結果

問題 No.229 線分上を往復する3つの動点の一致
ユーザー shimomireshimomire
提出日時 2015-06-20 02:45:44
言語 C++11
(gcc 11.4.0)
結果
AC  
実行時間 2 ms / 5,000 ms
コード長 5,907 bytes
コンパイル時間 1,158 ms
コンパイル使用メモリ 117,096 KB
実行使用メモリ 4,384 KB
最終ジャッジ日時 2023-09-21 10:30:53
合計ジャッジ時間 2,424 ms
ジャッジサーバーID
（参考情報） 		judge14 / judge13
このコードへのチャレンジ（β）

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,376 KB
testcase_01 AC 1 ms
4,376 KB
testcase_02 AC 1 ms
4,384 KB
testcase_03 AC 2 ms
4,380 KB
testcase_04 AC 2 ms
4,380 KB
testcase_05 AC 1 ms
4,376 KB
testcase_06 AC 2 ms
4,380 KB
testcase_07 AC 1 ms
4,380 KB
testcase_08 AC 1 ms
4,376 KB
testcase_09 AC 2 ms
4,380 KB
testcase_10 AC 1 ms
4,376 KB
testcase_11 AC 1 ms
4,380 KB
testcase_12 AC 1 ms
4,376 KB
testcase_13 AC 2 ms
4,376 KB
testcase_14 AC 1 ms
4,380 KB
testcase_15 AC 1 ms
4,380 KB
testcase_16 AC 2 ms
4,384 KB
testcase_17 AC 1 ms
4,376 KB
testcase_18 AC 1 ms
4,380 KB
testcase_19 AC 2 ms
4,376 KB
testcase_20 AC 1 ms
4,380 KB
testcase_21 AC 2 ms
4,376 KB
testcase_22 AC 1 ms
4,380 KB
testcase_23 AC 2 ms
4,376 KB
testcase_24 AC 1 ms
4,376 KB
testcase_25 AC 1 ms
4,380 KB
testcase_26 AC 1 ms
4,376 KB
testcase_27 AC 2 ms
4,380 KB
testcase_28 AC 2 ms
4,376 KB
testcase_29 AC 1 ms
4,376 KB
testcase_30 AC 2 ms
4,380 KB
testcase_31 AC 1 ms
4,376 KB
testcase_32 AC 2 ms
4,380 KB
testcase_33 AC 2 ms
4,380 KB
testcase_34 AC 1 ms
4,380 KB
testcase_35 AC 2 ms
4,380 KB
testcase_36 AC 1 ms
4,376 KB
testcase_37 AC 1 ms
4,376 KB
testcase_38 AC 1 ms
4,376 KB
testcase_39 AC 1 ms
4,380 KB
testcase_40 AC 1 ms
4,376 KB
testcase_41 AC 1 ms
4,376 KB
testcase_42 AC 2 ms
4,380 KB
testcase_43 AC 1 ms
4,380 KB
testcase_44 AC 1 ms
4,380 KB
testcase_45 AC 2 ms
4,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <cassert>// c
#include <iostream>// io
#include <iomanip>
#include <fstream>
#include <sstream>
#include <vector>// container
#include <map>
#include <set>
#include <queue>
#include <bitset>
#include <stack>
#include <algorithm>// other
#include <complex>
#include <numeric>
#include <functional>
#include <random>
#include <regex>
using namespace std;

typedef long long ll;typedef unsigned long long ull;typedef long double ld;

#define ALL(c) c.begin(),c.end()
#define IN(l,v,r) (l<=v && v < r)
template<class T> void UNIQUE(T v){v.erase(unique(ALL(v)),v.end());}
//debug
#define DUMP(x) cerr << #x <<" = " << (x)
#define LINE() cerr<< " (L" << __LINE__ << ")"

struct range{
    struct Iter{
        int v,step;
        Iter& operator++(){v+=step;return *this;}
        bool operator!=(Iter& itr){return v<itr.v;}
        int& operator*(){return v;}
    };
    Iter i, n;
    range(int i, int n,int step):i({i,step}), n({n,step}){}
    range(int i, int n):range(i,n,1){}
    range(int n):range(0,n){}
    Iter& begin(){return i;}
    Iter& end(){return n;}
};
struct rrange{
    struct Iter{
        int v,step;
        Iter& operator++(){v-=step;return *this;}
        bool operator!=(Iter& itr){return v>itr.v;}
        int& operator*(){return v;}
    };
    Iter i, n;
    rrange(int i, int n,int step):i({i-1,step}), n({n-1,step}){}
    rrange(int i, int n):rrange(i,n,1){}
    rrange(int n) :rrange(0,n){}
    Iter& begin(){return n;}
    Iter& end(){return i;}
};

//input
template<typename T1,typename T2> istream& operator >> (istream& is,pair<T1,T2>& p){return is>>p.first>>p.second;}
template<typename T1> istream& operator >> (istream& is,tuple<T1>& t){return is >> get<0>(t);}
template<typename T1,typename T2> istream& operator >> (istream& is,tuple<T1,T2>& t){return is >> get<0>(t) >> get<1>(t);}
template<typename T1,typename T2,typename T3> istream& operator >> (istream& is,tuple<T1,T2,T3>& t){return is >>get<0>(t)>>get<1>(t)>>get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> istream& operator >> (istream& is,tuple<T1,T2,T3,T4>& t){return is >> get<0>(t)>>get<1>(t)>>get<2>(t)>>get<3>(t);}
template<typename T> istream& operator >> (istream& is,vector<T>& as){for(int i:range(as.size()))is >>as[i];return is;}
//output
template<typename T> ostream& operator << (ostream& os, const set<T>& ss){for(auto a:ss){if(a!=ss.begin())os<<" "; os<<a;}return os;}
template<typename T1,typename T2> ostream& operator << (ostream& os, const pair<T1,T2>& p){return os<<p.first<<" "<<p.second;}
template<typename K,typename V> ostream& operator << (ostream& os, const map<K,V>& m){bool isF=true;for(auto& p:m){if(!isF)os<<endl;os<<p;isF=false;}return os;}
template<typename T1> ostream& operator << (ostream& os, const tuple<T1>& t){return os << get<0>(t);}
template<typename T1,typename T2> ostream& operator << (ostream& os, const tuple<T1,T2>& t){return os << get<0>(t)<<" "<<get<1>(t);}
template<typename T1,typename T2,typename T3> ostream& operator << (ostream& os, const tuple<T1,T2,T3>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t);}
template<typename T1,typename T2,typename T3,typename T4> ostream& operator << (ostream& os, const tuple<T1,T2,T3,T4>& t){return os << get<0>(t)<<" "<<get<1>(t)<<" "<<get<2>(t)<<" "<<get<3>(t);}
template<typename T> ostream& operator << (ostream& os, const vector<T>& as){for(int i:range(as.size())){if(i!=0)os<<" "; os<<as[i];}return os;}
template<typename T> ostream& operator << (ostream& os, const vector<vector<T>>& as){for(int i:range(as.size())){if(i!=0)os<<endl; os<<as[i];}return os;}

// values
template<typename T> inline T INF(){assert(false);};
template<> inline int INF<int>(){return 1<<28;};
template<> inline ll INF<ll>(){return 1LL<<58;};
template<> inline double INF<double>(){return 1e16;};
template<> inline long double INF<long double>(){return 1e16;};

template<class T> inline T EPS(){assert(false);};
template<> inline int EPS<int>(){return 1;};
template<> inline ll EPS<ll>(){return 1LL;};
template<> inline double EPS<double>(){return 1e-8;};
template<> inline long double EPS<long double>(){return 1e-8;};

// min{2^r | n < 2^r}
template<typename T> T upper_pow2(T n){ T res=1;while(res<n)res<<=1;return res;}
// max{d | 2^d  <= n}
template<typename T> T msb(T n){ int d=62;while((1LL<<d)>n)d--;return d;}

template<typename T,typename U> T pmod(T v,U M){return (v%M+M)%M;}

ll gcd_positive(ll a,ll b) { return b == 0 ? a : gcd_positive(b,a%b); }
ll gcd(ll a,ll b) { return gcd_positive(abs(a), abs(b)); }
ll lcm(ll a,ll b){return a/gcd(a,b)*b;}


template<class T> class Rational{
public:
    T u,d;
    Rational(T u,T d){
        T l =gcd(u,d);
        this->u = u/l;
        this->d = d/l;
    }

    static Rational<T> mv(Rational<T> r1,Rational<T> r2){
        T d = lcm(r1.d,r2.d);
        r1.u *= d/r1.d;r2.u *= d/r2.d;
        return {d,gcd(r1.u,r2.u)};
    }

    bool operator < (const Rational<T>& r) const{
        return (__int128)this->u * r.d < (__int128)this->d * r.u;
    }
    bool operator > (const Rational<T>& r) const{
        return (__int128)this->u * r.d > (__int128)this->d * r.u;
    }

};

class Main{
    public:

    void run(){
        vector<int> ts(3);cin >> ts;
        sort(ALL(ts));

        Rational<ll> mv = {INF<ll>(),1};

        Rational<ll> a01=Rational<ll>(ts[1]-ts[0],ts[0]*ts[1]);
        Rational<ll> b01=Rational<ll>(ts[1]+ts[0],ts[0]*ts[1]);

        Rational<ll> a12=Rational<ll>(ts[2]-ts[1],ts[1]*ts[2]);
        Rational<ll> b12=Rational<ll>(ts[2]+ts[1],ts[1]*ts[2]);

        mv=min(mv,Rational<ll>::mv(a01,a12));
        mv=min(mv,Rational<ll>::mv(a01,b12));
        mv=min(mv,Rational<ll>::mv(b01,a12));
        mv=min(mv,Rational<ll>::mv(b01,b12));

        cout << mv.u <<"/"<<mv.d <<endl;
    }
};

int main(){
    cout <<fixed<<setprecision(20);
    cin.tie(0);
    ios::sync_with_stdio(false);
    Main().run();
    return 0;
}
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