結果

問題 No.812 Change of Class
コンテスト
ユーザー hitonanode
提出日時 2019-04-14 08:27:05
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
MLE  
実行時間 -
コード長 4,068 bytes
コンパイル時間 1,759 ms
コンパイル使用メモリ 178,276 KB
実行使用メモリ 813,924 KB
最終ジャッジ日時 2024-06-12 20:42:18
合計ジャッジ時間 8,258 ms
ジャッジサーバーID
（参考情報） 		judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample -- * 3
other AC * 5 MLE * 1 -- * 54
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <bits/stdc++.h>
using namespace std;
using lint = long long int;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_;
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template<typename T> istream &operator>>(istream &is, vector<T> &vec){ for (auto &v : vec) is >> v; return is; }
template<typename T> ostream &operator<<(ostream &os, const vector<T> &vec){ os << "["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const deque<T> &vec){ os << "deq["; for (auto v : vec) os << v << ","; os << "]"; return os; }
template<typename T> ostream &operator<<(ostream &os, const set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_set<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec){ os << "{"; for (auto v : vec) os << v << ","; os << "}"; return os; }
template<typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa){ os << "(" << pa.first << "," << pa.second << ")"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename TK, typename TV> ostream &operator<<(ostream &os, const unordered_map<TK, TV> &mp){ os << "{"; for (auto v : mp) os << v.first << "=>" << v.second << ","; os << "}"; return os; }
template<typename T> void ndarray(vector<T> &vec, int len) { vec.resize(len); }
template<typename T, typename... Args> void ndarray(vector<T> &vec, int len, Args... args) { vec.resize(len); for (auto &v : vec) ndarray(v, args...); }
template<typename T> bool mmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template<typename T> bool mmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
template<typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template<typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
#define dbg(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ") " << __FILE__ << endl;
#define FI first
#define SE second
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) ((lint)(x).size())
#define POW2(n) (1LL << (n))

using Edges = vector<vector<int>>;

Edges e;

// rから各ノードへの距離
vector<int> tree_distance(int N, int r)
{
    vector<int> res(N); // res[r] = 0;
    queue<pint> q;
    q.push(pint(r, -1)); // (now, prev)
    while(!q.empty())
    {
        pint pa = q.front(); q.pop();
        if (pa.second >= 0) res[pa.first] = res[pa.second] + 1;
        for (auto nx : e[pa.first]) if (nx != pa.second) q.push(pint(nx, pa.first));
    }
    return res;
}

int main()
{
    int N, M;
    cin >> N >> M;
    REP(_, M)
    {
        e.resize(N + 1);
        int p, q;
        cin >> p >> q;
        e[p].push_back(q);
        e[q].push_back(p);
    }

    int Q;
    cin >> Q;
    REP(_, Q)
    {
        int A;
        cin >> A;
        vector<int> ds = tree_distance(N + 1, A);
        int maxi = *max_element(ALL(ds));
        maxi = max(maxi - 1, 0);
        int d = 0;
        REP(dd, 31) if (POW2(dd) & maxi) d = dd + 1;
        int n = 0;
        for (auto v : ds) n += (v > 0);
        cout << n << " " << d << endl;
    }
}
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