結果

問題 No.488 四角関係
ユーザー 👑 obakyan
提出日時 2019-04-08 11:28:07
言語 Lua
(LuaJit 2.1.1734355927)
結果
AC  
実行時間 167 ms / 5,000 ms
コード長 874 bytes
コンパイル時間 89 ms
コンパイル使用メモリ 5,376 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-07-01 22:50:23
合計ジャッジ時間 1,409 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

tall = {}
function check(i1, i2, i3, i4)
if(tall[i1][i2] and tall[i1][i3] and tall[i2][i4] and tall[i3][i4] and (tall[i1][i4] == nil and tall[i2][i3] == nil)) then
return true
elseif(tall[i1][i3] and tall[i1][i4] and tall[i2][i3] and tall[i2][i4] and (tall[i1][i2] == nil and tall[i3][i4] == nil)) then
return true
elseif(tall[i1][i2] and tall[i1][i4] and tall[i2][i3] and tall[i3][i4] and (tall[i1][i3] == nil and tall[i2][i4] == nil)) then
return true
end
return false
end
n, m = io.read("*n", "*n")
for i = 1, n do
tall[i] = {}
end
for i = 1, m do
a, b = io.read("*n", "*n")
a, b = a + 1, b + 1
tall[a][b] = true
end
cnt = 0
for i_a = 1, n - 3 do
for i_b = i_a + 1, n - 2 do
for i_c = i_b + 1, n - 1 do
for i_d = i_c + 1, n do
if(check(i_a, i_b, i_c, i_d)) then cnt = cnt + 1 end
end
end
end
end
print(cnt)
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0