結果
問題 | No.492 IOI数列 |
ユーザー |
👑 |
提出日時 | 2019-04-08 16:16:03 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 2 ms / 1,000 ms |
コード長 | 1,927 bytes |
コンパイル時間 | 1,909 ms |
コンパイル使用メモリ | 166,424 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-06-13 04:55:26 |
合計ジャッジ時間 | 3,025 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 19 |
ソースコード
import std.conv, std.functional, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.complex, std.container, std.math, std.numeric, std.range, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken.to!int; }long readLong() { return readToken.to!long; }real readReal() { return readToken.to!real; }bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;(unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }enum BigInt MO1 = "1000000007";enum BigInt MO2 = "101010101010101010101";enum BigInt MO = MO1 * MO2;BigInt[][] mul(in BigInt[][] a, in BigInt[][] b) {auto c = new BigInt[][](2, 2);foreach (i; 0 .. 2) foreach (k; 0 .. 2) foreach (j; 0 .. 2) {c[i][j] += a[i][k] * b[k][j];c[i][j] %= MO;}return c;}void main() {try {for (; ; ) {const N = readLong();BigInt[][] x = [[BigInt(100), BigInt(1)], [BigInt(0), BigInt(1)]];BigInt[][] y = [[BigInt(1), BigInt(0)], [BigInt(0), BigInt(1)]];for (long e = N; e; e >>= 1) {if (e & 1) {y = mul(y, x);}x = mul(x, x);}const ans = y[0][1];writeln(ans % MO1);writeln(ans % MO2);}} catch (EOFException e) {}}