n;}

template <typename I> void join(ostream &ost, I s, I t, string d=" "){for(auto i=s; i!=t; ++i){if(i!=s)ost<<d; ost<<*i;}ost<<endl;}
template <typename T> istream& operator>>(istream &is, vector<T> &v){for(auto &a : v) is >> a; return is;}
template <typename T, typename U> istream& operator>>(istream &is, pair<T,U> &p){is >> p.first >> p.second; return is;}

template <typename T, typename U> T& chmin(T &a, const U &b){return a = (a<=b?a:b);}
template <typename T, typename U> T& chmax(T &a, const U &b){return a = (a>=b?a:b);}
template <typename T, size_t N, typename U> void fill_array(T (&a)[N], const U &v){fill((U*)a, (U*)(a+N), v);}

const string S[41] = {
  "ABCDEFGHIJKLMNOPQRSTUVWXZ",
  "ABCDEFGHIJKLMNPQRSTVWXYZ", 
  "BCDEFGHIJKLMNOPQSTUVWXYZ", 
  "ABCDFGHIJKLMNOPQRSTUVWXYZ",
  "ABCDEFHJKLMNOPQRSTUWXYZ",  
  "ABCDFGHIJKLMOPQRSTUVWXYZ",
  "ABCDEFGHIJKLMNOPQRSUVXYZ", 
  "ABCDEFGHIJKLMNPQRSTUVWXYZ",
  "ABCDEFGHJKLMOPQRSUVWXYZ", 
  "ABCDFHIJKLMNOPQRSTUVWXYZ", 
  "ABCDFGHIJKLMNOPQTUVWXYZ",
  "ABCDEFGHIJKLMOPQRSTUVWXYZ",
  "BCDEFGHIJKLMOPQRSTUVWXYZ", 
  "ABCEFGHIJKLMNOPQRSTUVWXYZ",
  "ABCDEFGHIJKLNOPQRSTUVWXYZ",
  "ABCDEFGHIJKLMNOPQRSTUVWXZ",
  "ABCDEFGHIJKLMNPQRSTVWXYZ",
  "ABCDEFGHIJKLMNOPQSTUVWXYZ",
  "ABCDEFGHIJKLMNOPQRSUVWXYZ",
  "BCDEFGHIJKLMNOPQRTUVWXYZ",
  "ABCDEFGHIJLMNOPQRSTUVWXYZ",
  "ABCDEFGHJKLMNOPQRTUVWXYZ",
  "ABCDEFGHIJKLMNOPQRSUVWXYZ",
  "ABCDEFGHIJKLMNPQRSTUVWXYZ",
  "ABCDEGHJKLMOPQRSTUVWXYZ",
  "ABCEFGHIJKLMNOPQRSTUVWXYZ",
  "ABCDEFGHIJKLMNOPQRSUVWXYZ",
  "ABCDEFGIJKLMNOPQRSTUVWXYZ",
  "ABCDFGHIJKLMNOPQRSTUVWXYZ",
  "ABCDEGHIJKLMNOPQRSTUVWXYZ",
  "BDEFGHIJKLMNOPQRSUVWXYZ",
  "ABCDEFGHIJKLMNPQSTUVWXYZ",
  "ABCDEFGHJKLMNOPQRSTUVWXYZ",
  "BCDEFGHIJKMNOPQRSTUVWXYZ",
  "ABCDEFGHIJKLMNPQRSTUVWXYZ", 
  "ABCDEGHIJKLMNOPQRSTUVWXYZ",
  "ABCDEFGHIJKLMOPQRSTUVWXYZ",
  "ABCDEFGHIJKLNPQRSTUVWXYZ",
  "ABCEFGHIJKLMNOPQRSTVWXYZ",
  "ABCDEFGHIJKMNPQRSTUVWXYZ",
  "ABCDEFGHIJKLNOPQRSTUVWXYZ"
};

template <typename T> LLI factorial(T n, T m){LLI k = 1LL; FORE(i,1,n) k = (k*i) % m; return k;}

int main(){
  cin.tie(0);
  ios::sync_with_stdio(false);

  REP(i,41){
    string s = S[i];
    string t;

    vector<bool> e(26,false);
    for(auto c : s) e[c-'A'] = true;

    REP(j,26) if(not e[j]) t.push_back(j+'A');

    cerr << t;
  }
  cerr << endl;

  LLI n,m;
  while(cin >> n >> m){
    LLI ans;

    if(n > m) ans = 0;
    else ans = factorial(n,m);
    
    cout << ans << endl;
  }
  
  return 0;
}
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