結果
| 問題 |
No.488 四角関係
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2019-04-08 11:28:07 |
| 言語 | Lua (LuaJit 2.1.1734355927) |
| 結果 |
AC
|
| 実行時間 | 167 ms / 5,000 ms |
| コード長 | 874 bytes |
| コンパイル時間 | 89 ms |
| コンパイル使用メモリ | 5,376 KB |
| 実行使用メモリ | 5,376 KB |
| 最終ジャッジ日時 | 2024-07-01 22:50:23 |
| 合計ジャッジ時間 | 1,409 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 22 |
ソースコード
tall = {}
function check(i1, i2, i3, i4)
if(tall[i1][i2] and tall[i1][i3] and tall[i2][i4] and tall[i3][i4] and (tall[i1][i4] == nil and tall[i2][i3] == nil)) then
return true
elseif(tall[i1][i3] and tall[i1][i4] and tall[i2][i3] and tall[i2][i4] and (tall[i1][i2] == nil and tall[i3][i4] == nil)) then
return true
elseif(tall[i1][i2] and tall[i1][i4] and tall[i2][i3] and tall[i3][i4] and (tall[i1][i3] == nil and tall[i2][i4] == nil)) then
return true
end
return false
end
n, m = io.read("*n", "*n")
for i = 1, n do
tall[i] = {}
end
for i = 1, m do
a, b = io.read("*n", "*n")
a, b = a + 1, b + 1
tall[a][b] = true
end
cnt = 0
for i_a = 1, n - 3 do
for i_b = i_a + 1, n - 2 do
for i_c = i_b + 1, n - 1 do
for i_d = i_c + 1, n do
if(check(i_a, i_b, i_c, i_d)) then cnt = cnt + 1 end
end
end
end
end
print(cnt)